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# m1 help :( Watch

1. (Original post by kiiten)
So just use values of t like 1, 2 etc.

Yes, it says velocity when the stone hits the ground. If you use suvat why would s=-2 dont you have to account for the distance from when its thrown up?
If you want you can just consider it from when its first thrown, and therefore s=-2
2. so uyou're assuming that the displacement when the stone is thrown is 0m below that 0m where it was thrown is a displacement of -2m and above 0m is a distance of 3m which the stone travelled before reaching it's maximum height?
3. (Original post by Zacken)
s is displacement not distance. If you got up x amounts and go down x+2 amounts then your displacement is -2.
Ahh of course, i forget that s is displacement and not distance

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4. Thanks for all your help everyone

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5. (Original post by kiiten)
Ahh of course, i forget that s is displacement and not distance

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(Original post by kiiten)
Thanks for all your help everyone

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6. I plugged in values to plot the graph and got

5i+10.5j
10i+5j
15i-10.5j
20i-36j

Etc. but its different to the graph in the book?
7. (Original post by kiiten)
I plugged in values to plot the graph and got

5i+10.5j
10i+5j
15i-10.5j
20i-36j

Etc. but its different to the graph in the book?
In this case - you're plotting x v/s y not (x+y) v/s t.
8. i got tagged here? ????
9. (Original post by Zacken)
In this case - you're plotting x v/s y not (x+y) v/s t.
Thats how i plotted it with i on x axis and j on y axis but my graph is different
10. (Original post by thefatone)
i got tagged here? ????
Sorry i tagged then untagged you - i forgot that you havent done i and j vectors yet
11. oh yea that's fine.
12. (Original post by kiiten)
Thats how i plotted it with i on x axis and j on y axis but my graph is different
Can you take a picture and show us your working out for each point?
13. (Original post by Zacken)
Can you take a picture and show us your working out for each point?
Oh I used a calc. I just subbed t= 1, 2, 3, 4 and 5 into
R = 5ti + (6+9.5t - 5t^2) j
14. (Original post by kiiten)
Oh I used a calc. I just subbed t= 1, 2, 3, 4 and 5 into
R = 5ti + (6+9.5t - 5t^2) j
That should be correct, can you see that if you plug in t =0, you get the point 0i + 6j which is (0,6) on the graph? As shown in the picture, etc...?
15. (Original post by Zacken)
That should be correct, can you see that if you plug in t =0, you get the point 0i + 6j which is (0,6) on the graph? As shown in the picture, etc...?
Yeah, but i dont understand why they used random values for i like 9.5, 10 and 12 whereas i got 5, 10, 15 etc.
16. (Original post by kiiten)
Yeah, but i dont understand why they used random values for i like 9.5, 10 and 12 whereas i got 5, 10, 15 etc.
They used 5, 10 as well. It's fine.
17. (Original post by Zacken)
They used 5, 10 as well. It's fine.
Right, thanks

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