You are Here: Home >< Maths

# AQA 2016 C1 Unofficial Mark Scheme Watch

1. (Original post by BamSrown)
Anyone got any idea what grade boundaries will be like?
I assume they'll be lower than last year
2. Can someone please put the marks next to every answer much appreciated

Posted from TSR Mobile
3. Should be around 60 for an A. I hope.
4. (Original post by Katie904)
Can someone please put the marks next to every answer much appreciated

Posted from TSR Mobile
Don't want to put ones i don't know. Sorry.
5. [QUOTE=Iamz;64916099]AQA 2016 UNOFFICIAL MARK SCHEME

1)
a. Work out the gradient of a tangent, m = -5/3 (2marks)
b. Find the co-ordinates of B, B(-3,4) (3marks)
c. Work out k from (3+5k, 4-3k) ?,k = -30 (2marks)

2)
a. Simplify (3√5)^2 = 45 (2marks)
b. ((3√5)^2+√5) / (7+3√5) = 75 - 32√5 (5marks)

3)
a. Put x^2-7x-2, y= (x - 7/2)^2 - 41/4
bi. minimum value, - 41/4 (1mark)
c. What is the geometrical transformation from y=(...) onto y=(x-4)^2, Translation by (1/2 , 41/4)

4)
a. Show that (x+1) was a factor, subbed in to = 0 (2marks)
b. Give p(x) as three linear factors, (x+3)(x-4)(x-4) (3marks)
c. Find remainder when p(x) is divided by (..), r = 20 (2marks)
d. Divide p(x) by (x-2) and leave in the form (x-2)(x^2-bx+c)+n, (x-2)(x^2-3x+14) + 20 (3marks)

5)
ai. Find equation of circle, (x-5)^2+(y+3)^2 = 65 (2marks)
b. Find the co-ordinates of B when AB is the diameter, B(12,-7)
c. Find the length CT, √ 81 = 9
d. Find the equation of the tangent at A, 7x-4y+18=0

6)
a. Find the equation of the tangent, y = -32x - 40
ii. Find the value of x (something), x = -1±√5
b. Sketch the graph of 8-4x-2x^2, n-shaped parabola with y-intercept = 8 & x axis intercepts at -1+√5 & -1-√5 (3marks)
c. k=4 and k=20

7)
a.
b. Find the value of Q, Q(-5/4)
c. Find the definite integral between -2 & 1, 81/4 (5marks)
d. Find the shaded area ( definite integral - area of triangle), 45/4 (3marks)

8)
ai. Find d^2y / dx^2, -2x - 9x^2 (2marks)
ii. d^2y/dx^2= - 2x - 9x^2 sub in x-coordinate of p to get 45, 45>0 therefore it is a minimum value
bi. Y= k(4x + 1) & y= ...... , You had to make the y's equal each other then rearrange to form an equation given
bii. Solve the inequality (9k^2.....), k < -3/2 & k > 6 (4marks)

Hope this helped you in any way.]

Can you fill in the marks please
6. [QUOTE=Tjcmcfc;64939097]
(Original post by Iamz)
AQA 2016 UNOFFICIAL MARK SCHEME

1)
a. Work out the gradient of a tangent, m = -5/3 (2marks)
b. Find the co-ordinates of B, B(-3,4) (3marks)
c. Work out k from (3+5k, 4-3k) ?,k = -30 (2marks)

2)
a. Simplify (3√5)^2 = 45 (2marks)
b. ((3√5)^2+√5) / (7+3√5) = 75 - 32√5 (5marks)

3)
a. Put x^2-7x-2, y= (x - 7/2)^2 - 41/4
bi. minimum value, - 41/4 (1mark)
c. What is the geometrical transformation from y=(...) onto y=(x-4)^2, Translation by (1/2 , 41/4)

4)
a. Show that (x+1) was a factor, subbed in to = 0 (2marks)
b. Give p(x) as three linear factors, (x+3)(x-4)(x-4) (3marks)
c. Find remainder when p(x) is divided by (..), r = 20 (2marks)
d. Divide p(x) by (x-2) and leave in the form (x-2)(x^2-bx+c)+n, (x-2)(x^2-3x+14) + 20 (3marks)

5)
ai. Find equation of circle, (x-5)^2+(y+3)^2 = 65 (2marks)
b. Find the co-ordinates of B when AB is the diameter, B(12,-7)
c. Find the length CT, √ 81 = 9
d. Find the equation of the tangent at A, 7x-4y+18=0

6)
a. Find the equation of the tangent, y = -32x - 40
ii. Find the value of x (something), x = -1±√5
b. Sketch the graph of 8-4x-2x^2, n-shaped parabola with y-intercept = 8 & x axis intercepts at -1+√5 & -1-√5 (3marks)
c. k=4 and k=20

7)
a.
b. Find the value of Q, Q(-5/4)
c. Find the definite integral between -2 & 1, 81/4 (5marks)
d. Find the shaded area ( definite integral - area of triangle), 45/4 (3marks)

8)
ai. Find d^2y / dx^2, -2x - 9x^2 (2marks)
ii. d^2y/dx^2= - 2x - 9x^2 sub in x-coordinate of p to get 45, 45>0 therefore it is a minimum value
bi. Y= k(4x + 1) & y= ...... , You had to make the y's equal each other then rearrange to form an equation given
bii. Solve the inequality (9k^2.....), k < -3/2 & k > 6 (4marks)

Hope this helped you in any way.]

Can you fill in the marks please
Translation by (1/2 , -41/4) you replace x with x-1/2 and y with -(-41/4) which gives you y+41/4 but because they wanted it in the form y= you subtract the 41/4 and it becomes y=(x-1/2)^-41/4
7. thank you!!

TSR Support Team

We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

This forum is supported by:
Updated: February 20, 2017
Today on TSR

### Anxious about my Oxford offer

What should I do?

### Am I doomed because I messed up my mocks?

Discussions on TSR

• Latest
• ## See more of what you like on The Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.

• Poll
Useful resources

Can you help? Study help unanswered threadsStudy Help rules and posting guidelinesLaTex guide for writing equations on TSR

## Groups associated with this forum:

View associated groups
Discussions on TSR

• Latest
• ## See more of what you like on The Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.

• The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE