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1. (Original post by madfish)
but their division by 2 is surly not correct?
Why not???
2. (Original post by madfish)
but their division by 2 is surly not correct?
They find the midpoint of the line and STATE that it is equal to (b,2a) which is correct. They then solve the corresponding equations correctly.
3. (Original post by madfish)
but their division by 2 is surly not correct?
How do you find a midpoint?
Add x1 and x2 and divide by 2, same with y coordinates.
And you know that centre is a midopoint, you have its coordinates given so you make the two things equal!
4. (Original post by purplemind)
How do you find a midpoint?
Add x1 and x2 and divide by 2, same with y coordinates.
And you know that centre is a midopoint, you have its coordinates given so you make the two things equal!
Im sorry but I dont get what you mean :|

2a-4 / 2 = a-2 not 2a? surly?
5. (Original post by joostan)
They find the midpoint of the line and STATE that it is equal to (b,2a) which is correct. They then solve the corresponding equations correctly.
how is it equal to b,2a ?!?

omg, i get it now

thnanks
6. (Original post by madfish)
how is it equal to b,2a ?!?

omg, i get it now

thnanks
np
7. (Original post by madfish)
Im sorry but I dont get what you mean :|

2a-4 / 2 = a-2 not 2a? surly?
You are given 2 information:
2 points - what you do is to find the midpoint, its true that when you divide 2a-4 by 2 you get a-2
but you know that the midpoint is a circle centre so 2a-4/2=2a
since you are given the coordinates of a circle centre

Are you blonde?
8. (Original post by purplemind)
Are you blonde?
that was cruel
9. (Original post by davros)
that was cruel
No, it was just a subtle allusion. I'm very nice.
10. (Original post by purplemind)
No, it was just a subtle allusion. I'm very nice.
I'm sure you are

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