Hey there! Sign in to join this conversationNew here? Join for free
x Turn on thread page Beta

Edexcel FP2 Official 2016 Exam Thread - 8th June 2016 watch

    Offline

    22
    ReputationRep:
    (Original post by Emmak26)
    For de moivre's theorem, do we need to know the proof for both positive and negative integers? I mean positive i can manage it's just proof by induction by negative is just like extraaa...
    Nah. Just positive. Even negative is just proof by induction, BTW.
    Offline

    3
    ReputationRep:
    Hi does anyone know whether substitutions like these could be on FP2? http://madasmaths.com/archive/maths_...stitutions.pdf I don't think I've seen anything similar in past papers, but not too sure! Thanks
    Offline

    18
    ReputationRep:
    (Original post by economicss)
    Hi does anyone know whether substitutions like these could be on FP2? http://madasmaths.com/archive/maths_...stitutions.pdf I don't think I've seen anything similar in past papers, but not too sure! Thanks
    Well yeh transforming de's to solvable de's can come up, but they will give you a sub so all you need to do is substitute it which is easy.


    Posted from TSR Mobile
    Offline

    3
    ReputationRep:
    (Original post by physicsmaths)
    Well yeh transforming de's to solvable de's can come up, but they will give you a sub so all you need to do is substitute it which is easy.
    Posted from TSR Mobile
    Thank you
    Offline

    2
    ReputationRep:
    Question 6a in the june 2009 paper: in the MS - the first step they do in the fancy brackets, I dont get what we're doing to change |wi| to |w|? where does the i go?


    https://8dedc505ac3fba908c50836f5905...%20Edexcel.pdf
    Offline

    2
    ReputationRep:
    (Original post by imnoteinstein)
    Question 6a in the june 2009 paper: in the MS - the first step they do in the fancy brackets, I dont get what we're doing to change |wi| to |w|? where does the i go?


    https://8dedc505ac3fba908c50836f5905...%20Edexcel.pdf
    the magnitude of i is 1, so if it is in the modulus brackets you can just get rid of it
    • Thread Starter
    Offline

    15
    ReputationRep:
    How is FP2 going for everyone?

    I keep getting 70/75+ on every past paper I lay my hands on (bar one - 63/75 :laugh:), I hope the actual exam goes as well. FP2 papers are quite repetitive, hence the high grade boundaries.

    Chapter 3 transformations can be quite difficult for me sometimes (this is where I slip up the most), DE's are the easiest IMO
    Offline

    22
    ReputationRep:
    (Original post by edothero)
    How is FP2 going for everyone?
    It's going okay so far, I think.
    Offline

    3
    ReputationRep:
    Please could explain question 52b please, I understand up to finding the value of cos squared theta but I don't understand the last line of the mark scheme! Thanks Attachment 528889528891Name:  image.jpg
Views: 113
Size:  478.0 KB
    Attached Images
     
    Offline

    22
    ReputationRep:
    (Original post by economicss)
    Please could explain question 52b please, I understand up to finding the value of cos squared theta but I don't understand the last line of the mark scheme! Thanks Attachment 528889528891Name:  image.jpg
Views: 113
Size:  478.0 KB
    It's just saying that cos (3pi/10) is smaller than cos (pi/10) so cos(3pi/10) is the smaller root (5-sqrt(5)) instead of being the bigger root (5 + sqrt(5)).
    Offline

    3
    ReputationRep:
    (Original post by Zacken)
    It's just saying that cos (3pi/10) is smaller than cos (pi/10) so cos(3pi/10) is the smaller root (5-sqrt(5)) instead of being the bigger root (5 + sqrt(5)).
    Thank you
    • Thread Starter
    Offline

    15
    ReputationRep:
    More or less a month left for the exam, good luck to all!
    Offline

    14
    ReputationRep:
    Got a mock tomorrow and have only briefly looked at the first 5 chapters. Pray 4 me
    Offline

    22
    ReputationRep:
    (Original post by JoshC98)
    Got a mock tomorrow and have only briefly looked at the first 5 chapters. Pray 4 me
    It's just a mock, doesn't really matter this close to the exam, does it?
    Offline

    15
    (Original post by JoshC98)
    Got a mock tomorrow and have only briefly looked at the first 5 chapters. Pray 4 me
    “The Lord bless you and keep you; The Lord make His face shine upon you, And be gracious to you; The Lord lift up His countenance upon you, And give you peace.”’
    Offline

    2
    ReputationRep:
    Can someone explain this to me please?
    Name:  Screenshot_1.png
Views: 84
Size:  20.6 KB
    Attachment 530469530471
    Attached Images
     
    Offline

    4
    ReputationRep:
    (Original post by Chirstos Ioannou)
    Can someone explain this to me please?
    Name:  Screenshot_1.png
Views: 84
Size:  20.6 KB
    Attachment 530469530471
    The first step is to find z in terms of w. They have then expanded z into z = x + iy and w into w = u + iv. Next, they multiplied both sides by (1 - u + iv)/(1 - u + iv) to get rid of any imaginary numbers on the bottom, and then split the resulting fraction into real and imaginary parts.

    The question asks for y = 2x, so they equated the imaginary part of this (taking out i) with 2 lots of the real part of this. The denominators cancelled and the resulting algebra worked to give the equation of the circle.

    If you want me to go into more detail on a certain stage just say. In the exam, they would usually ask you a question which requires this method (where the algebra is usually more complicated) which requires you expanding z, or will give you a modulus of z substitution where you make z the subject and take the modulus of both sides (this is far more common and easy). Some questions may be worded slightly weirdly though, so you may need to use your initiative to answer them, but they're usually show questions.
    Offline

    2
    ReputationRep:
    (Original post by Craig1998)
    The first step is to find z in terms of w. They have then expanded z into z = x + iy and w into w = u + iv. Next, they multiplied both sides by (1 - u + iv)/(1 - u + iv) to get rid of any imaginary numbers on the bottom, and then split the resulting fraction into real and imaginary parts.

    The question asks for y = 2x, so they equated the imaginary part of this (taking out i) with 2 lots of the real part of this. The denominators cancelled and the resulting algebra worked to give the equation of the circle.

    If you want me to go into more detail on a certain stage just say. In the exam, they would usually ask you a question which requires this method (where the algebra is usually more complicated) which requires you expanding z, or will give you a modulus of z substitution where you make z the subject and take the modulus of both sides (this is far more common and easy). Some questions may be worded slightly weirdly though, so you may need to use your initiative to answer them, but they're usually show questions.
    Great answer, thank you very much! I think i got it
    Offline

    6
    ReputationRep:
    hi guys. Im really struggling on transformation questions (chapter 3). I barely get any questions correct. When I attempt them I sometimes get stuck in the middle and dont know what to do to solve them. Any help???
    Offline

    11
    ReputationRep:
    (Original post by arks_007)
    hi guys. Im really struggling on transformation questions (chapter 3). I barely get any questions correct. When I attempt them I sometimes get stuck in the middle and dont know what to do to solve them. Any help???
    These are quite helpful as he goes in depth https://www.youtube.com/playlist?lis...zClR4POCd-UmGB

    After getting your head around it you just need to do a lot of practice - it's a hard topic
 
 
 
Reply
Submit reply
Turn on thread page Beta
Updated: February 24, 2017
Poll
Do you agree with the proposed ban on plastic straws and cotton buds?

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Write a reply...
Reply
Hide
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.