# Edexcel A2 C3 Mathematics 12th June 2015Watch

This discussion is closed.
3 years ago
#3061
(Original post by Emmi12345)
Attachment 426305

There you go. Die no more.
thanks
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3 years ago
#3062
(Original post by Bealzibub)
Yeh .. i messed up on it too.

It was 5 marks aswell.

Then my mind went blank on part b of that question and there goes 9 marks.

Rest was pretty good though. Porbably lost 12-13 marks
He didn't 'mess up' on it... He's a Maths teacher (I think?). He just didn't sit the paper so he wants to see this trig identity to see why everyone found it so hard
Don't worry about it though, I think quite a few people didn't get it...
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3 years ago
#3063
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3 years ago
#3064
C3 was difficult
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3 years ago
#3065
(Original post by TeeEm)
I am dying to see this trig identity ...
Trig identity: how i did it...
split thing into 1/cos2x + sin2x/cos2x
then make common denominator of cos2x so it is (1+sin2x)/cos2x
then expand the double angle formulae so (1+2sinxcosx)/(cosx)^2 -(sinx)^2
then factorise denominator (diff of 2 squares) so
(1+2sinxcosx)/(cosx + sinx)(cosx - sinx)
using identity (sinx)^2 + (cos)^2 =1, sub in the sin and cos parts so you get
((sinx)^2 +(cosx)^2) +2sinxcosx)) / (cosx + sinx)(cosx - sinx)
the numerator can be factorised to (cosx+sinx)(cosx +sinx),
so now u have (cosx+sinx)(cosx +sinx) / (cosx + sinx)(cosx - sinx)
and then one of the (cosx + sinx) brackets cancel with the one on the bottom leaving u with (cosx + sinx) / (cosx -sinx)
sorry for it being hard to read...
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3 years ago
#3066
the equation of the asymptote for the first graph was y=-5, was there an asymptote for the second graph? If so what was the equation.
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3 years ago
#3067
(Original post by thatNoseyParker)
Just another copycat troll, sad really..
suck out they aren't trolling they are just smarter than you....
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3 years ago
#3068
Theres a C3 difficulty poll on this link btw

http://www.thestudentroom.co.uk/show...light=core%203
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3 years ago
#3069
(Original post by Johann von Gauss)
Prove: sec 2x + tan 2x = (cos x + sin x) / (cos x - sin x)
Spoiler:
Show
LHS = 1/cos 2x + 2tanx/(1-tan^2 x)
= 1 / (cos^2 x - sin^2 x) + 2sinxcosx / (cos^2 x - sin^2 x)
= (1 + 2sinxcosx) / (sin^2 x + cos^2 x)
= (sin^2 x + 2sinxcosx + cos^2 x) / (cos^2 x - sin^2 x)
= (sin x + cos x)^2 / (cos^2 x - sin^2 x)
= (cos x + sin x) / (cos x - sin x)

QED
thanks
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3 years ago
#3070
(Original post by hanif ahmed)
there was 10...on the last page after the division question
*sarcasm*
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3 years ago
#3071
(Original post by ColeNate)
9 for regular C3. Last question involved fractions, quadratics and k.
****
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3 years ago
#3072
(Original post by PaulCJH)
1. 2p/(1-p^2), 1/((p^2+1)^1/2), (1+p)/(p-1)
2. x> or equal to ln5/2, Solutions: ln3/2, ln7/2.
3. 26.57, 2 root 5, 51.8 and -25.3, k<2 root 5 and k>2 root 5
4. 20, ln2/40, 93
5. 4pi^2, 1/3pi
7. -4e^-4<g(x)<1/(8e)
8. 2.820, 5.962,
9. increasing, -3k/(x-2k)^2

Some might be wrong please bear that in mind.
For question 3, you're meant to put k>2root5 and k<-2root5 right?
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3 years ago
#3073
Guys, can i see a method for 5 b) please? The tangent to the curve question! Much appreciated.
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3 years ago
#3074
How did you find this paper? Vote Nowhttp://strawpoll.me/4609429/r
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3 years ago
#3075
(Original post by candol)
Didn't do paper, but if i understood question correct you need to multiply top and bottom by cosx + sinx . Then simplify and use double angle formula to get sin2x/cos2x = 1/2 which is tan2x=1/2 etc
Hi, I also had a brain freeze but I got it as 3cosx +sinx and put it in Rcos(x+a) form- I know I got thr right answers but will I still get the marks for not using tan?
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3 years ago
#3076
How many marks for 96UMS roughly?
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3 years ago
#3077
Me too 😭
Nearly cried when i found out
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3 years ago
#3078
(Original post by dominicwild)
How did you get it to be increasing?

K was negative and it was divided by the square of some function of x. Meaning the gradient at any point could only be negative. As it's always going to be negative/positive = negative. Meaning it's a decreasing function?
The number kept on getting smaller, and it was a negative, so a negative number getting smaller means that its an increasing function, because the value of it is actually increasing.
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3 years ago
#3079
(Original post by Bustamove)
I have nothing against people saying that they did well, but making fun of others not doing as well as you is not something that I agree with...
Oh yeah I agree we shouldn't belittle people who did hard, that's a general rule. I personally haven't belittled people who found it hard, I was just trying to put a neutral perspective on things.
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3 years ago
#3080
The y=2e^x-5 graph question, was it assymptote at y=-5 and (0,-3) and then part b, y=5 and (3,0) ??? And then they intersect at ln(5/2)
and last part - two solutions - x=ln(7/2) and ln(3/2)
??????????????????????????!!!!!!
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