OCR B Salter's Chemistry by Design F335 - 15th June 2015 Watch

username1082804
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#341
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#341
(Original post by Solarburst)
If the substrate conc increases and inhibitor stays the same surely rate will increase?

Isn't it all about the relative proportions
That's what I put!
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Charletitia
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#342
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(Original post by GrahamRianna)
I thought it said it was a liquid in the opening paragraph


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It did but then it said 'in pure form'.


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Charletitia
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#343
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#343
(Original post by Remedium)
Did anyone get the percentage of NO formed from ammonia or something? The weird 50cm3 question


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8% - total guess!


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Diamond Crafter
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#344
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#344
(Original post by Solarburst)
If the substrate conc increases and inhibitor stays the same surely rate will increase?

Isn't it all about the relative proportions
Only up until a certain point. After which the rate levels out (no effect) because all the enzymes that CAN form enzyme-substrate complexes HAVE formed them. So the rate cannot possibly go any faster because no more enzyme was being added.
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Solarburst
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#345
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(Original post by Diamond Crafter)
Only up until a certain point. After which the rate levels out (no effect) because all the enzymes that CAN form enzyme-substrate complexes HAVE formed them. So the rate cannot possibly go any faster because no more enzyme was being added.
Yeah but it had no mention of enzymes being a limiting factor
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king cobra
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#346
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#346
A star and full ums boundaries guys any predictions ? Higher or lower than last year ?


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GrahamRianna
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#347
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#347
It said that the inhibitor was still present, surely the rate doesn't change even if substrate conc increased because all of the enzyme active sites are still occupied by the inhibitor?


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kingcobra007
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#348
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#348
(Original post by Remedium)
I got pH 10 as you have to take into account the dilution factor and use the Kw formula.

The total solution volume was 55cm3 so divide moles by 0.055 to get 1x10-10

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yay i got 10 as well
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Diamond Crafter
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For the question about why phenelzine (or whatever it was) absorbed UV light and other aromatic compounds absorbed light in the visible region, did people put:

Phenelzine has less delocalisation compared to other aromatic compounds such as dyes thus the energy gap between the energy levels are bigger thus a higher frequency of light is needed to be absorbed by the electrons to become promoted to a higher energy level. This corresponds to UV light on the absorption spectrum. And vice versa-ish for aromatic compounds?
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Welbeck
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(Original post by kingcobra007)
yay i got 10 as well
I got 10 too
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Solarburst
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(Original post by GrahamRianna)
It said that the inhibitor was still present, surely the rate doesn't change even if substrate conc increased because all of the enzyme active sites are still occupied by the inhibitor?


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Inhibitor was reversible, it had it in bold in the question so it must be important/ there for a reason
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diba786
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#352
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#352
For the last question....did ppl say distil or heat under reflux? what did the question say? Reaction that aldehyde undergo...or how its formed?
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disillusion
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(Original post by GrahamRianna)
It said that the inhibitor was still present, surely the rate doesn't change even if substrate conc increased because all of the enzyme active sites are still occupied by the inhibitor?


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Reversible
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ssaahhaanndd
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#354
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What do you guys reckon the grade boundaries Gonna be like?im thinking
F334 65 for A
F335 85-90 for A
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disillusion
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#355
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Formed , distil
(Original post by diba786)
For the last question....did ppl say distil or heat under reflux? what did the question say? Reaction that aldehyde undergo...or how its formed?
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Solarburst
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(Original post by diba786)
For the last question....did ppl say distil or heat under reflux? what did the question say? Reaction that aldehyde undergo...or how its formed?
Aldehyde, distil, acidified potassium dichromate, green

I think those are the answers
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BrokenS0ulz
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#357
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(Original post by Diamond Crafter)
For the question about why phenelzine (or whatever it was) absorbed UV light and other aromatic compounds absorbed light in the visible region, did people put:

Phenelzine has less delocalisation compared to other aromatic compounds such as dyes thus the energy gap between the energy levels are bigger thus a higher frequency of light is needed to be absorbed by the electrons to become promoted to a higher energy level. This corresponds to UV light on the absorption spectrum. And vice versa-ish for aromatic compounds?
yeah i said that
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Charletitia
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(Original post by diba786)
For the last question....did ppl say distil or heat under reflux? what did the question say? Reaction that aldehyde undergo...or how its formed?
What the aldehyde undergoes!
I put acidified potassium dichromate, heat under reflux and green!


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Welbeck
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#359
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was the last question 2 or 3 marks?
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Diamond Crafter
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(Original post by Welbeck)
was the last question 2 or 3 marks?
I think 3.
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