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    (Original post by MasterOfTheSwag)
    For Q2,
    1) Time period against frequency was the y=1/x graph,
    2)Kinetic energy against velocity was y=x²,
    3) Distance between slits and screen against fringe spacing was y=x
    4) Distance against time (with constant acceleration) is y=x² (as s=at²)
    I can't remember the letters but hopefully you can all see that is true.
    1) B
    2) C
    3) A
    4) C

    I don't think they were in this order in the exam however!
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    (Original post by MasterOfTheSwag)
    For Q2,
    Time period against frequency was the y=1/x graph,
    Kinetic energy against velocity was y=x²,
    Distance between slits and screen against fringe spacing was y=x
    Distance against time (with constant acceleration) is y=x² (as s=at²)
    I can't remember the letters but hopefully you can all see that is true.

    (Original post by MasterOfTheSwag)
    For Q2,
    Time period against frequency was the y=1/x graph,
    Kinetic energy against velocity was y=x²,
    Distance between slits and screen against fringe spacing was y=x
    Distance against time (with constant acceleration) is y=x² (as s=at²)
    I can't remember the letters but hopefully you can all see that is true.
    C
    B
    A
    B

    I think is the correct order then. I think it went proportional, x^2, 1/x, then the weird one
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    (Original post by DomStaff)
    To those who are talking about Q2. There was definitely an A there and no D. So one was repeated, but which one I have forgotten.
    Was it BCAA or something like that?


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    (Original post by DomStaff)
    C
    B
    A
    B

    I think is the correct order then. I think it went proportional, x^2, 1/x, then the weird one
    I agree with this version. As long as we can all agree on the correct shapes of the graphs I wouldn't worry though.
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    (Original post by MasterOfTheSwag)
    I agree with this version. As long as we can all agree on the correct shapes of the graphs I wouldn't worry though.
    Yeah those were definitely the shapes I got
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    Pretty easy exam right guys? made a couple of stupid mistakes like 0.66m = half wavelength, and then wrote 1 wave length was 0.33m (retard) and I wrote 1 less A and N for the antinode and node question. Probably also lost some marks on the wordy answers, either way, should hopefully end up in the 90's oor worst case scenarios high 80's. Will be distraught if I dont get 95% UMS, if not 100% UMS :P
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    Umm question 3 was 1m for the height of and adult man and 10^-4 for the cross sectional area of a finger
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    So far we have: 1. a) Js^-1 b)kg m s^-2
    2. C B A B
    3. Human length estimate: 1m Finger area estimate: 1x10-4m²
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    4. Fairly sure it was the one with the incorrect spelling..
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    I think I put ACBC??

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    (Original post by emfp21)
    I think I put ACBC??

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    I'm fairly sure A was a linear graph, and that would not make sense for f=1/T. C was the y=1/x graph, so I think C was first.
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    (Original post by MasterOfTheSwag)
    So far we have: 1. a) Js^-1 b)kg m s^-2
    2. C B A B
    3. Human length estimate: 1m Finger area estimate: 1x10-4m²
    4 was the box with the error, that red light diffracts through a larger angle.

    5 phasers were, B and H I think, well anyway the two that were one wavelength apart.
    ii I think it was phase E, so amplitude pointing at 3 o'clock, the next one g was at about 10-11 o'clock
    Iii just form an equilateral triangle with phasers.

    Can't remember the next question

    Then it was a show that question to get d = 1.888 um ~ 2um.
    ii 630nm, something like that. You make theta = 90 and then rearrange for lambda with d = 1.9um.

    That's all of section A I can remember.
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    (Original post by DomStaff)
    4 was the box with the error, that red light diffracts through a larger angle.

    5 phasers were, B and H I think, well anyway the two that were one wavelength apart.
    ii I think it was phase E, so amplitude pointing at 3 o'clock, the next one g was at about 10-11 o'clock
    Iii just form an equilateral triangle with phasers.

    Can't remember the next question

    Then it was a show that question to get d = 1.888 um ~ 2um.
    ii 630nm, something like that. You make theta = 90 and then rearrange for lambda with d = 1.9um.

    That's all of section A I can remember.
    I agree with all of these answers.
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    (Original post by MasterOfTheSwag)
    I'm fairly sure A was a linear graph, and that would not make sense for f=1/T. C was the y=1/x graph, so I think C was first.
    C was the x^2 graph. B was the 1/x graph.
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    (Original post by Knowing)
    C was the x^2 graph. B was the 1/x graph.
    Oh Christ I think you're right. Oh well, the sentiment is there. I think we should just stick to specifying graph type for now, so 1/x, x², x, x²
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    If I don't get 95+/100 and 100% UMS I will not be happy.

    Hoping 100% will be about 90/100 so I should be in the clear! I can't imagine it being any higher and it certainly won't be much lower:
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    (Original post by MasterOfTheSwag)
    I agree with all of these answers.
    I drew a right angled triangle instead of equilateral will that matter??

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    (Original post by emfp21)
    I drew a right angled triangle instead of equilateral will that matter??

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    Technically speaking it is incorrect because all phasors should have the same amplitude, but whether they will condone it, I don't know.
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    (Original post by MasterOfTheSwag)
    I agree with all of these answers.
    5ii. Mine was 9o'clock as it had only moved through a 1/4 of a wave and was moving in the anti-clockwise direction. I got the same for G though? Thoughts?
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    (Original post by emfp21)
    I drew a right angled triangle instead of equilateral will that matter??

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    Technically would be wrong, as it said all phasors had the same amplitude.

    ...but not sure how pedantic OCR will be; you might get it if it resolved
 
 
 
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