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    (Original post by MAyman12)
    So how are we going to use this in finding R1,R2 by radial resolution?

    I'm really sorry. I'm sleep deprived and not thinking straight.
    Look at the given solution.

    For each of the points, B1, B2, we have an equation relation loss in GPE to gain in KE.

    So we have the velocity at each of the two points.

    Then resolving radially at each of the points, taking into account motion in a circle you arrive at the next two equations in the given solution.
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    (Original post by ghostwalker)
    Look at the given solution.

    For each of the points, B1, B2, we have an equation relation loss in GPE to gain in KE.

    So we have the velocity at each of the two points.

    Then resolving radially at each of the points, taking into account motion in a circle you arrive at the next two equations in the given solution.
    Thank you Do you mind if I asked you any more questions in the future in this thread?

    Can you please explain the second part of this question?
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    (Original post by MAyman12)
    Thank you Do you mind if I asked you any more questions in the future in this thread?
    I don't usually look at long running threads with multiple questions.

    However, as you've asked, I look at this extra question.

    Can you please explain the second part of this question?
    The entire shape is being suspended from a horizontal axis through C to give you a pendulum.
    You need to use rate of change of angular momentum = sum of moments of forces.

    Then for small angles you proceed as per the standard derivation for a simple pendulum, which you should have covered.

    And comparing your equation with the standard SHM equation you can work out what \lambda is.
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    (Original post by ghostwalker)
    I don't usually look at long running threads with multiple questions.

    However, as you've asked, I look at this extra question.



    The entire shape is being suspended from a horizontal axis through C to give you a pendulum.
    You need to use rate of change of angular momentum = sum of moments of forces.

    Then for small angles you proceed as per the standard derivation for a simple pendulum, which you should have covered.

    And comparing your equation with the standard SHM equation you can work out what \lambda is.

    I got it now. Thank you for your help.
 
 
 
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