Turn on thread page Beta
    Offline

    13
    I think I got about 61/62 in this paper, and I think I got 16/17 in the coursework - any chance this will be an A*?


    Posted from TSR Mobile
    Offline

    0
    ReputationRep:
    What would you get the individual marks for on the rate of change one? Completely messed that one up...
    Offline

    12
    ReputationRep:
    (Original post by iAmanze)
    What a beautiful exam.

    I ran out of time on the last question but should get marks for working out and the graph. (didnt label the intersects though but yolo)

    That and arccosx = arcsinx which I had no clue about which was only 2 marks. I lost around 6 marks in that exam. Could only afford to lose 4 for the 90% A* so need to bang out on dreaded c4.

    Every question in that paper was from a past paper! Loved the rates of change one!
    It was literally copying and pasting from papers I've done but changing the numbers around
    For the rates of change questionwas it cos45 = H divided by R?And I got R = H/COS45
    Offline

    18
    ReputationRep:
    (Original post by groovyd97)
    I think I got about 61/62 in this paper, and I think I got 16/17 in the coursework - any chance this will be an A*?


    Posted from TSR Mobile
    Nope.

    max = 90.

    best case scenario: 62 + 17 = 79

    79x100 / 90 = 88% (2s.f). Close

    Bang out on C4 mate.
    Offline

    2
    ReputationRep:
    A grade boundaries for past few years:
    June 14: 58
    June 13: 58
    Jan 13: 60
    June 12: 60
    Jan 12: 55
    June 11: 54
    Jan 11: 54

    Considering this exam was quite hard, and everyone I've spoken to said they struggled, I predict an A to be between 54-56 marks


    Posted from TSR Mobile
    Offline

    2
    ReputationRep:
    Is there an unofficial mark scheme yet?
    Offline

    18
    ReputationRep:
    (Original post by Hody421)
    For the rates of change questionwas it cos45 = H divided by R?And I got R = H/COS45
    Cos would insinuate we have the hypotenues. We only were given the opposite which was r and adjacent which was h if I remember correctly. Thus needed to be in form of tan45.

    tan45 = r/h

    so r = htan45.

    replace r in equation with this.
    Offline

    15
    ReputationRep:
    (Original post by Hody421)
    For the rates of change questionwas it cos45 = H divided by R?And I got R = H/COS45
    I assumed r=h because it was iscosceles
    Offline

    3
    ReputationRep:
    (Original post by Barrel)
    I've got the first one wrong and probably others


    Posted from TSR Mobile
    If you did the first one in radians you'd have ended up with 1.11ish which is would be okay.

    Posted from TSR Mobile
    Offline

    2
    ReputationRep:
    If on 9(iii) I forgot to minus the one so I got 4ln3 -4instead of 3ln3 -4 would I lose all the marks?
    Offline

    12
    ReputationRep:
    (Original post by iAmanze)
    Cos would insinuate we have the hypotenues. We only were given the opposite which was r and adjacent which was h if I remember correctly. Thus needed to be in form of tan45.

    tan45 = r/h

    so r = htan45.

    replace r in equation with this.
    Oh f***..

    Lost 3 marks I think.
    Offline

    0
    ReputationRep:
    here are some of my answers:

    1. (1.107,4.094)
    2. (3/8)(2x-1)^(4/3)
    3. 4ln2 - 15/16
    4. 1/20pi
    5. remind me what this question was please
    6. i) 0.5
    ii) (sqrt2)/2
    7.remind me what this question was please
    8. cant remember exactly what the questions were but for shaded area i got 4-3ln3 i think
    9. i) Q (-2, -8)
    ii) ln(3) lol not sure if these two questions were in 8 or 9
    iii) what was this question?
    iv) g(x) = ln(sqrt(x+1) + 2) domain x>/=-1 range y>/=ln2
    Offline

    2
    ReputationRep:
    (Original post by AlexParmenter)
    I assumed r=h because it was iscosceles
    Tan45=1. H*1=h. R=h
    Offline

    18
    ReputationRep:
    (Original post by AlexParmenter)
    I assumed r=h because it was iscosceles
    similar question:

    http://www.mei.org.uk/files/papers/c306ja_xjtwqz.pdf

    Q4.

    This is why i said it was a copy and paste exam for me. Every question that came up was virtually from another paper.
    Offline

    2
    ReputationRep:
    For the last seven marker I managed to rearrange to the inverse and got the range and domain but I messed up the graph. What do you think I would of gotten out of seven?
    Offline

    2
    ReputationRep:
    (Original post by Jim997)
    Wow we've never been taught that ...
    I knew how the graphs were plotted so I drew them on the same graph and saw the translation


    Posted from TSR Mobile
    Offline

    2
    ReputationRep:
    (Original post by JamesExtra)
    If on 9(iii) I forgot to minus the one so I got 4ln3 -4instead of 3ln3 -4 would I lose all the marks?
    Anyone know if I'd lose all 5?
    Offline

    3
    ReputationRep:
    (Original post by JamesExtra)
    Anyone know if I'd lose all 5?
    No, you'd lose 1, max 2 marks I reckon
    Offline

    12
    ReputationRep:
    (Original post by iAmanze)
    similar question:

    http://www.mei.org.uk/files/papers/c306ja_xjtwqz.pdf

    Q4.

    This is why i said it was a copy and paste exam for me. Every question that came up was virtually from another paper.
    Wait so how many marks would I lose

    I got the chain rule correct -

    Is it 3?
    Offline

    2
    ReputationRep:
    (Original post by ArielHaeems)
    No, you'd lose 1, max 2 marks I reckon
    Ok thanks
 
 
 
Reply
Submit reply
Turn on thread page Beta
Updated: April 20, 2016

1,597

students online now

800,000+

Exam discussions

Find your exam discussion here

Poll
Should predicted grades be removed from the uni application process

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Write a reply...
Reply
Hide
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.