Stuck on Matrix Algebra Watch
- Thread Starter
- 29-11-2010 18:41
(Original post by AG27)
- 29-11-2010 18:45
Yes, I did get up to that. The determinant I believe is 1, so shouldn't the matrix remain as it is?
- 31-12-2010 23:01
i have no idea why i'm bumping a month old thread
matrix multiplication is associative so (AB)(C) = I so C = B'A', and (A)(BC) = I so A = C'B' so CA = B'A'C'B', and if ABC = I then A'C'B' = I so CA = B'