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# IB Maths HL 2012 Watch

1. The trig one was fine I multiplied the top and bottom by (CosA+SinA) and the answer presented itself. I think there were other ways too.
2. (Original post by MAMDS1993)
oh the xy=6 x^2-y^2=5 ??
What number was this? Q10 anyone xD, got the answer but it was only 7 marks........ I feel like it should have been at least 8 or 9.
3. I tried qn 10, I got up until the limits i got 1/2(e^(-x)sinx - e^(-x)cosx) and then put in the limits and ran out of time before I could complete..but I feel like I would've gotten it with abit more time! the xy=6 and x^2-y^2=5 was number 12! the complex number question where u had to find the roots of that number and its conjugate!
4. What do you guys think the grade boundaries for 7 and 6 are gonna be for paper 1?
5. 95 for 7. I never really pay attention to the 6 boundries so can't guess, sorry.

Did anyone else, in the complex numbers, get something weird for the argument like arctan((root7)/3 or something).
6. (Original post by arra)
95 for 7. I never really pay attention to the 6 boundries so can't guess, sorry.

Did anyone else, in the complex numbers, get something weird for the argument like arctan((root7)/3 or something).
It varies tremendously especially with HL Math. I've seen it go anywhere from 80 to 100.
7. (Original post by dogmatichurricane)
It varies tremendously especially with HL Math. I've seen it go anywhere from 80 to 100.
I've seen it at 74 on some papers. And today's Paper 2 was harder than those paper's for sure.

But this paper one was certainly on the easier side, so I'm guessing 95.
8. (Original post by arra)
I've seen it at 74 on some papers. And today's Paper 2 was harder than those paper's for sure.

But this paper one was certainly on the easier side, so I'm guessing 95.
Ah fair enough - I wouldn't think too much about it though. I came out of my papers last year thinking Paper 1 was straightforward and Paper 2 had the most messed up section B I had ever seen. Paper 1's grade boundary came out at 79 and Paper 2's was 84 or something along those lines if I remember right. Each to their own I guess....
9. (Original post by TTGenius)
the one u have to transfer to e^(iθ) form, anyone have ideas ????
Ok, I took my time to write this out for you guys

10. Guys low lets estimate the difficulty of paper 1 by a scale from 1 to 10 (1 easy to 10 hard)
11. I got the roots for the 5+2i, revised that the night before . I'd give it an 8 in relative terms, usually I find P1 easier than P2 for this year it was the opposite. I don't remember them exactly they were 2, -2 and 3i I think.
12. Paper 1 section A was a 3 or 4. Section B was a 5.
13. (Original post by Saymyname!)
Ok, I took my time to write this out for you guys

Oh I got that question pretty much then except i didn't put pi - and pi +! I put 2e^(i(arctan(root(7)/3)) and 2e^i(arctan(-root(7)/3))! Which is I suppose the same thing because pi plus gives u a positive sign and pi minus gives u a negative sign!
14. yeah -5+12i was (2+3i) or (-2-3i) and -5-12i (the conjugate i guess) was (2-3i) (-2+3i)!
15. People in my class didn't like paper 1..so its not everyone of us who thought it was okay! May 2009 TZ2 Paper 1 is one of the easiest papers I have ever seen and the boundary for that is 91! Even though our paper 1 was pretty good, I'd still say May 09 TZ2 P1 was way easier!
16. Was it 5+12i or -5+12i?
17. (Original post by Saymyname!)
Ok, I took my time to write this out for you guys

That is quite relieving....I got exactly that..at least all the answers look familiar

for the equation at start of part B

I got (x+4)(x-2)(x^2 + 3x +4)
18. (Original post by Banna)
That is quite relieving....I got exactly that..at least all the answers look familiar

for the equation at start of part B

I got (x+4)(x-2)(x^2 + 3x +4)
well done! I got the same equation!
19. (Original post by Saymyname!)
well done! I got the same equation!
Yeah I got that as well!!

I read -5+12i lol! And then the conjugate as -5-12i If it isn't here we go misread marks!
20. If u got 3i then im pretty sure u did -5+12i too! Coz 5+12i is (3+2i)^2 not (2+3i)^2

Updated: July 14, 2012
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