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    (Original post by Zacken)
    Sorry! At least now you know.
    Would've been nice to know for the exams I sat last year :rofl:

    Thanks anyway
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    (Original post by Andy98)
    Would've been nice to know for the exams I sat last year :rofl:

    Thanks anyway
    You must've done well anyway!

    No problem.
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    (Original post by Zacken)
    If x=1 then you end up with a division by 0.
    Sorry to bring this up again, but what do you mean if X is less than/equal to 1 it will end in a division by 0? I don't get why you would be dividiving by 0.
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    (Original post by Questioness)
    Sorry to bring this up again, but what do you mean if X is less than/equal to 1 it will end in a division by 0? I don't get why you would be dividiving by 0.
    You are right in stating that x \leq 1, buuut we can't have x=1 since if that was allowed then we'd be doing \frac{x-4}{x-1} = \frac{1-4}{1-1} = \frac{-3}{0} but we can'd divide by 0\, so our inequality should be

    x \leq 1 AND x \neq 1. But we can just simplify that as x < 1.
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    (Original post by Zacken)
    You must've done well anyway!

    No problem.
    Well, I'm resitting C1&4 and S1

    (Original post by Questioness)
    Sorry to bring this up again, but what do you mean if X is less than/equal to 1 it will end in a division by 0? I don't get why you would be dividiving by 0.
    \frac{x-4}{x-1}, when you use 1 it becomes \frac{1-4}{1-1}=\frac{-3}{0} which is bad :yep:
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    (Original post by Zacken)
    You are right in stating that x \leq 1, buuut we can't have x=1 since if that was allowed then we'd be doing \frac{x-4}{x-1} = \frac{1-4}{1-1} = \frac{-3}{0} but we can'd divide by 0\, so our inequality should be

    x \leq 1 AND x \neq 1. But we can just simplify that as x < 1.
    Ok, makes sense. Thanks again .
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    (Original post by Andy98)
    Well, I'm resitting C1&4 and S1
    Good luck! The maths forum is here if you've got any queries.

    \frac{x-4}{x-1}, when you use 1 it becomes \frac{1-4}{1-1}=\frac{-3}{0} which is bad :yep:
    Slowcoach.
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    You Get a rep Anyways. Sorry Zacken, I've already repped you
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    (Original post by Questioness)
    You Get a rep Anyways. Sorry Zacken, I've already repped you
    Don't worry about it!
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    I'm not done . Why is it that X can be equal to 4? That would also make 0 . Not likin' the double standards here.
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    (Original post by Questioness)
    I'm not done . Why is it that X can be equal to 4? That would also make 0 . Not likin' the double standards here.
    It's not a strict inequality, so \frac{x-4}{x-1} = \frac{4-4}{4-1} = 0 \leq 0 which is true. 0 is less than or equal to 0.

    You can do this on your calculator, it's all perfectly legit. But try dividing by 0 on your calculator, what happens?

    Moral of the story: 0 in the numerator is okay. 0 in the denominator is bad news.
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    (Original post by Zacken)
    It's not a strict inequality, so \frac{x-4}{x-1} = \frac{4-4}{4-1} = 0 \leq 0 which is true. 0 is less than or equal to 0.

    You can do this on your calculator, it's all perfectly legit. But try dividing by 0 on your calculator, what happens?
    Right- an error. Okay I get it.Thanks.
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    (Original post by Questioness)
    Right- an error. Okay I get it.Thanks.
    No problem!
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    (Original post by Zacken)
    Good luck! The maths forum is here if you've got any queries.



    Slowcoach.
    I'm not one to spam


    Ssshhh, I am also doing actual work
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    (Original post by Andy98)
    I'm not one to spam


    Ssshhh, I am also doing actual work
    I'm doing actual work too.
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    (Original post by Zacken)
    I'm doing actual work too.
    Sure :rolleyes:

    What work? :eyeball:
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    (Original post by Andy98)
    Sure :rolleyes:

    What work? :eyeball:
    Uhm... uhm... okay nevermind.
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    (Original post by Zacken)
    Uhm... uhm... okay nevermind.
    Thought as much :rofl:
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    (Original post by Andy98)
    Thought as much :rofl:
    :talkhand:
 
 
 
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