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    (Original post by Jyashi)
    Relax buddy. I just added that line because I didn't want to seem disrespectful.

    And feeding this in a scientific calculator does not give the right results even after triple checking. And I would encourage everyone who is reading to try it out and report back here so mine is not a fluke.
    Just tried it with a scientific calculator, works fine - if it's not working for you after three tries, you may want to re-evaluate whether you know how to use a scientific calculator properly and take the necessary measures to learn how to do so.
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    (Original post by Zacken)
    Just tried it with a scientific calculator, works fine - if it's not working for you after three tries, you may want to re-evaluate whether you know how to use a scientific calculator properly and take the necessary measures to learn how to do so.
    Guessed at the syntax to get Wolfram Alpha to verify and got it right first time. It's nice to be able to quickly post a link that settles the argument so definitively...
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    (Original post by DFranklin)
    Guessed at the syntax to get Wolfram Alpha to verify and got it right first time. It's nice to be able to quickly post a link that settles the argument so definitively...
    Pretty satisfying, I imagine.
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    (Original post by DFranklin)
    If you start from

    a_n = 2 \times 2^{n/2} (which is correct for even n), and then look at what happens for odd n, you find you need to replace the first 2 with \frac{3}{\sqrt{2}} to get it to work for odd n.

    That is, you need to add \frac{3}{\sqrt{2}} - 2 to the first 2 when n is odd.

    Then I just used that \frac{1}{2}(1-(-1)^n) is 0 for n even and 1 for n odd.

    [And if you were wondering - part of the point of doing this was to illustrate that sometimes asking for a single formula is not the most sensible thing to do...]
    If possible could you also kindly tell how you got to know that 3 / sq 2 - 2 can be used instead of 2 for finding the odd numbers? Thank you
 
 
 
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