Edexcel Maths Higher Calculator Paper - How was it?

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    Yeah I hope you guys are right about the boundaries there. The thing is, Edexcel changed the format of the question quantity this year with there being a total of 52 questions instead of the usual 40 combined as in past years.

    170 sounds a lot more reasonable than 180, I just hope your guys are right about that.
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    few questions really...
    a) the question about the plane doin 1400km was it 2.2h or 2h 20mins
    b) i put 133.33% for the population increase - how many marks will i get with method
    c) i did the quad correct to the x^2-10x+9 or w.e then tried the quad form, got wrong answer - how many should i get?
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    What about an A?
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    June 2006 an A was 116/200



    so this year im guessing

    130/200 for an A
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    Oh dear some people hey!

    I totally agree with you

    45million X = 60 million

    100((60/45)-1)=33.3
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    I think it was 118/200 for an A in 2006.
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    HERE IS THE SOLUTION FOR THE QUADRATIC ALGEBRARIC FRACTION WITH EXPLANATION.
    |
    |
    -\==/
    --\=/
    ---\/

    Attached Images
     
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    I kicked myself so hard at the end of that exam, I didn't realise that question was a quadratic >.< Major blunder.
    Still put lots and lots and lots of working out Maybe I can scrape a few marks from that.
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    (Original post by Potent)
    I think it was 118/200 for an A in 2006.

    nope 116 check the examiners report

    http://www.edexcel.org.uk/VirtualCon...p_20060817.pdf

    Page 54
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    Hey theolympic

    Tanks for that explonation but wont the answer from the factorised part be
    +1 and -9 because if one set of brackets equal 0 then the other has got to so if it +9 X=-9

    Am i right.

    Thanx for explaining though! I got it wrong
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    To be honest i don't think the grade boundries are going to be that high at all. Everyone in here may well think the papers were easy, but people who can be arsed to go to the trouble of discussing an exam over the internet are likely to be quite commited studets. Also, all the GCSE maths papers are "easy" and have low grade boundaries and it will be the same this year!
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    right, someone please explain why it was 33.3% please. %change = change/original x 100. so... 6.0x10^7 - 4.5x10^7 = 1.5x10^7
    1.5x10^7 / 6.0x10^7 = 0.25 x 100 = 25%
    how are you getting 33.3%
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    My german teacher said that the average grade for any subject for an average british person is a....D:eek: :eek: :eek: !!!!!!

    That makes people on TSR...the geniuses of the nation ! Welcome fellow geniuses!

    K xxxx
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    ah muff! iv'e just realised where i went wrong in the standard form question :'( thats a lot of marks ive lost now. not sure i'll be getting an A*
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    (Original post by andy7257)
    To be honest i don't think the grade boundries are going to be that high at all. Everyone in here may well think the papers were easy, but people who can be arsed to go to the trouble of discussing an exam over the internet are likely to be quite commited studets. Also, all the GCSE maths papers are "easy" and have low grade boundaries and it will be the same this year!
    Yeah I tend to agree that we do overlook the ability of the entire country and base certain standards to reflect the performance of candidates that solely post on TSR. I just hope the grade boundaries aren't set too high to restrict those who admittedly lost marks due to silly mistakes - like the % increase on that standard form question for me! I can't believe I got 25% and didn't take the change from 45,000,000 instead of 60,000,000 citizens! That was a two marker...right...guys...stay with me...stay with me...please?
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    (Original post by odeargodishouldrevise)
    right, someone please explain why it was 33.3% please. %change = change/original x 100. so... 6.0x10^7 - 4.5x10^7 = 1.5x10^7
    1.5x10^7 / 6.0x10^7 = 0.25 x 100 = 25%
    how are you getting 33.3%
    you divide it by the original in 1933 or waterver


    so 1.5*10^7/4.5*10^7 * 100
    = 33.33333333333
    =33.3% to 1 DP
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    (Original post by Jsk)
    Hey theolympic

    Tanks for that explonation but wont the answer from the factorised part be
    +1 and -9 because if one set of brackets equal 0 then the other has got to so if it +9 X=-9

    Am i right.

    Thanx for explaining though! I got it wrong

    ye u are right. this person has factorised wrongly, it shud b (x-1) (x-9) to get x^2-10x+9
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    (Original post by tushar_1)
    ye u are right. this person has factorised wrongly, it shud b (x-1) (x-9) to get x^2-10x+9
    It is a typo as he has it correctly above the but copies it down wrong
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    Can someone please explain the answer for the last question?

    The last one was the only one where my mind literallly went blank.
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    216° was given as the reflex angle of the arc, and 15cm as the radius. I used these things to find the length of the arc by obviously doing:

    pi x d (30cm) x 216/360

    I believe that the arc length would give me the actual circumference of the base, because when the net is folded, that would be the bottom edge. So if you do the calculation for the arc length above, you find the circumference of the base must be 56.54866776.

    So I did

    56.54866776= πd
    18=d (divded by pi)
    so base r= 9

    I then just drew a right angled triangle with the side slope (15cm), the radius of the base (9cm) and the height that was asked for. And used pythagorases theorem like this

    15²-9²=144
    √144=h
    h=12.
 
 
 
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