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# Stuck on Matrix Algebra Watch

1. (Original post by Noble.)

Did you get up to that?

Yes, I did get up to that. The determinant I believe is 1, so shouldn't the matrix remain as it is?
2. (Original post by AG27)
Yes, I did get up to that. The determinant I believe is 1, so shouldn't the matrix remain as it is?
http://mathworld.wolfram.com/MatrixInverse.html
3. i have no idea why i'm bumping a month old thread

matrix multiplication is associative so (AB)(C) = I so C = B'A', and (A)(BC) = I so A = C'B' so CA = B'A'C'B', and if ABC = I then A'C'B' = I so CA = B'

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Updated: December 31, 2010
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