x Turn on thread page Beta
 You are Here: Home >< Maths

# AQA A2 Mathematics MPC3 Core 3 - Wednesday 15th June 2016 [Official Thread] watch

1. Help, I'm doing June 2010 Q7B.

I used 0.2 in my integral and I keep getting like 0.022...

Mark scheme keeps showing like 2.095 can someone explain?

I am talking about the step from M1 to m1, I have no idea how it went that way.
2. (Original post by Dinasaurus)
Help, I'm doing June 2010 Q7B.

I used 0.2 in my integral and I keep getting like 0.022...

Mark scheme keeps showing like 2.095 can someone explain?

I am talking about the step from M1 to m1, I have no idea how it went that way.
3. (Original post by mickel_w)
HAha, I think that's what my problem was, I was in degrees not radians.
4. (Original post by SunDun111)
hey guys if i was asked to sketch a random inverse graph how would I do it
use graphical calculator?
5. (Original post by Dinasaurus)
HAha, I think that's what my problem was, I was in degrees not radians.
wait, ive just done it in radians
its 0.032
I think it's because you are forgetting the 64(pi) at the beginning - in m1 they leave the pi outside the brackets but multiply 0.032 by 64 which is equal to 2.09
6. (Original post by fpmaniac)
Yep, thats right
7. is one to many the same as many to one?
8. Goodluck people.
9. Can someone plz help me with june 15 q2 on how should you draw this equation y= 4 - I 2x+1 I
Thee lines mean modulus
10. (Original post by koolgurl14)
Can someone plz help me with june 15 q2 on how should you draw this equation y= 4 - I 2x+1 I
Thee lines mean modulus
This means that you do the modulus, but the minus means that it is reflected in the x-axis, meaning that everything is below the x-axis. Then you raise the line by 4 in the y-direction, as it gives a translation by vector (0,4)

Posted from TSR Mobile
11. (Original post by SunDun111)
Goodluck people.
You too, mate

Posted from TSR Mobile
12. (Original post by koolgurl14)
is one to many the same as many to one?
No. Many to one means that for a particular y values there are more than one x values, think sinx or x2.
One to many means that for one x value, there are multiple y values, think x=y2 and x=siny.
13. Can somebody quickly tell me how to find an inverse function on the calculator, like to get the points so you can plot them. I have a Casio fx-991ES plus, I know how to get values to plot but what do I put as begin and end value and steps?
14. When you are integrating for example (y-8)^2 how do you know whether to integrate by raising the power and diving by it, or by multiplying the brackets out and integrating that way? I've come across a different way in the mark scheme every time and I never know which to do. Thanks
15. (Original post by FluorescentM)
When you are integrating for example (y-8)^2 how do you know whether to integrate by raising the power and diving by it, or by multiplying the brackets out and integrating that way? I've come across a different way in the mark scheme every time and I never know which to do. Thanks

You raise the power and divide by the new power as you said , however don't forget to multiply by the differential of the bracket. - reverse chain rule

It just depends on the difficulty of the question i think

[ Take (2x^2 -4)^3 , the integral would be (2x^2-4)^4/16x ]
16. (Original post by FluorescentM)
When you are integrating for example (y-8)^2 how do you know whether to integrate by raising the power and diving by it, or by multiplying the brackets out and integrating that way? I've come across a different way in the mark scheme every time and I never know which to do. Thanks
i use substiution e.g. u = y - 8
17. (Original post by SunDun111)
Goodluck people.
Cheers, you too bro.
18. (Original post by xs4)
You raise the power and divide by the new power as you said , however don't forget to multiply by the differential of the bracket. - reverse chain rule

It just depends on the difficulty of the question i think

[ Take (2x^2 -4)^3 , the integral would be (2x^2-4)^4/16x ]
(Original post by SunDun111)
i use substiution e.g. u = y - 8
Okay thank you both good luck for tomorrow!
19. (Original post by MahuduElec)
Integrate x^2(x^3-10)^6 .dx

I made this up, but using that 'reverse chain rule', you can do this in two or so steps without parts/substitution.
I have done this in my head: (1/21)(x^3-10)^7
20. Good luck everyone! ☺

TSR Support Team

We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

This forum is supported by:
Updated: June 1, 2017
Today on TSR

### Any tips for freshers...

who are introverts?

### More snow?!

Discussions on TSR

• Latest
Poll
Useful resources

Can you help? Study help unanswered threadsStudy Help rules and posting guidelinesLaTex guide for writing equations on TSR

## Groups associated with this forum:

View associated groups
Discussions on TSR

• Latest

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE