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    (Original post by junayd1998)
    Yeah lmao just hit me up on that question lmao. Na but anyways what did you do to learn Vectors any particular good video?
    Unfortunately I just had a good teacher who taught it to us well so I don't have any video to suggest. I'm sure YouTube would have some good videos, you'll just have to search for a bit to find one.

    Even if you type in "GCSE vectors" on Google there will be some information on it.
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    http://prntscr.com/b14ka0

    Like for example this question, I only understand we are going from O to M but how do we figure out the letter between O and M and M and G?
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    (Original post by junayd1998)
    http://prntscr.com/b14ka0

    Like for example this question, I only understand we are going from O to M but how do we figure out the letter between O and M and M and G?
    Basically, with vectors you can kind of trace along a path with your fingers.

    So, for example - if you want to go from O to G,that's just from O to P and then from P to G.

    Which is just OG = a + b.

    Now you want half of OG, that is the midpoint, well - you know what OG is, so to find the midpoint, what do you do?
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    (Original post by junayd1998)
    http://prntscr.com/b14ka0

    Like for example this question, I only understand we are going from O to M but how do we figure out the letter between O and M and M and G?
    So M is the midpoint of OG and we know that OG is a+b. Therefore, OM is half of a+b so the answer (I think) is 1/2a+1/2b (or 0.5a+0.5b or 1/2(a+b) )
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    (Original post by Zacken)
    Basically, with vectors you can kind of trace along a path with your fingers.

    So, for example - if you want to go from O to G,that's just from O to P and then from P to G.

    Which is just OG = a + b.

    Now you want half of OG, that is the midpoint, well - you know what OG is, so to find the midpoint, what do you do?
    So you can do a+b divided by 2?
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    (Original post by junayd1998)
    So you can do a+b divided by 2?
    Yeah.
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    (Original post by Zacken)
    Yeah.
    So your final answer a + b / 2 ??
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    (Original post by junayd1998)
    So your final answer a + b / 2 ??
    Yeah.
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    (Original post by Zacken)
    Yeah.

    http://prntscr.com/b19mh7

    How do you do this one part b)
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    Vectors almost always comes up in the Maths paper, so from probability, you should try to get your head around it.
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    (Original post by Fractite)
    Vectors almost always comes up in the Maths paper, so from probability, you should try to get your head around it.
    Yeah I know im trying tends to be the last question on the edexcel maths paper either that or graph transformations
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    (Original post by junayd1998)
    http://prntscr.com/b19mh7

    How do you do this one part b)
    You want to show that NM is parallel to MC. So find NM, find MC - show that they are multiples of one another.
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    Proving straight lines in vectors just means that you have to show that the NM vector is a multiple of the NC vector and start at the same point (which they do, becuase they start at N).

    You work out the NC vector, and then then NM vector, then divide them by each other (NC divided by NM) and it should give you a whole number, proving that they're a multiple of each other, and that NMC is a straight line.

    If that makes sense.
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    (Original post by junayd1998)
    http://prntscr.com/b19mh7

    How do you do this one part b)
    If you prove that \overrightarrow{NM} is parallel to \overrightarrow{NC} then this proves that NMC is a straight line.

    To see why this must be true, draw a line NM anywhere on a peice of paper. Then try to draw a line NC on the paper such that NC is parallel to NM.

    EDIT : Zacken's way is also fine.
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    (Original post by Zacken)
    You want to show that NM is parallel to MC. So find NM, find MC - show that they are multiples of one another.
    Okay so N to M is b + 1/2BP ??
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    (Original post by junayd1998)
    Okay so N to M is b + 1/2BP ??
    Find it all in terms of a and b.
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    (Original post by Fractite)
    Proving straight lines in vectors just means that you have to show that the NM vector is a multiple of the NC vector and start at the same point (which they do, becuase they start at N).

    You work out the NC vector, and then then NM vector, then divide them by each other (NC divided by NM) and it should give you a whole number, proving that they're a multiple of each other, and that NMC is a straight line.

    If that makes sense.
    It doesn't - you can't divide vectors and it's also not necessary that they be integer multiples. They need only be real multiples of one another.
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    (Original post by Zacken)
    It doesn't - you can't divide vectors and it's also not necessary that they be integer multiples. They need only be real multiples of one another.
    Oh yeah.
    Sorry.
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    (Original post by Zacken)
    Find it all in terms of a and b.
    Ugh im confused so we know N to P is b then P to M is what??

    If we know A to P is 3b that means P to M is -1.5b? because its half?
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    (Original post by junayd1998)
    Ugh im confused so we know N to P is b then P to M is what??

    If we know A to P is 3b that means P to M is -1.5b? because its half?
    You know what PB is, PM is half of PB. Which isn't -1.5b.
 
 
 
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