Hey there! Sign in to join this conversationNew here? Join for free
    Offline

    0
    ReputationRep:
    (Original post by Door105)
    GUYS WHAT DO YOU THINK THE GRADE BOUNDARIES WILL BE I REALLY WANT AN A BUT I THINK I GOT AROUND 120-130 OUT OF 200?!?!?! IS it possible?
    calm down mate. you need like 140-150 for an A. and about 160-170 for an A*
    Offline

    11
    ReputationRep:
    (Original post by Rajive)
    I got 40.0?
    same
    Offline

    3
    ReputationRep:
    (Original post by yoyojames1234567)
    did u guys get 84638 bars ?
    that's a very scary answer
    Offline

    0
    ReputationRep:
    3:9.25
    4:18 Chips /Small
    5:0.09 0.36
    7:3:2
    9:124
    Offline

    0
    ReputationRep:
    Ya dads balls these all wrong like your birth want me to hit you for a 6'er?
    Offline

    0
    ReputationRep:
    Can someone do what they done last time by actually doing the paper ?? 🙂
    Offline

    12
    ReputationRep:
    (Original post by Anonymous20000)
    Woouldnt 23 be 3x+4 because you cancel 3-x and x-3 out??
    That's not possible as 3-x and x-3 are completely different numbers . It was a trick question
    Offline

    2
    ReputationRep:
    Perimeter x = 9.25
    Counters = 0.09 and 0.36
    Trail and Improvement = 3.7
    Parallel Lines = 124 (might have been 126 i can’t remember)
    Polygons = 144
    DMV = 3
    Compound Depreciation = no, care is worth £7766 or something
    Pythagoras and Trig = 30.1
    Stratified Sample = 11
    Quadratic = 0.29 or -2.29
    Bounds = 29.something
    Sectors = 28.9 (around that)
    Last one = 80.4
    Offline

    0
    ReputationRep:
    (Original post by nasm)
    I got 80.4 for the last question too!
    thats cos its right
    Offline

    1
    ReputationRep:
    i put 3 ?
    Offline

    0
    ReputationRep:
    (Original post by rayestar)
    that's a very scary answer
    you have a very scary face
    Offline

    1
    ReputationRep:
    me and a teacher just did the question, it was sine rule. SINX / 15.6 = SIN 90 /18. then change the formula to work out x and times by sin-1. This gave you the whole angle. remember it was two triangles in one- so you had to take away 30. The answer was in fact 30.1 to the nearest decimal.

    or was this the first triangle question
    Offline

    15
    ReputationRep:
    ALL THE ANSWERS pic.twitter.com/tE46Iq7rCw
    Offline

    0
    ReputationRep:
    That was the first step
    Offline

    0
    ReputationRep:
    (Original post by CaSweeney)
    I did, did you get 80.4 degrees for the last one?
    Yes i got 80.4 for the last answer i used area of non right angle triangle, cosine rule for angle and length..
    Offline

    3
    ReputationRep:
    (Original post by Door105)
    GUYS WHAT DO YOU THINK THE GRADE BOUNDARIES WILL BE I REALLY WANT AN A BUT I THINK I GOT AROUND 120-130 OUT OF 200?!?!?! IS it possible?
    An A is probably about 130-135
    Offline

    2
    ReputationRep:
    (Original post by GFH_Ginger)
    calm down mate. you need like 140-150 for an A. and about 160-170 for an A*
    Lol. He said he got max 130 and you're telling him the grade boundary for an A will be 140 ? How are you making him calm down ?


    ⚔🛡⚔~Nothing happens to anyone that he is not fitted by nature to bear - Maximus Decimus Meridius~⚔🛡⚔
    Offline

    2
    ReputationRep:
    I got 80.3 for the last one is this wrong?
    Offline

    3
    ReputationRep:
    The last question was 100% 80.4 degrees. You had to re-arrange half absinC to get 18cm2 divided by half x 7 x 8. With the number you get, use inverse sine. This gives you the angle between the 2 lengths. As you have an angle between 2 lengths, you can use cosine rule to find the final length. The length squared = 7^2 + 8^2 - 2 x 7 x 8 x cos (the angle got from before). Square root this answer to give you the final length of the triangle. Once you have all 3 lengths, you can then re-arrange the cosine rule to find the final angle (not given on the formula sheet). Do 7^2 + (length acquired just now)^2 - 8^2 divided by 2 x 7 x (length acquired just now) gives you cos of the angle they asked you to find. Do inverse cos on this number and you get 80.4 which looked very similar to the angle given. Who else did this for the last question?
    Offline

    1
    ReputationRep:
    (Original post by angelax)
    I got 3.7 too but it seems more people got 3.8 :/
    I got 3.7

    The question asked you to work out the closest value that 'x' could be (to1 decimal place) if ("x cubed") - (5 multiplied by 'x') = 34

    If you sub 3.7 into that equation you will get an answer of 32.153
    If you sub 3.8 into that equation you will get an answer of 35.872

    To then work out which is closest you had to work out the difference between each answer and 34.

    For 3.7:
    34 - 32.153 = 1.847

    For 3.8:
    35.872 - 34 = 1.872

    Seeing as 1.847 is a smaller number than 1.872, it means that 3.7 is the closest value of 'x' to 1 decimal place
 
 
 
  • See more of what you like on The Student Room

    You can personalise what you see on TSR. Tell us a little about yourself to get started.

  • Poll
    Would you rather give up salt or pepper?
  • See more of what you like on The Student Room

    You can personalise what you see on TSR. Tell us a little about yourself to get started.

  • The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

    Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

    Write a reply...
    Reply
    Hide
    Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.