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Maths year 11 Watch

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    (Original post by 34908seikj)
    Use pythagorus

     \sqrt{x^2 + (2x)^2} = 25


     \sqrt{x^2 + 4x^2} = 25
    On my phone ( came out in latex

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    (Original post by z_o_e)
    On my phone ( came out in latex

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    Sorry Will fix it now.
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    (Original post by 34908seikj)
    Use pythagorus
    *Pythagoras.
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    (Original post by 34908seikj)
    Sorry Will fix it now.
    I did this now as well

    I think it's right.



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    (Original post by B_9710)
    *Pythagoras.
    Sorry babe

    (Original post by z_o_e)
    On my phone ( came out in latex

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    Try and finish it from here
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    (Original post by z_o_e)
    A bit stuck.


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    a=x, b=2x. Just plug this in and find c.
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    (Original post by z_o_e)
    I did this now as well

    I think it's right.



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    I got 8.5, but what you did was right.
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    (Original post by 34908seikj)
    I got 8.5, but what you did was right.
    I just don't get this!
    Never did this before.



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    (Original post by 34908seikj)
    I got 8.5, but what you did was right.
    Got this!!



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    (Original post by z_o_e)
    I just don't get this!
    Never did this before.



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    Okay, split it up.


    You have √5 * √x^2 = 25

    The √x^2 cancel out which leaves you with x

    Now you have x√5 = 25

    Divide by √5 and rationalise the denominator


    So it will be x = 25/√5 -----> x = 25√5/5

    Which leaves you with x = 5√5
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    (Original post by z_o_e)
    Got this!!



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    You would still have x√5 not 5x since you can rewrite it as √5 * √x^2 = 25


    Now the square cancels out the square root so you are left with √5 * x = 25


    Which is the same as x√5 = 25
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    (Original post by 34908seikj)
    I got 8.5, but what you did was right.
    My answer from yesterday gives 8.56...
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    (Original post by B_9710)
    My answer from yesterday gives 8.56...
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    Then I rounded incorrectly
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    (Original post by 34908seikj)
    You would still have x√5 not 5x since you can rewrite it as √5 * √x^2 = 25


    Now the square cancels out the square root so you are left with √5 * x = 25


    Which is the same as x√5 = 25
    Can you do this question from scratch please feel so bad asking you again.

    But I don't understand the last square root stuff.

    Then I'll do a similar question to this "

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    (Original post by z_o_e)
    Can you do this question from scratch please feel so bad asking you again.

    But I don't understand the last square root stuff.

    Then I'll do a similar question to this "

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     x^2 + (2x)^2 = 25^2 .
     5x^2= 25^2 so
     x^2=125 so  x= \sqrt{125}= 5\sqrt 5 \text{cm} .
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    (Original post by z_o_e)
    Can you do this question from scratch please feel so bad asking you again.

    But I don't understand the last square root stuff.

    Then I'll do a similar question to this "

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    (Original post by 34908seikj)
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    Too hard (
    I think I should leave this question.

    I don't understand surds and squares maybe I need to learn them in order to understand this?
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    (Original post by z_o_e)
    Too hard (
    I think I should leave this question.

    I don't understand surds and squares maybe I need to learn them in order to understand this?
    Yes. Surds are super simple once you get the hang of them.
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    (Original post by 34908seikj)
    Yes. Surds are super simple once you get the hang of them.
    I need an introduction haha I know a bit of this
    :awesome:
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    (Original post by z_o_e)
    I need an introduction haha I know a bit of this
    :awesome:
    There are very simple rules you need to follow to answer all of these questions.
     \sqrt a \times \sqrt b = \sqrt{ab} and also
     \displaystyle \frac{\sqrt a}{\sqrt b }= \sqrt{\frac{a}{b}} .
 
 
 
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