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    (Original post by Sophsha)
    Lolololol
    Lol

    more pity
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    (Original post by plusC)
    Hey!, thank you

    That I am, if you ever need help with an indefinite integral I'm your guy
    Or wolfram alpha :ahee:

    How's it going?

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    (Original post by Mubariz)
    Or wolfram alpha :ahee:

    How's it going?

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    :laugh:

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    (Original post by Mubariz)
    Or wolfram alpha :ahee:

    How's it going?

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    True, my rival

    It's going good, watching netflix, smashing out integrals and playing ps2, that's what you call a relaxing summer.

    How about urs?
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    (Original post by plusC)
    Hey!, thank you

    That I am, if you ever need help with an indefinite integral I'm your guy
    I need help

    By decomposing  \dfrac{y^2 + 2y + 1}{y^4 + 2y^2 + 1} into partial fractions, find

     \displaystyle \int \dfrac{y^2 + 2y + 1}{y^4 + 2y^2 + 1} \text{d}y.

    Have fun

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    (Original post by Arieisit)
    I need help

    By decomposing  \dfrac{y^2 + 2y + 1}{y^4 + 2y^2 + 1} into partial fractions, find

     \displaystyle \int \dfrac{y^2 + 2y + 1}{y^4 + 2y^2 + 1} \text{d}y.

    Have fun

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    Looks like fun! I'll give it a go
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    (Original post by plusC)
    Looks like fun! I'll give it a go


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    Wazza Aaron

    (Original post by plusC)
    True, my rival

    It's going good, watching netflix, smashing out integrals and playing ps2, that's what you call a relaxing summer.

    How about urs?
    Ps2? Hitting them vintage games yeah?

    Yeah, downloading movies, trying to think of a research project, playing Xbox and waiting for my university taster weeks :ahee:

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    (Original post by Mubariz)
    Wazza Aaron



    Ps2? Hitting them vintage games yeah?

    Yeah, downloading movies, trying to think of a research project, playing Xbox and waiting for my university taster weeks :ahee:

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    Do you say wazza in real life? :lol:

    Anyway, I'll be off in a bit. Got a few things to do.

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    \dfrac{y^{2}+2y+1}{y^{4}+2y^{2}+  1}=\dfrac{y^{2}+1}{(y^{2}+1)^{2}  }+\dfrac{2y}{(y^{2}+1)^{2}}

    \displaystyle \int \dfrac{y^{2}+2y+1}{y^{4}+2y^{2}+  1}=\arctan(y)-\dfrac{1}{y^{2}+1}+C

    probably not following instructions , but this is the answer as far as I'm concerned
    (Original post by Mubariz)
    Wazza Aaron



    Ps2? Hitting them vintage games yeah?

    Yeah, downloading movies, trying to think of a research project, playing Xbox and waiting for my university taster weeks :ahee:

    Posted from TSR Mobile
    Yeah precisely, got pretty addicted to the japanese version of kingdom hearts 2, been playing it non stop really haha

    This is the life :lol:
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    (Original post by plusC)
    \dfrac{y^{2}+2y+1}{y^{4}+2y^{2}+  1}=\dfrac{y^{2}+1}{(y^{2}+1)^{2}  }+\dfrac{2y}{(y^{2}+1)^{2}}

    \displaystyle \int \dfrac{y^{2}+2y+1}{y^{4}+2y^{2}+  1}=\arctan(y)-\dfrac{1}{y^{2}+1}+C

    probably not following instructions , but this is the answer as far as I'm concerned

    Yeah precisely, got pretty addicted to the japanese version of kingdom hearts 2, been playing it non stop really haha

    This is the life :lol:
    No, it's wrong. :no: Sorry

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    I wish I could join in the maths discussion but I didn't do further maths :cry:

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    (Original post by Arieisit)
    No, it's wrong. :no: Sorry

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    Is the actual answer correct though? Its just I definitely know those aren't partial fractions, but why would you when you have this neat little trick
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    (Original post by Arieisit)
    Do you say wazza in real life? :lol:

    Anyway, I'll be off in a bit. Got a few things to do.

    Posted from TSR Mobile
    Sometimes yeah.

    My friends use it more than me, I rarely use it in real life tbf.

    Later :wavey:

    (Original post by plusC)
    \dfrac{y^{2}+2y+1}{y^{4}+2y^{2}+  1}=\dfrac{y^{2}+1}{(y^{2}+1)^{2}  }+\dfrac{2y}{(y^{2}+1)^{2}}

    \displaystyle \int \dfrac{y^{2}+2y+1}{y^{4}+2y^{2}+  1}=\arctan(y)-\dfrac{1}{y^{2}+1}+C

    probably not following instructions , but this is the answer as far as I'm concerned

    Yeah precisely, got pretty addicted to the japanese version of kingdom hearts 2, been playing it non stop really haha

    This is the life :lol:
    Na, I prefer new games, I don't like vintage games.

    Meh, each to their own

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    (Original post by Eva.Gregoria)
    I wish I could join in the maths discussion but I didn't do further maths :cry:

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    :console:, can always self teach it
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    (Original post by Eva.Gregoria)
    I wish I could join in the maths discussion but I didn't do further maths :cry:

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    I haven't done it either.

    Yet

    (Original post by plusC)
    :console:, can always self teach it
    May aswell run at a brick wall

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    (Original post by plusC)
    Is the actual answer correct though? Its just I definitely know those aren't partial fractions, but why would you when you have this neat little trick
    It is partial fractions, you have to "spot the trick"

    Your answer is correct but you could've easily put it into wolfarm

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    (Original post by Eva.Gregoria)
    I wish I could join in the maths discussion but I didn't do further maths :cry:

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    I haven't done FM either :laugh:

    (Original post by Mubariz)
    I haven't done it either.

    Yet



    May aswell run at a brick wall

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    Thought you told me you did FM in PM? :confused:

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    (Original post by plusC)
    :console:, can always self teach it
    Haha I tried at the beginning of my gap year like :lol: I actually almost completed complex numbers too but I just couldn't be bothered to continue without the threat of failing exams or teachers to motivate me

    (Original post by Mubariz)
    I haven't done it either.

    Yet



    May aswell run at a brick wall

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    It's not that difficult imo, if you're good at maths, getting A or A*, the jump shouldn't be too difficult lol.

    (Original post by Arieisit)
    I haven't done FM either :laugh:
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    So then what was that beastly looking equation you posted?

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    (Original post by Arieisit)
    It is partial fractions, you have to "spot the trick"

    Your answer is correct but you could've easily put it into wolfarm

    Posted from TSR Mobile
    Might as well do that, I'm not familiar with integration with complex conjugate roots on the denominator
 
 
 
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