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# AQA M1 Mechanics 1B kinematics in one dimension question watch

1. (Original post by Marxist)
You should have two of the same displacements for the time T, you set them equal to each other to get V in terms of T, which is $V=3/2T$ and then sub in to the two equations. Adding them together you get the quadratic

$T^2-60T+416=0$

therefore

$T=8$ once we've solved the equation(the other value of T is discarded, of course).
Right
2. (Original post by Sayless)
I'm stuck on the following question 19a)

I have to find how long the car is accelerating for however I have two unknowns whenever I try make a suvat equation, I only know
a = 1.5
u = 0
I don't know anything else for that time interval
The distance i'm giving is overall, not that for time period, and the time is overall also which doesn't help, how can I answer this question?
First apply first equation of motion v=u+at then let u=0
then t=T
u will get aT=1.5 ......(i)
from second equation s=ut+1/2at^2
s=312,t=30s
312=30a/2
a=21m/s^2
then (i)....aT=1.5
21T=1.5
therefore T=0.07s

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Updated: November 12, 2015
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