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F334 (19/06/2013 9:00AM) - Salters Chemistry (Chemistry of Materials) Revision Thread Watch

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    (Original post by suncake)
    Alright, I'll do it later this evening. You'll have to ignore my scribblings

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    Thank you! And if I can remember, didn't you get an A? I'm sure your scribblings will be useful then
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    (Original post by abzy1234)
    Thank you! And if I can remember, didn't you get an A? I'm sure your scribblings will be useful then
    https://docs.google.com/file/d/1sdHM...it?usp=sharing

    Here you go. Yeah, ignore the incorrect scribbles then And excuse my awful scanning skills :lol:
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    (Original post by suncake)
    https://docs.google.com/file/d/1sdHM...it?usp=sharing

    Here you go. Yeah, ignore the incorrect scribbles then And excuse my awful scanning skills :lol:
    Thank you so much! You did so well in that paper (even got the rate of disappearance!)

    I can't believe I messed up; looking back at that paper, I'm beginning to think OCR were justified in hiking the grade boundaries

    Cheers again!
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    (Original post by abzy1234)
    Thank you so much! You did so well in that paper (even got the rate of disappearance!)

    I can't believe I messed up; looking back at that paper, I'm beginning to think OCR were justified in hiking the grade boundaries

    Cheers again!
    No bother, and thanks Can't believe I forgot the bloody units, as you can see by my angry underlining :mad: :lol:

    It always seems easier in retrospect though... I still think it was a difficult paper compared to previous years. At least now you've already had a go, so you'll most likely do better
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    (Original post by suncake)
    No bother, and thanks Can't believe I forgot the bloody units, as you can see by my angry underlining :mad: :lol:

    It always seems easier in retrospect though... I still think it was a difficult paper compared to previous years. At least now you've already had a go, so you'll most likely do better
    Aha, how did you work it out? I still have no clue -_-

    That's so true! The question on electrode potentials was perhaps the hardest question; honestly, I think it's the exam pressure that gets to most, especially with salters chemistry!

    Yah hopefully! I think as I'm doing unit 2 and 5 now, so am literally induated with chemistry (fml), it should hopefully boost my knowledge.

    How are you finding unit 5?

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    (Original post by abzy1234)
    Aha, how did you work it out? I still have no clue -_-

    That's so true! The question on electrode potentials was perhaps the hardest question; honestly, I think it's the exam pressure that gets to most, especially with salters chemistry!

    Yah hopefully! I think as I'm doing unit 2 and 5 now, so am literally induated with chemistry (fml), it should hopefully boost my knowledge.

    How are you finding unit 5?

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    I looked at it again yesterday, and I'm not entirely sure myself! I think it's because there were two moles of I- in the equation, so it would be used up at double the rate... Or something...

    Yeah I agree, well, it was probably alright if you understood it, but I never really learnt that topic properly in the first place Exam pressure's a ***** haha.

    Ooh that's a lotta chemistry, fun times :mmm: It's not too bad I guess, just loads of reaction mechanisms and equations etc. to remember! And the fact that the paper is mainly synoptic is pretty scary!

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    (Original post by suncake)
    I looked at it again yesterday, and I'm not entirely sure myself! I think it's because there were two moles of I- in the equation, so it would be used up at double the rate... Or something...

    Yeah I agree, well, it was probably alright if you understood it, but I never really learnt that topic properly in the first place Exam pressure's a ***** haha.

    Ooh that's a lotta chemistry, fun times :mmm: It's not too bad I guess, just loads of reaction mechanisms and equations etc. to remember! And the fact that the paper is mainly synoptic is pretty scary!

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    That's sorta makes sense! My teachers still have no clue -_-

    Yup, especially now, as it's the final throw of the dice tbh! I see you've insured Leicester, I've also insured it too!

