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    (Original post by SDavis123)
    Yh I did, did you see the picture?


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    I hadn't but I have now.

    So make y the subject. There are many ways you can do it. Combining the logarithms would be a sensible step and then you are going to need to raise both sides to base e.
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    (Original post by Mr M)
    I hadn't but I have now.

    So make y the subject. There are many ways you can do it. Combining the logarithms would be a sensible step and then you are going to need to raise both sides to base e.
    If before was painful, I think what your about to see might just be enough to knock you out!




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    (Original post by SDavis123)
    If before was painful, I think what your about to see might just be enough to knock you out!




    Posted from TSR Mobile
    You have some really worrying misconceptions.

    \sqrt{a^2+b^2} \neq a + b
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    (Original post by Mr M)
    You have some really worrying misconceptions.

    \sqrt{a^2+b^2} \neq a + b
    I'm not getting anywhere, sorry for the headache that I've caused you and thanks for trying to help


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    (Original post by SDavis123)
    I'm not getting anywhere, sorry for the headache that I've caused you and thanks for trying to help


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    Multiply through by 2 and combine the logarithms. Now exponentiate and you are pretty much there.
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    \frac{1}{2}\ln{(y^{2} + 1)} \not= \ln{(y + 1)}

    ^ Referring to what Mr M was saying.


    (Original post by Mr M)
    \sqrt{a^2+b^2} \neq a + b
 
 
 
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