OCR Chemistry F322 June 2016

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Reply 20

nicoleemmak

Original post by BanterBus

I got Propyl-Propanoate (not the correct name for it) with propanoic acid forming a ester bond with propan-2-ol

Would it not have been 1-methylethylpropanoate?

Reply 21

toby22222

what did you guys get from number of repeat units of the monomer. i put 714.2..... and i think its wrong coz you had to put 714 or 715

Reply 22

milutin767

Original post by FluffyCommie

CH3CH2CH2ONa? That doesn't sound right, are you talking about the last question? I got the two haloalkanes as CH3CH2CH2Br and CH3CHBrCH3
Then propan-1-ol and propan-2-ol after reflux with OH-...

That's right I did get CH3CH2CH2Br and CH3CHBrCH3 and in IR I got CH3CH2COOH after reflux (carboxylic acid is formed?) and then when it mentioned that the acid (G) reacted with another product from hydrolysis (I assumed that was NaBr) I said it formed CH2CH2COONa unfortunately I was wrong but never mind can't do anything now lol

Reply 23

milutin767

Original post by toby22222

what did you guys get from number of repeat units of the monomer. i put 714.2..... and i think its wrong coz you had to put 714 or 715

yeah i put 715

Reply 24

sa32rra

Original post by FluffyCommie

CH3CH2CH2ONa? That doesn't sound right, are you talking about the last question? I got the two haloalkanes as CH3CH2CH2Br and CH3CHBrCH3
Then propan-1-ol and propan-2-ol after reflux with OH-...

i got that too^ then the propan-1-ol forms the carboxylic acid which was the infrared spectra

Reply 25

nimbusninja

Original post by nicoleemmak

Would it not have been 1-methylethylpropanoate?

I got 1,1-dimethylpropanoatesimply because the O-H group was in the middle, so there would have been a methyl on the top and the bottom of the middle carbon

Reply 26

mattyk5

Original post by nimbusninja

I got 1,1-dimethylpropanoatesimply because the O-H group was in the middle, so there would have been a methyl on the top and the bottom of the middle carbon

Ah yes thats what i got its just the naming of it is confusing

Reply 27

Oooooooa

On the last question we were just required to give the structure of the ester right, not the name?

Reply 28

Twomenoneclub

Original post by mattyk5

yeah 3 carbons. Couldnt have been 4 carbons because the empirical formula can have 2/3 carbons. If lets say the empirical had 2 then the only way to get 4 carbons was to double the empirical formula which leads to the Mr being OVER 150 which it couldnt be so therefore had to be 3 carbons imo

So relieved

Reply 29

nicoleemmak

Original post by nimbusninja

I got 1,1-dimethylpropanoatesimply because the O-H group was in the middle, so there would have been a methyl on the top and the bottom of the middle carbon

I think you can draw it either way because the central carbon just has to have 2 Cs and one O coming off it, but it doesn't matter which side is which, you didn't have to name it in the exam did you? 😣

Reply 30

mattyk5

Original post by Oooooooa

On the last question we were just required to give the structure of the ester right, not the name?

yeah just the structure thankfully

Reply 31

TheGeekGal

Are people sure it's not 4 carbons instead of 3?? I got four carbons each time :// Will I still get something like an ecf mark for it over all?? 😩

Reply 32

mattyk5

Original post by Twomenoneclub

So relieved

Hehe yh it did my head a little but i missed out a step and i was like "OOOhhhh". Only had 15 minutes to do all of last question so luckily got it in time

Reply 33

mattyk5

Original post by TheGeekGal

Are people sure it's not 4 carbons instead of 3?? I got four carbons each time :// Will I still get something like an ecf mark for it over all?? 😩

Possibly, i dont see why not its over 10 marks so you should get some sort of assistance

Reply 34

Saywhatyoumean

Did anyone get 218.9 or 281.9 litres (some of those numbers) for the petrol question?

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Reply 35

Saywhatyoumean

Also I got -281 for the enthalpy question I think I did something wrong :/

Posted from TSR Mobile

Reply 36

Pingu7

for the emperical formula I got 3 carbons 7 hydrogens and 1 br which got me a mr of 120ish something which is less than 150. I thought that when you get a the number 3 point- something in your emperical formula you would have to double all the other numbers but the clue I saw was less than 150 so I left it. Therefore I think its C3H7BR.

Reply 37

mercuryman

FFs I got so many silly mistakes

For The mass of cyclopentanol I got 13.7 bc I thought the initial mr of cyclohexene was 70 when it was 68....

Also I got the wrong monomer unit for the polymer hence I got 595.5 as the number of units FML

Pls tell me I'll get ECF marks for this mess somehow.. :frown: