You are Here: Home >< Chat >< Chat

# 6th Years and Leavers :: Chat Thread #2 :: Revenge of the Ape watch

• View Poll Results: Choose one.
Coca Cola (Sweet & Sticky)
30.11%
Pepsi (Cool & Crisp)
36.56%
Sex.
33.33%

1. (Original post by ukdragon37)
That's why it's actually quite difficult - either the questions are designed to trip you up or send you down a very long maths rabbit hole.

E.g. Try 16 (*without* looking at the answer). How would you tackle it?
Q16 seems to be fairly straightforward, though I'm undoubtebly oversimplifying it.

x+y+z=750, so mean =250.
2. (Original post by Ape Gone Insane)
You got it too, don't sigh!

I'm truly honoured to be in your sig.
3. (Original post by Ape Gone Insane)
16. The numbers x, y and z satisfy the equations
x + y + 2z = 850, x + 2y + z = 950, 2x + y + z = 1200.
What is their mean?
A 250 B C 750 D 1000 E More information is needed.

It's finding mean, so I would treat the equations like I would numbers and add them all divide by the number.

x+x+2x, y+2y+y, 2z+z+z = 4x+4y+4z = 3000. Take out the common, "4"

= 4( x + y + z ) 3000. Bring the 4 over to divide giving me 750.

x + y + z = 750 and from there tbh, I would have ticked 750 even though the answer is 250 I would have forgot to divide by 3 since there are 3 equations.
(Original post by namedeprived)
Q16 seems to be fairly straightforward, though I'm undoubtebly oversimplifying it.

x+y+z=750, so mean =250.
Well done! Both of you used the "correct" and quick method.

I did the wrong way actually when I sat this paper - I used GE on the set of equations and found x, y and z then found the mean

Still got a gold in the end, but only just
4. (Original post by ukdragon37)
Well done! Both of you used the "correct" and quick method.

I did the wrong way actually when I sat this paper - I used GE on the set of equations and found x, y and z then found the mean

Still got a gold in the end, but only just
Normally I would do something like that, only reason I didn't is because I dislike Gaussian elimination so i looked harder for the 'trick'.

For the Junior and Intermediate challenges I only got Bronze. Shame I don't think we're doing it this year, think I could get at least silver.
5. (Original post by Ape Gone Insane)
That's what I initially thought then I went and remembered you only need GCSE/Standard Grade maths in order to sit the SMC.

Trying to trick me, damn you Maths!
Some people in my school (who were in the AH class incidentally) *actually* did Q1 by multiplying out 2008 twice

My favourite questions were 12, 13, 15 and 17
6. (Original post by TheUnbeliever)
No. All SQA markers are 73 y.o. eunuchs raised inside a veiled society that refuses to acknowledge the existence of the very students whose papers they mark. Few know of them, but those who do speak of them only in hushed tones. Their presence alone is enough to make the lights dim, the air hum, and conversation lull.
Who told you this? Have you been sneaking around the old barn out back? Dang, we'll have to move the Marking Centre again, that's the third time in 149 years. The eunuchs don't like change.

SAM

(If not all the markers are eunuchs, and not all the markers are 73yo, and none are both, and all are neither except maybe a few, what's the average sense per word of this message?)
7. (Original post by ukdragon37)
Some people in my school (who were in the AH class incidentally) *actually* did Q1 by multiplying out 2008 twice

My favourite questions were 12, 13, 15 and 17
Any hints for 13? I can only rule out A and E based on common sense. I suppose I could just number crunch but I don't really feel much like that.

Edit: Duh, I can't rule out A.
8. (Original post by namedeprived)
Any hints for 13? I can only rule out A and E based on common sense. I suppose I could just number crunch but I don't really feel much like that.
I'll just give you a little push in the right direction (how I did it anyway):
9. (Original post by Ape Gone Insane)
I'm having a go at them.

