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    (Original post by BanterBus)
    I got Propyl-Propanoate (not the correct name for it) with propanoic acid forming a ester bond with propan-2-ol
    Would it not have been 1-methylethylpropanoate?
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    what did you guys get from number of repeat units of the monomer. i put 714.2..... and i think its wrong coz you had to put 714 or 715
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    (Original post by FluffyCommie)
    CH3CH2CH2ONa? That doesn't sound right, are you talking about the last question? I got the two haloalkanes as CH3CH2CH2Br and CH3CHBrCH3
    Then propan-1-ol and propan-2-ol after reflux with OH-...
    That's right I did get CH3CH2CH2Br and CH3CHBrCH3 and in IR I got CH3CH2COOH after reflux (carboxylic acid is formed?) and then when it mentioned that the acid (G) reacted with another product from hydrolysis (I assumed that was NaBr) I said it formed CH2CH2COONa unfortunately I was wrong but never mind can't do anything now lol
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    (Original post by toby22222)
    what did you guys get from number of repeat units of the monomer. i put 714.2..... and i think its wrong coz you had to put 714 or 715
    yeah i put 715
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    (Original post by FluffyCommie)
    CH3CH2CH2ONa? That doesn't sound right, are you talking about the last question? I got the two haloalkanes as CH3CH2CH2Br and CH3CHBrCH3
    Then propan-1-ol and propan-2-ol after reflux with OH-...
    i got that too^ then the propan-1-ol forms the carboxylic acid which was the infrared spectra
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    (Original post by nicoleemmak)
    Would it not have been 1-methylethylpropanoate?
    I got 1,1-dimethylpropanoatesimply because the O-H group was in the middle, so there would have been a methyl on the top and the bottom of the middle carbon
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    (Original post by nimbusninja)
    I got 1,1-dimethylpropanoatesimply because the O-H group was in the middle, so there would have been a methyl on the top and the bottom of the middle carbon
    Ah yes thats what i got its just the naming of it is confusing
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    On the last question we were just required to give the structure of the ester right, not the name?
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    (Original post by mattyk5)
    yeah 3 carbons. Couldnt have been 4 carbons because the empirical formula can have 2/3 carbons. If lets say the empirical had 2 then the only way to get 4 carbons was to double the empirical formula which leads to the Mr being OVER 150 which it couldnt be so therefore had to be 3 carbons imo
    So relieved
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    (Original post by nimbusninja)
    I got 1,1-dimethylpropanoatesimply because the O-H group was in the middle, so there would have been a methyl on the top and the bottom of the middle carbon
    I think you can draw it either way because the central carbon just has to have 2 Cs and one O coming off it, but it doesn't matter which side is which, you didn't have to name it in the exam did you? 😣
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    (Original post by Oooooooa)
    On the last question we were just required to give the structure of the ester right, not the name?
    yeah just the structure thankfully
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    Are people sure it's not 4 carbons instead of 3?? I got four carbons each time :// Will I still get something like an ecf mark for it over all?? 😩
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    (Original post by Twomenoneclub)
    So relieved
    Hehe yh it did my head a little but i missed out a step and i was like "OOOhhhh". Only had 15 minutes to do all of last question so luckily got it in time
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    (Original post by TheGeekGal)
    Are people sure it's not 4 carbons instead of 3?? I got four carbons each time :// Will I still get something like an ecf mark for it over all?? 😩
    Possibly, i dont see why not its over 10 marks so you should get some sort of assistance
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    Did anyone get 218.9 or 281.9 litres (some of those numbers) for the petrol question?


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    Also I got -281 for the enthalpy question I think I did something wrong :/


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    for the emperical formula I got 3 carbons 7 hydrogens and 1 br which got me a mr of 120ish something which is less than 150. I thought that when you get a the number 3 point- something in your emperical formula you would have to double all the other numbers but the clue I saw was less than 150 so I left it. Therefore I think its C3H7BR.
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    FFs I got so many silly mistakes

    For The mass of cyclopentanol I got 13.7 bc I thought the initial mr of cyclohexene was 70 when it was 68....

    Also I got the wrong monomer unit for the polymer hence I got 595.5 as the number of units FML

    Pls tell me I'll get ECF marks for this mess somehow..
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    (Original post by Saywhatyoumean)
    Also I got -281 for the enthalpy question I think I did something wrong :/


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    Why do you think you did something wrong? Im not sure what i got but i know i didnt forget the minus
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    (Original post by mercuryman)
    FFs I got so many silly mistakes

    For The mass of cyclopentanol I got 13.7 bc I thought the initial mr of cyclohexene was 70 when it was 68....

    Also I got the wrong monomer unit for the polymer hence I got 595.5 as the number of units FML

    Pls tell me I'll get ECF marks for this mess somehow..
    I got 14.0 for the mass, what did anyone else get?
 
 
 
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