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1. (Original post by mia_14)
i am sorry. mistype
Problem is, a and b are still dependant, or at least can be.
2. i have couple more question is you can answer its
1)
What is the gradient (m) and intercept (c) for the straight line, 4y = 2x - 12 ?

2)Identify ALL of the following lines that are parallel with 2x + y - 4 = 0 .

1. 3y + 12 = -6x

2. y = 2x

3. 4 = 0.5y + x

4. y = 1 - 2x

5. y = 0.5x - 1

6. y = 2 - x

3)

Line (i) is perpendicular to y = 3x and passes through (0, 0)
Line (ii) is perpendicular to y = 2x + 3 and passes through (2, -1)
Line (iii) is perpendicular to 2x + y - 4 = 0 and passes through (3, 1)
Line (iv) is perpendicular to 2x + 3y = 4 and passes through (5, -1)
Line (v) is perpendicular to 4x - y + 1 = 0 and passes through (0, 6)

Matching pairs
Line (i) - Select choice -y = 3x - 1x + 3y = 06 - y = xNone of the other answersy = -2x3x - 2y = 172y = -xx - 2y - 1 = 0x + 4y - 24 = 0y = -3x

Line (ii) - Select choice -y = 3x - 1x + 3y = 06 - y = xNone of the other answersy = -2x3x - 2y = 172y = -xx - 2y - 1 = 0x + 4y - 24 = 0y = -3x

Line (iii) - Select choice -y = 3x - 1x + 3y = 06 - y = xNone of the other answersy = -2x3x - 2y = 172y = -xx - 2y - 1 = 0x + 4y - 24 = 0y = -3x

Line (iv) - Select choice -y = 3x - 1x + 3y = 06 - y = xNone of the other answersy = -2x3x - 2y = 172y = -xx - 2y - 1 = 0x + 4y - 24 = 0y = -3x

Line (v) - Select choice -y = 3x - 1x + 3y = 06 - y = xNone of the other answersy = -2x3x - 2y = 172y = -xx - 2y - 1 = 0x + 4y - 24 = 0y = -3x
3. (Original post by TheSownRose)
Problem is, a and b are still dependant, or at least can be.
tahts fine thank u so much

the thing is i am reallly ill and have to do this work before 12 nght or i am screwed . if you can help me do this work. all i can say .. your the best
4. (Original post by mia_14)
tahts fine thank u so much

the thing is i am reallly ill and have to do this work before 12 nght or i am screwed . if you can help me do this work. all i can say .. your the best
Yeah... Sorry about that one, but something isn't coming across properly on TSR because there's no way that I can see to unravel that.

These, however...

1)
What is the gradient (m) and intercept (c) for the straight line, 4y = 2x - 12 ?
Imagine that is 3y = 6x + 9.

You know the general formula equation is y = mx + c, so how do you get 3y = 6x + 9 into this form?
Spoiler:
Show
You need the y to be by itself, so divide through by 3 to isolate it:
(3y)/3 = (6x)/3 + (9/3)
--> y = 2x + 3

Now just see what numbers match the position of m and c:
m = 2
c = 3

2)Identify ALL of the following lines that are parallel with 2x + y - 4 = 0 .

1. 3y + 12 = -6x

2. y = 2x

3. 4 = 0.5y + x

4. y = 1 - 2x

5. y = 0.5x - 1

6. y = 2 - x
In the general graph equation, the m indicates gradient and c indicates where the lines crosses the y-axis. If two lines have the same gradient, they will be parallel; it doesn't matter where they cross the y-axis.

So this is a case of finding the gradients - you know how to do that ) - and seeing which ones are the same.

3)

Line (i) is perpendicular to y = 3x and passes through (0, 0)
Line (ii) is perpendicular to y = 2x + 3 and passes through (2, -1)
Line (iii) is perpendicular to 2x + y - 4 = 0 and passes through (3, 1)
Line (iv) is perpendicular to 2x + 3y = 4 and passes through (5, -1)
Line (v) is perpendicular to 4x - y + 1 = 0 and passes through (0, 6)

Matching pairs
Line (i) - Select choice -y = 3x - 1x + 3y = 06 - y = xNone of the other answersy = -2x3x - 2y = 172y = -xx - 2y - 1 = 0x + 4y - 24 = 0y = -3x