    I'm literally counting down the days when I don't have to do no more chemistry! Gosh that seems so far away

    I am petrified for that paper, seriously! It's more or less 100% synoptic, giving them the license to ask whatever they want! Oh well, best just to prepare fully and be ready for the worst
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    has anyone done question 5aii on june 2010 paper and understand it? can u please help.. its a calculation question
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    (Original post by tsr1)
    has anyone done question 5aii on june 2010 paper and understand it? can u please help.. its a calculation question
    The electrode one? You just do the more positive electrode minus the more negative one, so 0.80-0.34 = 0.46
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    (Original post by tsr1)
    has anyone done question 5aii on june 2010 paper and understand it? can u please help.. its a calculation question
    We were always taught to do this as the more positive Ecell value minus the less positive value, so higher value - lower
    They say the copper and silver electrodes, so we are looking at the values for the Cu and Ag half reactions
    (+0.80) - (+0.34) = 0.46
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    (Original post by Kreayshawn)
    We were always taught to do this as the more positive Ecell value minus the less positive value, so higher value - lower
    They say the copper and silver electrodes, so we are looking at the values for the Cu and Ag half reactions
    (+0.80) - (+0.34) = 0.46
    (Original post by super121)
    The electrode one? You just do the more positive electrode minus the more negative one, so 0.80-0.34 = 0.46
    sorry... there seems to be confusion, its the one with dilution factor, I have checked the paper twice but it is june 2010 and question 5aii
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    (Original post by tsr1)
    sorry... there seems to be confusion, its the one with dilution factor, I have checked the paper twice but it is june 2010 and question 5aii
    Lol, I thought this was too easy :P
    What's the question asking?

    This is June 2010 http://www.ocr.org.uk/Images/65142-q...-materials.pdf
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    A solution of hydrogen peroxide s diluted by factor 10. 10.cm3 of this diluted H2O2 reacted with exactly 18.2cm3 of 0.0200 dm-3Mno-2 solution. The equation for the reaction is: 2 MnO4- + 6H + 5 H2O2 ---> 2Mn2+ 8H2O + 5O2... calculate the concentration of undiluted H2O2 solution....... also sorry tsr doest allow me to put spaces?!?!
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    (Original post by super121)
    Lol, I thought this was too easy :P
    What's the question asking?

    This is June 2010 http://www.ocr.org.uk/Images/65142-q...-materials.pdf
    hey sorry.. it was JAN 2010 paper.. but the question is below:
    A solution of hydrogen peroxide s diluted by factor 10. 10.cm3 of this diluted H2O2 reacted with exactly 18.2cm3 of 0.0200 dm-3Mno-2 solution. The equation for the reaction is: 2 MnO4- + 6H + 5 H2O2 ---> 2Mn2+ 8H2O + 5O2... calculate the concentration of undiluted H2O2 solution
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    (Original post by tsr1)
    hey sorry.. it was JAN 2010 paper.. but the question is below:
    A solution of hydrogen peroxide s diluted by factor 10. 10.cm3 of this diluted H2O2 reacted with exactly 18.2cm3 of 0.0200 dm-3Mno-2 solution. The equation for the reaction is: 2 MnO4- + 6H + 5 H2O2 ---> 2Mn2+ 8H2O + 5O2... calculate the concentration of undiluted H2O2 solution
    This paper? http://www.ocr.org.uk/Images/65140-q...-materials.pdf
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    the question seems to be on none of them but I was doing it and I have it printed on me..
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    (Original post by tsr1)
    the question seems to be on none of them but I was doing it and I have it printed on me..
    The specimen paper possibly?


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    (Original post by super121)
    The specimen paper possibly?


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    I guess its one of those legacy papers.. lol no wonder why I have 3 of 2010 papers :P attached
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  1. File Type: pdf Question_paper_2849-01.pdf (189.5 KB, 890 views)
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    (Original post by tsr1)
    A solution of hydrogen peroxide s diluted by factor 10. 10.cm3 of this diluted H2O2 reacted with exactly 18.2cm3 of 0.0200 dm-3Mno-2 solution. The equation for the reaction is: 2 MnO4- + 6H + 5 H2O2 ---> 2Mn2+ 8H2O + 5O2... calculate the concentration of undiluted H2O2 solution....... also sorry tsr doest allow me to put spaces?!?!
    18.2cm^3=0.0182dm^3
    0.0182*0.02=3.6*10^-4 moles of MnO4 (vol*conc=moles)
    3.6*10^-4*(5/2)=9*10^-4 (moles of H2O2 from the equation)
    That number of H2O2 is in 10cm^3, which is 0.01dm^3, giving a concentration of 0.09moles/dm^3, but the solution has been diluted by 10, meaning the original concentration 0.9mol/dm^3.

    Hope this helps!
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    (Original post by suncake)
    https://docs.google.com/file/d/1sdHM...it?usp=sharing

    Here you go. Yeah, ignore the incorrect scribbles then And excuse my awful scanning skills :lol:
    You must have got like 90% ums on that?
 
 
 
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