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    (Original post by kiiten)
    So just use values of t like 1, 2 etc.

    Yes, it says velocity when the stone hits the ground. If you use suvat why would s=-2 dont you have to account for the distance from when its thrown up?
    If you want you can just consider it from when its first thrown, and therefore s=-2
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    so uyou're assuming that the displacement when the stone is thrown is 0m below that 0m where it was thrown is a displacement of -2m and above 0m is a distance of 3m which the stone travelled before reaching it's maximum height?
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    (Original post by Zacken)
    s is displacement not distance. If you got up x amounts and go down x+2 amounts then your displacement is -2.
    Ahh of course, i forget that s is displacement and not distance

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    Thanks for all your help everyone

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    (Original post by kiiten)
    Ahh of course, i forget that s is displacement and not distance

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    (Original post by kiiten)
    Thanks for all your help everyone

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    De nada.
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    Name:  image.jpg
Views: 32
Size:  319.4 KBI plugged in values to plot the graph and got

    5i+10.5j
    10i+5j
    15i-10.5j
    20i-36j

    Etc. but its different to the graph in the book?
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    (Original post by kiiten)
    Name:  image.jpg
Views: 32
Size:  319.4 KBI plugged in values to plot the graph and got

    5i+10.5j
    10i+5j
    15i-10.5j
    20i-36j

    Etc. but its different to the graph in the book?
    In this case - you're plotting x v/s y not (x+y) v/s t.
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    i got tagged here? ????
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    (Original post by Zacken)
    In this case - you're plotting x v/s y not (x+y) v/s t.
    Thats how i plotted it with i on x axis and j on y axis but my graph is different
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    (Original post by thefatone)
    i got tagged here? ????
    Sorry i tagged then untagged you - i forgot that you havent done i and j vectors yet
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    oh yea that's fine.
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    (Original post by kiiten)
    Thats how i plotted it with i on x axis and j on y axis but my graph is different
    Can you take a picture and show us your working out for each point?
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    (Original post by Zacken)
    Can you take a picture and show us your working out for each point?
    Oh I used a calc. I just subbed t= 1, 2, 3, 4 and 5 into
    R = 5ti + (6+9.5t - 5t^2) j
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    (Original post by kiiten)
    Oh I used a calc. I just subbed t= 1, 2, 3, 4 and 5 into
    R = 5ti + (6+9.5t - 5t^2) j
    That should be correct, can you see that if you plug in t =0, you get the point 0i + 6j which is (0,6) on the graph? As shown in the picture, etc...?
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    (Original post by Zacken)
    That should be correct, can you see that if you plug in t =0, you get the point 0i + 6j which is (0,6) on the graph? As shown in the picture, etc...?
    Yeah, but i dont understand why they used random values for i like 9.5, 10 and 12 whereas i got 5, 10, 15 etc.
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    (Original post by kiiten)
    Yeah, but i dont understand why they used random values for i like 9.5, 10 and 12 whereas i got 5, 10, 15 etc.
    They used 5, 10 as well. It's fine.
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    (Original post by Zacken)
    They used 5, 10 as well. It's fine.
    Right, thanks
 
 
 
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