You are Here: Home >< Maths

# Edexcel AS/A2 Mathematics M1 - 8th June 2016 - Official Thread watch

When can you assume that the reaction forces at two supports are the same? Is it only when the questions tell you they are, otherwise always assume they are not the same magnitude?
Only when they tell you they are, definitely

Posted from TSR Mobile
2. (Original post by 83457)
What are some of the hardest past papers people have come across for M1? Doesn't have to be Edexcel (and I'd prefer non-Edexcel ones, since I think I've done the hard ones from that )
My favourite M1 problem ever!!! And home made of course.
3. (Original post by Cryptokyo)
My favourite M1 problem ever!!! And home made of course.
only 6 marks?
When can you assume that the reaction forces at two supports are the same? Is it only when the questions tell you they are, otherwise always assume they are not the same magnitude?
Yes exactly! Or the reaction forces are equidistant from the centre of mass of the rod and the weight of the rod is the only force acting downwards.
5. (Original post by KloppOClock)
only 6 marks?
Well for the tension... [please elaborate]
6. (Original post by KloppOClock)
here
Minor update to certain wording of the questions but otherwise the same stuff!
Attached Images
7. Mechanics 1 Practice Paper 4 UPDATE.pdf (510.5 KB, 69 views)
8. (Original post by KloppOClock)
if its is an isoceles triangle, and sinA=3/4, then drawing a triangle gives cosA as 3/4 as well i think?

cosa^2+sina^2 = 1.125 but i thought that was supposed to be equal to one
and so
9. (Original post by Cryptokyo)
and so
yh i forgot that was just for right angle triangles
10. (Original post by KloppOClock)
yh i forgot that was just for right angle triangles
Well you can split into two right angled triangles.
11. (Original post by Cryptokyo)
My favourite M1 problem ever!!! And home made of course.
Do yoy have the answer for a? Not sure ive done it right
12. (Original post by metrize)
Do yoy have the answer for a? Not sure ive done it right
yeah same, i got (18-3root7)/4
13. [QUOTE=metrize;65449145]Do yoy have the answer for a? Not sure ive done it right[/QUOTE

Spoiler:
Show
Set up equations:

Sub in values known to get

Back into first equation:

Tension is 12.6N

14. [QUOTE=Cryptokyo;65450051]
(Original post by metrize)
Do yoy have the answer for a? Not sure ive done it right[/QUOTE

Spoiler:
Show
Set up equations:

Sub in values known to get

Back into first equation:

Tension is 12.6N

Ah i messed up because for the 1kg particle i didnt realise it would have moved up the plane
15. [QUOTE=Cryptokyo;65450051]
(Original post by metrize)
Do yoy have the answer for a? Not sure ive done it right[/QUOTE

Spoiler:
Show
Set up equations:

Sub in values known to get

Back into first equation:

Tension is 12.6N

oh i thought that as it says the rod remains in equilbrium, then the blocks remained in equilbrium, which isnt true
16. [QUOTE=KloppOClock;65450303]
(Original post by Cryptokyo)

oh i thought that as it says the rod remains in equilbrium, then the blocks remained in equilbrium, which isnt true
The force that the tension exerts on the pulley keeps the rod in equilibrium as it produces a moment.
17. [QUOTE=Cryptokyo;65450607]
(Original post by KloppOClock)

The force that the tension exerts on the pulley keeps the rod in equilibrium as it produces a moment.
so the resultant force of the tension acting on the rod is equal to the weight of the particle on the rod?
18. Yes
(Original post by KloppOClock)

so the resultant force of the tension acting on the rod is equal to the weight of the particle on the rod?
19. Can someone help me urgently please? <3

LOOK IN DIAGRAM!

So in this question where it says 2.5 -x

I labelled that part as x and the other part where it says x as 2.5 - x, so essentially I switched them around

I did the calculation and got x = 2 MY WAY, but the mark scheme way (not switched around) got x = 0.5

Am I not aloud to label the end part as 2.5 - x or something?
Attached Images

20. (Original post by KINGYusuf)
Can someone help me urgently please? <3

LOOK IN DIAGRAM!

So in this question where it says 2.5 -x

I labelled that part as x and the other part where it says x as 2.5 - x, so essentially I switched them around

I did the calculation and got x = 2 MY WAY, but the mark scheme way (not switched around) got x = 0.5

Am I not aloud to label the end part as 2.5 - x or something?
No yours is right, you just have to mention that it is 2 metres from M to B or something like that.

Posted from TSR Mobile
21. (Original post by SaphBruh)
No yours is right, you just have to mention that it is 2 metres from M to B or something like that.

Posted from TSR Mobile
Thanks, I was so stressed

TSR Support Team

We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

This forum is supported by:
Updated: October 25, 2016
Today on TSR

### The most controversial member on TSR?

Who do you think it is...

### Is confrontation required?

Discussions on TSR

• Latest
Poll
Useful resources

Can you help? Study help unanswered threadsStudy Help rules and posting guidelinesLaTex guide for writing equations on TSR

## Groups associated with this forum:

View associated groups
Discussions on TSR

• Latest

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE