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    (Original post by Jm098)
    I didn't square root my initial speed on question one ffs, do they ECF?
    Yeah physics is quite nice with ecf
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    (Original post by screwedmofo)
    how though?
    sorry the V is 5.78 velocity at D is 3.45 something. Height for second bounce is 0.6m
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    130.8 for shc anyone?
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    (Original post by Danny_L)
    For S2 mass, I used keplers third law and rearranged.
    M = (4pisquared x (3.6*10^12)^3)/(G x (86400x365x4)^2)
    =1.73*10^33
    Yeah I got a very similar value. 1.03x10^33, but I combined the two equations from previous questions. I think both ways work too.
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    (Original post by UnknownAnon)
    I definitely agree. I really liked last years paper. Plus this year had no long questions which I usually prefer. I've given up hope on this. Just hope G485 is amazing.
    The really easy stuff, the gravitational force questions, were the one thing they decided to **** up and make into a symbols only mess.
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    (Original post by Danny_L)
    130.8 for shc anyone?
    Yep got the same answer
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    (Original post by Asiimov)
    I thought max KE was 80mJ?
    me too, no idea where they got 50 from.
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    I struggled for so long on the very first question trying to understand the graph I rushed everything else. Can someone explain how you get the energy to use to find c in the pellets question?
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    (Original post by yuweizheng)
    Q1:velocity is 5.38. D is 3.45. Height is 0.6m
    broo i got that please tell me its right
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    (Original post by Danny_L)
    130.8 for shc anyone?
    Yeah.
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    (Original post by Asiimov)
    I thought max KE was 80mJ?
    That's what I used, but no, because there was residual epe, it was epe max - epe min = ke max
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    (Original post by Danny_L)
    130.8 for shc anyone?
    Yep! Didn't seems right for Lead but oh well. Lots of people got it.
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    (Original post by madberry1)
    I got 969 too for the fireman question
    That's what I got as well
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    For the assumptions for the lead, I said no loss to surrounding environment jadada. Then said that all gpe is converted to ke and not transferred into other forms or used to deform the pellets, then crossed it out and wrote that all pellets fall 1.2 m. Regretting crossing it out now, what do you think?
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    (Original post by yuweizheng)
    sorry the V is 5.78 velocity at D is 3.45 something. Height for second bounce is 0.6m
    How did you work out D?
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    (Original post by steph-carys)
    Damn, I botched up my graph then. Hopefully there will be full ecf for following calculations..
    There should be full ecf
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    (Original post by screwedmofo)
    me too, no idea where they got 50 from.
    Max KE is 50 Because the graph started at 30 mj so 80-30=50
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    (Original post by screwedmofo)
    me too, no idea where they got 50 from.
    I got 50 because max PE was 80 and min PE was 30.

    Why did you get 80?
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    (Original post by tobybes)
    Yeah I got a very similar value. 1.03x10^33, but I combined the two equations from previous questions. I think both ways work too.
    I got power of 41.
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    For the assumption I said that to assume there is little time between inversions on the tube
 
 
 
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