PS. Are you allowed a calculator in the challenge? EDIT: No, you're not.
9 was fun and so was 18. I got the right answer for 18 but I didn't think it was the easiest method.

10. (Original post by mysqa)
Who told you this? Have you been sneaking around the old barn out back? Dang, we'll have to move the Marking Centre again, that's the third time in 149 years. The eunuchs don't like change.

SAM

(If not all the markers are eunuchs, and not all the markers are 73yo, and none are both, and all are neither except maybe a few, what's the average sense per word of this message?)
Sam's back!
11. (Original post by ukdragon37)
I'll just give you a little push in the right direction (how I did it anyway):
Ah, ingenious!

12. (Original post by namedeprived)
Ah, ingenious!

Yep. The official answer required you to know that 1280 = 5 * 2^8, which at the heat of the moment in the exam is not exactly very reliable. I think my way's better
13. (Original post by ukdragon37)
Yep. The official answer required you to know that 1280 = 5 * 2^8, which at the heat of the moment in the exam is not exactly very reliable. I think my way's better
Definitley. Must admit that I'd never have worked that out.
14. (Original post by Ape Gone Insane)
9 and 18?

9. What is the remainder when the 2008-digit number 222 ... 22 is divided by 9?

God, I hope questions aren't like this.
Lol lol lol that was one of the easiest questions I thought I got it in 2 seconds whilst my classmates were doing hideous long divisions. Although I did have an extra bit of information that helped

(Original post by Ape Gone Insane)
25. What is the area of the polygon formed by all points in the plane satisfying
the inequality ?
(x, y)
||x| − 2| + ||y| − 2| ≤ 4
A 24 B 32 C 64 D 96 E 112
25 is the hardest question in the paper, so I'll leave you to it.

If you get almost all of the inner two pages right and 1 or 2 of the outer page then you'd get a gold - that's how I did last year.
15. (Original post by Ape Gone Insane)

You need to get 75 for a gold, 25 start off with. 50 marks/4 = 12.5 questions.

I need to get 13 questions (And allow for 2 mistakes) out of 25 right to get Gold if the boundaries for marks are roughly the same this year.
The remainder of a number divided by 9 is the same as the digital root of that number.

222..222 mod 9 = (2*2008) mod 9 = (4016) mod 9 = (4+6+1) mod 9 = 11 mod 9 = 2

Now this is a different way from the official answer but I say mine is better again, if you had the prior knowledge

EDIT: Wait, they are the same essentially.
16. (Original post by Ape Gone Insane)
That's awesome. Hidden methods FTW

Clever.

PS. Got a PM from SimonM
Ooooh

What's it about, if you are willing to share?
17. (Original post by Ape Gone Insane)
They are?

Yes, both solutions used the same number property so it's essentially the same.
18. (Original post by Ape Gone Insane)
Wow. So much respect, it's like talking to God.

Tips for tomorrow.
I would suggest you take them onboard. Like now. Or even write them down and bring them in with you.
19. (Original post by Ape Gone Insane)

What crazy calculations have you seen him do to warrant such followers?
Alas! I fear for your sanity if you glimpse at them

Let's just say about a year ago (when I was actually interested somewhat in the Maths board) uni students were actually asking *him* for help.

He's just extremely well-read in maths, which is why he's just so knowledgeable. Oh and I guess being a genius does help.

Again
20. (Original post by Ape Gone Insane)

What crazy calculations have you seen him do to warrant such followers?
Mind passing them on to me?

(Just in case we are doing it, and partly because I'm interested)

TSR Support Team

We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

This forum is supported by:
Updated: December 20, 2009
Today on TSR

### Cambridge interviews

Find out who is getting invitations

### Being bullied can cause mental health issues

Poll
Useful resources

Got a question about the site content or our moderation? Ask here.

### Welcome Lounge

We're a friendly bunch. Post here if you're new to TSR.

## Groups associated with this forum:

View associated groups

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE