PC2 Maths, AQA 24/05/10 Watch

war833
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#21
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#21
(Original post by Jono404)
I never got round to teaching myself sigma notation so lost 4 marks there annoyingly.

The one where you had to translate the graph and find out where y=0, it was like 2^(4x-1)-0.5 wasn't it? then I got X=0 but I don't think that was right.
I can confirm X=0. Hope its right.
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lifeadd1ct
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#22
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(Original post by Ollie901)
I found it quite difficult as well.
I thought it was harder then the past papers from the past 3 or 4 years, but that may just be because of my lack of sleep last night (dodgy chinese )

Q4 threw me a bit as well. What did you get for p & q?
I got -3 and 3 I think.
I got a negative area on the bit afterwards. Can't remember what it was exactly but it was a small number.
The constants of the binomial expansion were 1, -3, 3, -1 (the third row of pascal's triangle)
The area was 100% 1.7 and the answer you are getting is - because the graph was under the x- axis. I left it as a minus. Hopefully won't lose any marks.

The only question i struggled and got wrong was the translations.
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Jono404
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#23
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(Original post by Ollie901)
Yes!
I got exactly the same. Please tell me you are good at maths :P
I spent quite a bit of time subbing values back in etc to check so I'm fairly sure they're right, was so unsure about the limit to infinity one though
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Jono404
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#24
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#24
(Original post by war833)
I can confirm X=0. Hope its right.
Casio FX991es equation solver saves my life once again
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memomemootoo
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#25
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#25
is it just me or did anyone else find the last few log questions difficult?
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lifeadd1ct
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#26
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#26
(Original post by Jono404)
Casio FX991es equation solver saves my life once again
I got x=0 as well....But my teachers told me it wasn't. PLEASEESESESES please tell me you are correct, sir. If yes I'm getting drunk tonight!!!!
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war833
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#27
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(Original post by memomemootoo)
is it just me or did anyone else find the last few log questions difficult?
Very.
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lifeadd1ct
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#28
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#28
The last log question was quite hard because you had to spot that log(base10)2.5/log(base10)2 + 3 =1/log(base10)2
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chronicl3
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#29
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#29
(Original post by lifeadd1ct)
I got x=0 as well....But my teachers told me it wasn't. PLEASEESESESES please tell me you are correct, sir. If yes I'm getting drunk tonight!!!!
I got x= 0.75.

Cuz after the translation the equation would become 2^4(x-1)-0.5 that is 2^4x-4 - 0.5
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memomemootoo
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#30
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#30
(Original post by war833)
I can confirm X=0. Hope its right.
oh crap...i got x=0 aswell and then i might have crossed it out :zomg:
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N!*
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#31
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#31
(Original post by Jono404)
Okay that was a touch solid, the binomial expansion/integration one had me stumped for ages had to go back and spend 15 mins on it at the end.

Answers I can remember:

Second term of arithmetic sequence 8, common difference -0.5, limit to infinity of geometric series 10?

p and q on the binomial were -3 and 3, then you integrated and got -1.7

gradient was 3/2 and gradient of normal -2/3 (might be other way round)

Trapezium Rule was 5.55
Phew, glad I wasn't the only one who found Q4 difficult.

I was rushing at the and and put P=3, Q=3.
What were the marks for that question, would I have got 1 mark for that?

Can't remember the others, but I got the trapezium one correct :yeah:
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lifeadd1ct
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#32
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#32
(Original post by chronicl3)
No, I got x= 0.75.

Cuz after the translation the equation would become 2^(4x-1)-0.5 that is 2^4x-4 - 0.5
ye that's what my teacher said but he told me he wasn't 100% positive.
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war833
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#33
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(Original post by chronicl3)
No, I got x= 0.75.

Cuz after the translation the equation would become 2^(4x-1)-0.5 that is 2^4x-4 - 0.5
Iirc after the translation it was 2^(4x-1)-0.5. Maybe I translated the original graph rather than the one it asked?
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Jono404
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#34
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#34
(Original post by N!*)
Phew, glad I wasn't the only one who found Q4 difficult.

I was rushing at the and and put P=3, Q=3.
What were the marks for that question, would I have got 1 mark for that?

Can't remember the others, but I got the trapezium one correct :yeah:
The p and Q one was only worth 2 marks which i thought was weird, the thing that threw me is that the signs were ++- in the question
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chronicl3
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#35
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#35
(Original post by war833)
Iirc after the translation it was 2^(4x-1)-0.5. Maybe I translated the original graph rather than the one it asked?
I got 2^4(x-1) - 0.5
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rob...
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#36
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#36
The translation WAS 2^4(X-1) - 0.5! = 2^(4x-4) -0.5. x was 0.75 i'm certain.

I had to spend 5 mins explaining this to my maths teacher haha. Also for the 2^4x translates to 2^(4x-3) is a translation of 0.75 units parallel to x-axis. NOT +3 UNITS!!!
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lifeadd1ct
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#37
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#37
stupid translations..they costed me 2 marks in january's pure core 3 (got 91%).
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Jono404
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#38
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#38
Yeah I see where I went wrong now, needed parentheses then expansion. How many marks was that worth? Hopefully I'll get one of them for the -0.5....
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war833
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#39
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#39
Oh crap!
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chronicl3
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#40
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#40
(Original post by rob...)
The translation WAS 2^4(X-1) - 0.5! = 2^(4x-4) -0.5. x was 0.75 i'm certain.

I had to spend 5 mins explaining this to my maths teacher haha. Also for the 2^4x translates to 2^(4x-3) is a translation of 0.75 units parallel to x-axis.
:yes:

Did you get " translation (3/4 0) for the question before that
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