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    (Original post by physicsmaths)
    Yes but u couldve just done -2x-3/4=3/2 so a^3/2 but yh thats aroota.


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    Cool, so what is the final answer of the whole question?
    2 root 2, a root a?
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    (Original post by Chittesh14)
    Cool, so what is the final answer of the whole question?
    2 root 2, a root a?
    Yep i think so.


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    (Original post by physicsmaths)
    Yep i think so.


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    Thanks, so my brother was correct! He was just partly confused as i misguided him lol. He got 2 root 2, a root a aswell. Also, I will ask him this too and I want to ask you aswell if you don't mind, why does the a have to be calculated seperately. Why can't we just do 1/1/4a^-2 = 4a^2 and then work out from there (4a^2)^3/4.

    Why do you have to work them out both seperately?
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    (Original post by Chittesh14)
    Thanks, so my brother was correct! He was just partly confused as i misguided him lol. He got 2 root 2, a root a aswell. Also, I will ask him this too and I want to ask you aswell if you don't mind, why does the a have to be calculated seperately. Why can't we just do 1/1/4a^-2 = 4a^2 and then work out from there (4a^2)^3/4.

    Why do you have to work them out both seperately?
    Well each has to be calculated but I only separated the number out to demonstrate the invalidity of your 16
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    (Original post by TenOfThem)
    Well each has to be calculated but I only separated the number out to demonstrate the invalidity of your 16
    Oh right. So usually you should seperate out the number and the term to work out the real answer, or you could be misunderstood and come up with a different answer.
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    (Original post by Chittesh14)
    Thanks, so my brother was correct! He was just partly confused as i misguided him lol. He got 2 root 2, a root a aswell. Also, I will ask him this too and I want to ask you aswell if you don't mind, why does the a have to be calculated seperately. Why can't we just do 1/1/4a^-2 = 4a^2 and then work out from there (4a^2)^3/4.

    Why do you have to work them out both seperately?
    You dont. You can just do it together.


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    (Original post by physicsmaths)
    You dont. You can just do it together.


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    I don't understand, if you do it all together, how will it work out. That is basically doing 1/4(1/a^2) = 1/4a^2.
    If you then do (1/4a^2)^-3/4 it becomes 1/1/4a^2 = 1/4a^2
    (1/4a^2)^3/4 = fourth root of (1/4a^2) = root a / root 2
    if u cube it then a root a / 2 root 2 or other way round. wow ur excellent dude thanks .
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    (Original post by Chittesh14)
    I don't understand, if you do it all together, how will it work out. That is basically doing 1/4(1/a^2) = 1/4a^2.
    If you then do (1/4a^2)^-3/4 it becomes 1/1/4a^2 = 1/4a^2
    (1/4a^2)^3/4 = fourth root of (1/4a^2) = root a / root 2
    if u cube it then a root a / 2 root 2 or other way round. wow ur excellent dude thanks .
    Have you done C1?


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    (Original post by physicsmaths)
    Have you done C1?


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    Nope, I'm gcse, year 10.


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