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# Find roots of polynomial of degree 7 watch

1. (Original post by Mihael_Keehl)
I was talking in general for a polynomial with a high degree, not in this particular case, sorry ifI was vague
in general, no

these are not complex conjugates
2. (Original post by TeeEm)
in general, no

these are not complex conjugates
I see thanks.
3. (Original post by B_9710)
I do have the answers. With the general solution being x=tan(nπ/7 + π/28)
So, here's my solution given the hint above:

Spoiler:
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Observe that if , then and so . Since tan(arg(x+iy)) = y / x we can deduce Im((1+it)^7) / Re(1+it)^7 =
That is,
Comparing with our original equation we see we need , so and so as desired.

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Updated: October 26, 2015
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