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    Wait how did people get 4-ln(3) for the area underneath?

    The line intersected at 1 and 4

    Area of rectangle = 3 x 1 ?
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    How did you do the arccosx = arcsinx? I got x=1/4 pie...
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    (Original post by Lord-Febreeze)
    what was the formula of they function that we had to differentiate twice in q8? im sure it wasnt (x-2)2/2 as has been said earlier, although i could be wrong
    Replace the 2 with an x
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    Did everyone remember to add "+ c" at the end of answer in question 2??
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    What did everyone get for the y value for the first question?


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    (Original post by chizz1889)
    Will I lose a mark for saying 'x= (root2)/2' I didn't put +/- but it was only a two mark question
    -root2/2 doesn't work as a solution


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    (Original post by QueNNch)
    Did everyone remember to add "+ c" at the end of answer in question 2??
    Yeah although in mark schemes at c3 they usually condone omission of c
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    (Original post by QueNNch)
    Did everyone remember to add "+ c" at the end of answer in question 2??
    Ahh ****


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    (Original post by Gcseboy1997)
    -root2/2 doesn't work as a solution


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    Oh yeah 😂😅 got 2/2 there then ☺️
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    (Original post by QueNNch)
    Did everyone remember to add "+ c" at the end of answer in question 2??
    Wasn't it +0.5c because you multiply by a half? Help!!
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    (Original post by ThatWasHard!)
    Wasn't it +0.5c because you multiply by a half? Help!!
    No if you multiply c by any constant then it remains as c as c represents a constanct you don't know ☺️
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    (Original post by Jim997)
    How did you do the arccosx = arcsinx? I got x=1/4 pie...
    arccosx= -arcsinx +1/2pi
    Therefore 2arcsinx -1/2pi = 0
    Therefore arcsin x= 1/4 pi
    Therefore x =sin(1/4pi)
    Therefore x= root2/2 :-)


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    (Original post by chizz1889)
    No if you multiply c by any constant then it remains as c as c represents a constanct you don't know ☺️
    Would a mark be taken off for that?
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    Vote on the difficulty of this paper here:http://strawpoll.me/4609673
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    (Original post by Gcseboy1997)
    arccosx= -arcsinx +1/2pi
    Therefore 2arcsinx -1/2pi = 0
    Therefore arcsin x= 1/4 pi
    Therefore x =sin(1/4pi)
    Therefore x= root2/2 :-)


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    Or you can do arccosx=theta=arcsinX
    X=costheta=sintheta
    Tantheta = 1 so theta = pi/4 x=sin(pi/4)=root2/2
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    (Original post by Gcseboy1997)
    arccosx= -arcsinx +1/2pi
    Therefore 2arcsinx -1/2pi = 0
    Therefore arcsin x= 1/4 pi
    Therefore x =sin(1/4pi)
    Therefore x= root2/2 :-)



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    Wow we've never been taught that ...
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    (Original post by chizz1889)
    No if you multiply c by any constant then it remains as c as c represents a constanct you don't know ☺️
    What did you get for the question where you had to calculate the area between y=1 and the curve?

    Wasn't it 3 x 1? Since it intersects at 4 and 1

    So 3 - Integral of the Curve
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    i did **** in this paper. reckon i got max 50 marks. If i got 16/18 in the coursework then will that pull up the C3 grade much from the C average it says i'll get from looking at the past papers?
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    Would I loose marks on 6 (I) for leaving the answer as x= sin(pie/6) ?
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    What a beautiful exam.

    I ran out of time on the last question but should get marks for working out and the graph. (didnt label the intersects though but yolo)

    That and arccosx = arcsinx which I had no clue about which was only 2 marks. I lost around 6 marks in that exam. Could only afford to lose 4 for the 90% A* so need to bang out on dreaded c4.

    Every question in that paper was from a past paper! Loved the rates of change one!
    It was literally copying and pasting from papers I've done but changing the numbers around
 
 
 
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