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    (Original post by Rager6amer)
    I am pretty sure they will have an 'OE' in the mark scheme meaning it can be in any simplified form like your form. You should have nothing to worry about so good luck with core 2
    Thank you so much, good luck to you too!
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    (Original post by Rager6amer)
    Do you mean as in get the answer to the question?
    Just how you go by doing questions similar to that really
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    (Original post by Rager6amer)
    I dont know if anyone is interested but I made a more updated mark scheme that includes all of the actual questions, the step-by-step answers and where marks are allocated as well as a grade boundary guide. Let me know what people think
    Pure genius. That's all i can say right now
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    (Original post by chocolatecocoyum)
    Pure genius. That's all i can say right now
    who you are? Did you get 'em all right or something?
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    Btw guys i know its late but if you need revision advice i found a channel on YouTube which is quite helpful, he's called Ryhan Hussain https://www.youtube.com/channel/UCg2...S5iIu74rRO5x1w
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    Btw people i know its late but if you need revision advice i found a channel on YouTube which is quite helpful, he's called Ryhan Hussain https://www.youtube.com/channel/UCg2...S5iIu74rRO5x1w
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    x^+y^-10x+6y=K Was the question right

    (x-5)^-25+(y+3)^-9=k

    (x-5)^+(y+3)^= 25+9 right?

    So Isn't the answer 34... Correct me If I'm wrong
    • Thread Starter
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    (Original post by medicine71012)
    x^+y^-10x+6y=K Was the question right

    (x-5)^-25+(y+3)^-9=k

    (x-5)^+(y+3)^= 25+9 right?

    So Isn't the answer 34... Correct me If I'm wrong
    no you cant do that because you cannot complete the square if they already gave you the co ordinates so 34 is wrong
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    (Original post by beanigger)
    no you cant do that because you cannot complete the square if they already gave you the co ordinates so 34 is wrong
    What were the coordinates?
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    (Original post by Rager6amer)
    I dont know if anyone is interested but I made a more updated mark scheme that includes all of the actual questions, the step-by-step answers and where marks are allocated as well as a grade boundary guide. Let me know what people think
    Thanks man this 100% bag on.
    Have you got something like this for C2?
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    (Original post by Umaster54)
    Thanks man this 100% bag on.
    Have you got something like this for C2?
    Hoping it will be done by tomorrow my friend
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    In question 7 a) I did differentiation but didn't differentiated 4. so the equation came out wrong then I got wrong answers for b) and d). But the steps are all correct. How many marks will I get if it is 5marks, 1mark and 5marks?
    • Welcome Squad
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    Welcome Squad
    (Original post by beanigger)
    Unoffical Mark scheme for C1 AQA 2016

    It would help if you could link answers to questions as i cant remember them

    Questions:

    1) a)Asked to work out gradient of a tangent, m= - 5/3 [2]
    b)Asked to find co-ordinates of B B( - 3,4) [3]
    c)Asked to find K K= - 30 [2]

    2) a) simplify (3√5)^2 = 45 [1]
    b) i cant remember the question but the answer was75 - 32√5 [4]

    3) a) y=(x-7/2)^2 - 41/4 [2]
    b) min value = -41/4 [1]
    c) Translation of (1/2 , 41/4) [3]

    4) a) show that (x+3) was a factor of x^3 - 5x^2 -8x + 48, p(-3) = 0, (x+3) is a factor of p(x). [2]
    b) three linear factors of p(x) = (x+3)(x-4)(x-4) [3]
    c) find remainder when p(x) was divided by (x+2) R=20 [2]
    d) Factorise p(x) using (x+2) R = (x-2)(x^2-3x-14) + 20 [3]

    5) a) asked to find equation of circle (x-5)^2+(y+3)^2=65 (note 65 = r^2) [3]
    b) asked to find co-ordinates of B (AB is diameter) B ( 12, -7) [2]
    c) asked to find equation of tangent at A 7x-4y+18=0 [5]
    d) asked to find length of CT = 9 [3]

    6) a) x = -1±√5 [2]
    b) upside down positive graph passing through y axis at 8 [2]
    b) Q(-5/4) [1]
    d) y=-32x-40

    7) a)
    b)
    c) definite integral = = 81 /4 [5]
    d) area of shaded region = = 45/4 [3]


    8) a) d^2y/dx^2= - 2x - 9x^2 [2]
    b) verify that P was a minimum point sub x co-ordinate of P into dy/dx (given in the question) to prove it was a stationary point, then sub in x-coord of p into d^2y/dx^2 to get +45, d^2y/dx^2>0 therefore minimum point [4]
    c)show that y is decreasing, so make your dy/dx<0 and rearrange to get into the form they wanted (note when you multiply by -1 the inequality sign flips)
    d) cant remember anything except the answers were k>6 and k<-3/2

    Answers that need a question to be assigned to
    - k=4 and k=20
    sorted out some marks
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    (Original post by JasmineXu)
    Hi all, do you have the 2016 Core 1 paper ?
    What's the point of cheating for your mocks? They're there for you to revise properly and see how you would do if you took the exam now, so that you can improve. Go revise.
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    **** u
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    (Original post by alvinbenny)
    **** u
    You naughty little gremlin
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    (Original post by saaidq)
    It should be 34right?
    Thats what Igot when I completed the square after sub. the coordinates C and A,
    But it seems that when I implanted the C and A into the distance formula, the distance between C and A is the radius, i got 65 so this question really needs clear justification
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    2017 was harder
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    (Original post by saaidq)
    It should be 34right?
    Wrong
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    (Original post by Rit101)
    Does anyone remember the questions and the equations given???
    No
 
 
 
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