Line (ii) - Select choice -y = 3x - 1x + 3y = 06 - y = xNone of the other answersy = -2x3x - 2y = 172y = -xx - 2y - 1 = 0x + 4y - 24 = 0y = -3x

Line (iii) - Select choice -y = 3x - 1x + 3y = 06 - y = xNone of the other answersy = -2x3x - 2y = 172y = -xx - 2y - 1 = 0x + 4y - 24 = 0y = -3x

Line (iv) - Select choice -y = 3x - 1x + 3y = 06 - y = xNone of the other answersy = -2x3x - 2y = 172y = -xx - 2y - 1 = 0x + 4y - 24 = 0y = -3x

Line (v) - Select choice -y = 3x - 1x + 3y = 06 - y = xNone of the other answersy = -2x3x - 2y = 172y = -xx - 2y - 1 = 0x + 4y - 24 = 0y = -3x
I have no idea what this is even asking, and the layout is very confusing - sorry, again.
5. (Original post by TheSownRose)
Yeah... Sorry about that one, but something isn't coming across properly on TSR because there's no way that I can see to unravel that.

These, however...

Imagine that is 3y = 6x + 9.

You know the general formula equation is y = mx + c, so how do you get 3y = 6x + 9 into this form?
Spoiler:
Show
You need the y to be by itself, so divide through by 3 to isolate it:
(3y)/3 = (6x)/3 + (9/3)
--> y = 2x + 3

Now just see what numbers match the position of m and c:
m = 2
c = 3

In the general graph equation, the m indicates gradient and c indicates where the lines crosses the y-axis. If two lines have the same gradient, they will be parallel; it doesn't matter where they cross the y-axis.

So this is a case of finding the gradients - you know how to do that ) - and seeing which ones are the same.

I have no idea what this is even asking, and the layout is very confusing - sorry, again.

i dont what you mean what u said about the second question.
6. (Original post by mia_14)

i dont what you mean what u said about the second question.
The second question requires you to determine which lines are parallel. In order to be parallel, two lines must have the same equation. The m in y = mx + c determines gradient, so if two equations have the same value for m, they will be parallel.
7. (Original post by TheSownRose)
The second question requires you to determine which lines are parallel. In order to be parallel, two lines must have the same equation. The m in y = mx + c determines gradient, so if two equations have the same value for m, they will be parallel.
this last one please. just explain to me and give them ansswer
8. (Original post by mia_14)
this last one please. just explain to me and give them ansswer
Well, like I said before, won't give the answers because the idea is you learn what to do, not what the answer to just that question is. However, will give some hints to help you to learn.

Say you had an graph equation y = 7x - 8, so the gradient (how steep it is) is 7.

The line y = 7x + 3 would be parallel because its gradients match and therefore they have the same steepness. However, y = 4x + 2 would not because gradients are not the same - it has a gradient of 4.

The other way to check is to set them equal to one another and see if you can find an intersecting point; if you can, it's not parallel. If you can't, it is parallel.

y = 7x - 8
y = 7x + 3
--> 7x + 3 = 7x - 8

Can't be rearranged, you end up neutralising the x.

y = 7x - 8
y = 4x + 2
--> 4x + 2 = 7x - 8

3x = 10
x = 3.33333

y = (7 x 3.33333) - 8 = 15.3

They will cross eventually, and therefore cannot be parallel.
9. (Original post by thesownrose)
well, like i said before, won't give the answers because the idea is you learn what to do, not what the answer to just that question is. However, will give some hints to help you to learn.

Say you had an graph equation y = 7x - 8, so the gradient (how steep it is) is 7.

The line y = 7x + 3 would be parallel because its gradients match and therefore they have the same steepness. However, y = 4x + 2 would not because gradients are not the same - it has a gradient of 4.

The other way to check is to set them equal to one another and see if you can find an intersecting point; if you can, it's not parallel. If you can't, it is parallel.

Y = 7x - 8
y = 7x + 3
--> 7x + 3 = 7x - 8

can't be rearranged, you end up neutralising the x.

Y = 7x - 8
y = 4x + 2
--> 4x + 2 = 7x - 8

3x = 10
x = 3.33333

y = (7 x 3.33333) - 8 = 15.3

they will cross eventually, and therefore cannot be parallel.
you are bestttttttttttttttttttted

lots love from here xxxx

merry xmas / happy hols
10. (Original post by mia_14)
you are bestttttttttttttttttttted

lots love from here xxxx

merry xmas / happy hols
Merry Christmas yourself.

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