You are Here: Home >< Maths

# Edexcel C12 math January 2015 watch

1. im not sure
2. Guys on a scale of 1-10, how hard was the exam?

Posted from TSR Mobile
3. (Original post by davidvicto)
Guys on a scale of 1-10, how hard was the exam?

Posted from TSR Mobile
5 or 6, hahaha
4. What was the answer of the question that asks about the year when something increases over 1 million? Which year was it?
5. (Original post by davidvicto)
Guys on a scale of 1-10, how hard was the exam?

Posted from TSR Mobile
6. (Original post by davidvicto)
Guys on a scale of 1-10, how hard was the exam?

Posted from TSR Mobile
7 or 6
7. It was a little above average , not hard though, and time was great
8. Farah it was year 2030
9. What was the answer to the sequences question of:
u1=k

and u4=15

find K
10. (Original post by anujsr)
What was the answer to the sequences question of:
u1=k

and u4=15

find K

I got k=3
11. (Original post by Farah4298)
What was the answer of the question that asks about the year when something increases over 1 million? Which year was it?
The right answer is year 2029, since N is 14 years and you count in year 2016 as number 1 2016+13 years = 2029

The year 2030 is an expected mistake many students fall for it, there were many similar questions in the past papers
12. No the answer is 2029 since you add 14 years year 2016 was the first year
13. (Original post by faisalss96)
The right answer is year 2029, since N is 14 years and you count in year 2016 as number 1 2016+13 years = 2029

The year 2030 is an expected mistake many students fall for it, there were many similar questions in the past papers
I'm not quite sure you're right. Firstly, you can't count 2016 for this part of the question (but when finding the sum in the next part you use n=11 counting 2016). I'm saying this because the value 275000 increases by a ratio of 1.1 starting from 2017.

Illustrating this fact:
2017 - 275000 * 1.1
2018 - 275000 * 1.1^2
2019 - 275000 * 1.1^3
2020 - 275000 * 1.1^4
2021 - 275000 * 1.1^5
2022 - 275000 * 1.1^6
2023 - 275000 * 1.1^7

2024 - 275000 * 1.1^8
2025 - 275000 * 1.1^9
2026 - 275000 * 1.1^10
2027 - 275000 * 1.1^11
2028 - 275000 * 1.1^12
2029 - 275000 * 1.1^13
2030 - 275000 * 1.1^14

As you see in 2030, 275000 increases by a factor of 1.1^14 and it is the first year when the value becomes > 1000000.

Correct me if I'm wrong
14. (Original post by faisalss96)
The right answer is year 2029, since N is 14 years and you count in year 2016 as number 1 2016+13 years = 2029

The year 2030 is an expected mistake many students fall for it, there were many similar questions in the past papers
Look at my attachment. The question is the same as the one in the exam yesterday.
Attached Images

15. how do you think u guys did on this paper?!? i found it very difficult. Even harder compared to last may/june paper. By the way, did u guys skip any questions? i hope they lower the grade boundary significantly....
16. For me the paper was relatively easy if not slightly challenging. To be honest, May 2014 paper remains the hardest Edexcel math past-paper I've done. I feel that yesterday's exam was on par with the Jan 2014 C12 paper in terms of difficulty.

Initially I felt like I wouldn't be able to complete the paper, but in the end I completed it and managed to check my answers as well I think an 'A' will require between 90 and 100 marks out of 125. But that's just my opinion.
17. Did anyone get the unofficial mark scheme?
18. If one of you remembers all of the questions (likely not :P) post them on this thread and I can make an unofficial mark scheme.
I'm not quite sure you're right. Firstly, you can't count 2016 for this part of the question (but when finding the sum in the next part you use n=11 counting 2016). I'm saying this because the value 275000 increases by a ratio of 1.1 starting from 2017.

Illustrating this fact:
2017 - 275000 * 1.1
2018 - 275000 * 1.1^2
2019 - 275000 * 1.1^3
2020 - 275000 * 1.1^4
2021 - 275000 * 1.1^5
2022 - 275000 * 1.1^6
2023 - 275000 * 1.1^7

2024 - 275000 * 1.1^8
2025 - 275000 * 1.1^9
2026 - 275000 * 1.1^10
2027 - 275000 * 1.1^11
2028 - 275000 * 1.1^12
2029 - 275000 * 1.1^13
2030 - 275000 * 1.1^14

As you see in 2030, 275000 increases by a factor of 1.1^14 and it is the first year when the value becomes > 1000000.

Correct me if I'm wrong
You are right as 2016 has common ratio of power zero so it is 2030

in the kite question did anyone get the angle 0.48sth in radians , and kite area of 48.sth
20. (Original post by Hshraideh)
You are right as 2016 has common ratio of power zero so it is 2030

in the kite question did anyone get the angle 0.48sth in radians , and kite area of 48.sth
Yes the area of the kite was around 48 to 49. Can't entirely remember, but I think this was my calculation :

2(0.5*10*12*sin0.421) = 49 cm^2

TSR Support Team

We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

This forum is supported by:
Updated: June 19, 2015
Today on TSR

### Three reasons you may feel demotivated right now

...and how to stay positive

### Can I get A*s if I start revising now?

Discussions on TSR

• Latest
Poll
Useful resources

Can you help? Study help unanswered threadsStudy Help rules and posting guidelinesLaTex guide for writing equations on TSR

## Groups associated with this forum:

View associated groups
Discussions on TSR

• Latest

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE