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# Maths year 11

1. (Original post by z_o_e)
Got it!! I got 71% on that work!!

Now this...

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Sorry I put my answers in terms of Pi because I'm lazy.

2. (Original post by z_o_e)
I got the top ones. I think they are right. What about these?

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Cross section of the first one is quarter of a circle.
For the second youre finding the volume of the solid outer bit of the pipe. So the cross sectional area you're concerned with will be the area of the larger circle - area of the smaller circle.
3. (Original post by 34908seikj)
Sorry I put my answers in terms of Pi because I'm lazy.

So it's Csa*L

These are tricker ones do I use same method :/

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4. (Original post by z_o_e)
So it's Csa*L

These are tricker ones do I use same method :/

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5. (Original post by 34908seikj)
I got them all wrong "(

The answer was 7.3
2) 2
3) 7.2

I think it's working out isn't right.

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6. (Original post by z_o_e)
I got them all wrong "(

The answer was 7.3
2) 2
3) 7.2

I think it's working out isn't right.

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Ugh, my answers are incorrect, are you sure?

I rounded to two 2dp, so my answers are correct for questions 1 and 3, lemme figure out where I went wrong on 2.
7. (Original post by 34908seikj)
Ugh, my answers are incorrect, are you sure?
According to the website.

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8. (Original post by z_o_e)
According to the website.

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ohhhh for question two, I didn't multiply by 1/2. Sorry, that's my fault.
9. (Original post by z_o_e)
I got them all wrong "(

The answer was 7.3
2) 2
3) 7.2

I think it's working out isn't right.

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You're supposed to do it to 1 decimal place.
10. (Original post by Ano123)
You're supposed to do it to 1 decimal place.
I did.

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11. Did you round it correctly?
12. (Original post by Ano123)
You're supposed to do it to 1 decimal place.
Heya. I'm going to start from today xx

I needed explanation on this question please.

I would like to workout the answers and stuff all by myself as I wouldn't learn if I got them x

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13. (Original post by 34908seikj)
Did you round it correctly?

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14. (Original post by z_o_e)
Heya. I'm going to start from today xx

I needed explanation on this question please.

I would like to workout the answers and stuff all by myself as I wouldn't learn if I got them x

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If you let the length BD be denoted , then using the triangle on the right hand side we get
.
15. If you let BCA be denoted , then . So you just solve for .
16. (Original post by B_9710)
If you let BCA be denoted , then . So you just solve for .
I did this

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17. (Original post by z_o_e)
I did this

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You're working out the wrong angle.
18. (Original post by z_o_e)
Heya. I'm going to start from today xx

I needed explanation on this question please.

I would like to workout the answers and stuff all by myself as I wouldn't learn if I got them x

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For part b

Use Sin to find BD, you can do this because you have the opposite side to an angle. - SOHCAHTOAH - Sin opp/hyp Cos adj/hyp Tan opp/adj

So set it up like this: 12.8/x = Sin(42)

Now try rearranging the formulae to make x the subject.

Long time no see Zoe, have you been revising
19. (Original post by B_9710)
You're working out the wrong angle.
Oh?
Is this fine?

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20. (Original post by z_o_e)
Oh?
Is this fine?

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That's right.

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