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How to find constants of quadratic equation given the coordinates. watch

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    (Original post by Jyashi)
    Yes i do.
    Lol feel like im getting married.
    Now multiply both sides by 2x, what do you get?

    :rofl: :rofl:
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    (Original post by Zacken)
    Now multiply both sides by 2x, what do you get?

    :rofl: :rofl:
    AAAAAAAAAHHHHHHHHH......

    5 million years later

    hhhhhhhhh.
    I get as you said .
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    (Original post by Jyashi)
    AAAAAAAAAHHHHHHHHH......

    5 million years later

    hhhhhhhhh.
    I get as you said .
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    You're missing the \frac{dy}{dx}, but I think you've gotten it.

    To recap:

    \displaystyle \frac{dy}{dx} = \frac{1}{2\sqrt{x}} \Rightarrow 2x \frac{dy}{dx} = \frac{2x}{2\sqrt{x}} \Rightarrow 2x \frac{dy}{dx} = \sqrt{x} \Rightarrow 2x\frac{dy}{dx} = y
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    (Original post by Zacken)
    You're missing the \frac{dy}{dx}, but I think you've gotten it.

    To recap:

    \displaystyle \frac{dy}{dx} = \frac{1}{2\sqrt{x}} \Rightarrow 2x \frac{dy}{dx} = \frac{2x}{2\sqrt{x}} \Rightarrow 2x \frac{dy}{dx} = \sqrt{x} \Rightarrow 2x\frac{dy}{dx} = y
    Yes that explains it perfectly. Sometimes you just need some Zacken in your head to see things more clearly.
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    (Original post by Jyashi)
    Yes that explains it perfectly. Sometimes you just need some Zacken in your head to see things more clearly.
    Awesome, I'm off to bed now - see you around. :-)
 
 
 
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