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    (Original post by Aph)
    Why does it scare you??

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    It doesn't scare me!

    However, some people are scared of basic arithmetic
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    Some people spend half their time scared of fractions.

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    Well, I say half their time...
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    (Original post by FireGarden)
    This limit is not good enough. You can of course have a number to the power of a different number, and to take that into account, you need to approach 0^0 from any possibility; therefore we must consider x^y. Now I agree, \lim_{x\to 0}(x^x)=1, but that is only one case of the required limit (along the line y=x towards the origin).

    Consider the limits \lim_{x\to 0}(x^0)=1; and \lim_{x\to 0}(0^x)=0. These limits are clearly not equal, hence there is no unique, sensible value for 0^0.
    Ah i see what you're getting at. Limit does not exist then as different approaches dont give the same limit.

    I remember reading it was an indeterminate form anyway...must have eluded me lol
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    omg what even is maths
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    (Original post by lerjj)
    Some people spend half their time scared of fractions.

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    Well, I say half their time...
    What about the other 2/3 of their time?
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    It's a weird one because it is technically undefined, but also very useful to set 0^0=1 for notation purposes when writing down polynomials is general summation form.
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    (Original post by james22)
    It's a weird one because it is technically undefined, but also very useful to set 0^0=1 for notation purposes when writing down polynomials is general summation form.
    Is there a variable x missing from the maths in your signature - what is the sum meant to be a continuous function of?
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    (Original post by RichE)
    Is there a variable x missing from the maths in your signature - what is the sum meant to be a continuous function of?
    Yes, thanks for pointing that out.
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    (Original post by FireGarden)
    Not as simple as you think. If 0^0 exists then \lim_{x\to 0}(\lim_{y\to 0}(x^y)) = \lim_{y\to 0}(\lim_{x\to 0}(x^y)) . This is obviously not true for all paths to (0,0) in \mathbb{R}^2.
    B-B-But Google says it's 1. Google's never wrong!
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    (Original post by Dilzo999)
    B-B-But Google says it's 1. Google's never wrong!
    https://www.google.co.uk/#q=99999999...99999999999998


    Where's your God now?!?
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    Uhh, well, hmm... You know those easter eggs that Google tend to put it? It must be one of those. Nice spot.
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    (Original post by Dilzo999)
    Uhh, well, hmm... You know those easter eggs that Google tend to put it? It must be one of those. Nice spot.
    It was discussed on the google forums and judging from the replies of Google employees, it is not an intentional easter egg.
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    (Original post by Aph)
    Why does it scare you??

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    because it looks like eggman off sonic the hedgehog.
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    (Original post by DJMayes)
    It was discussed on the google forums and judging from the replies of Google employees, it is not an intentional easter egg.
    Yeah I was just joking, apparently it's to do with the coding of the google calc. It also answers dividing by 0 with infinity.
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    I suppose it may scare people because they are 'taught' (rather told to remember) that anything to the power 0 equals 1, but 0 to the power anything equals 0 and 0^0 is where it breaks down
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    (Original post by newblood)
    We can easily show the limit of x^x as x approaches 0 is 1.

    So why has it scared you?
    But  \displaystyle\lim_{x \to 0} 0^x =0

    Conclusion: maths is wrong . Let's all do geography instead.


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    (Original post by LightBlueSoldier)
    But  \displaystyle\lim_{x \to 0} 0^x =0

    Conclusion: maths is wrong . Let's all do geography instead.


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    I only have enough money for a pen (hence i study maths). If you buy the colouring pencils, im all yours
 
 
 
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