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    (Original post by daniellon)
    Cosine rule in the formula booklet?
    Yep
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    What was the tension before P was released?
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    (Original post by daniellon)
    What was the tension before P was released?
    O.2g = 1.96?
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    My answers:
    Distance: 10, time 1.43
    a=6.8
    3, 1.25
    82.7
    82.8
    0.918, 48.6
    6
    3.75
    4.75
    12, 16.3
    2.06 (east)
    1.96, 1.81
    3.64
    1.96?
    10
    3, 25 (as shown)
    6.76
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    (Original post by Furthermaths100)
    My answers:
    Distance: 10, time 1.43
    a=6.8
    3, 1.25
    82.7
    82.8
    0.918, 48.6
    6
    3.75
    4.75
    12, 16.3
    2.06 (east)
    1.96, 1.81
    3.64
    1.96?
    10
    3, 25 (as shown)
    6.76
    Please could you help by putting these into the community MS?
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    (Original post by Furthermaths100)
    My answers:
    Distance: 10, time 1.43
    a=6.8
    3, 1.25
    82.7
    82.8
    0.918, 48.6
    6
    3.75
    4.75
    12, 16.3
    2.06 (east)
    1.96, 1.81
    3.64
    1.96?
    10
    3, 25 (as shown)
    6.76
    I got 2.37 instead of 1.96
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    (Original post by Parallex)
    Ahh, fair enough. Looks like I pictured the resultant force wrongly...
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    (Original post by Parallex)
    your cosine rule is wrong. it's a^2 + b^2 - c^2 not (a^2 - b^2 - c^2)
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    (Original post by physicskid123)
    your cosine rule is wrong. it's a^2 + b^2 - c^2 not (a^2 - b^2 - c^2)
    It isn't wrong..
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    (Original post by Parallex)
    It isn't wrong..
    it is
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    For question 5 I said the direction is to the right. Can I get away with it
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    your cosine rule is wrong. it's a^2 + b^2 - c^2 not (a^2 - b^2 - c^2)

    - You're a moron.
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    any grade boundary predictions?
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    What are people predicting for grade boundaries?
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    look it's cos a = (4^2 + 4^2 - 6^2) / 2*4*4 so cos a = -.125 and so a is 97.18
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    (Original post by Parallex)
    That equation isn't correct.

    You did b^2 + c^2 - a^2/ -2bc but there shouldn't be a minus
    It should be just 2bc
    Posted from TSR Mobile
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    (Original post by daniellon)
    For question 5 I said the direction is to the right. Can I get away with it
    I did too
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    What was the total mark for the question with the 2 4N forces because I got that whole bit wrong
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    Just a quick question for question 4 part iii. In the unofficial mark scheme it mentioned that it had already been verified. However in the question it said that after B collides with CD that there are no more collisions after this point. This means that surely B can not have a velocity of zero as A would then collide with B. Therefore shouldn't the velocity of B be at least greater than 4ms^-1 (which was the previous speed of A).
 
 
 
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