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    (Original post by marioman)
    Did anyone on here manage to augment the flow the second time?
    No I'm hopeful it was a mistake


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    Yeah I have a feeling it was a misprint and I think they wanted us to put 9 through it
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    What did you guys get for the minimax question at the very end?


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    (Original post by drandy76)
    What did you guys get for the minimax question at the very end?


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    Was this the absolute difference? I got a value of 1 lmao.. wbu?
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    (Original post by AstroNandos)
    Was this the absolute difference? I got a value of 1 lmao.. wbu?
    Oh ffs I added them together and got 10 **** my life


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    (Original post by drandy76)
    Oh ffs I added them together and got 10 **** my life


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    Well i have no idea if i did it right. You can still always get method marks for doing what you did right cant you?
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    (Original post by drandy76)
    Oh ffs I added them together and got 10 **** my life


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    Omg 😂😂
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    Xsanda’s solutions:

    1) Matching
    i) JF=3-ND=4
    1:MA
    2:-
    3:JF
    4:ND
    5:JA
    6:MJ
    ii) SO=5-JA=2
    1:MA 2:JA 3:JF 4:ND 5: SO 6:MJ
    iii) 3=JF,4=ND,5=SO always
    1:MJ 2:MA 3:JF 4:ND 5: SO 6:JA

    2) Flow
    i) FT = 2, DT = 4, cut = 9
    iia) SCBFT +2 (given)
    b) SCFBAEDT +1
    iii) 8, with cut {SABCF}{DET} of value 8

    3) Hungarian
    i) Add dummy column X with 100 in each
    Reduce rows -86, -92, -88, -98
    Reduce cols -0,-2,-0,-2
    ii) AS, BT, CL, no match for D, £271 cost
    iii) CS, BT; AL costs £83

    4) Rock paper scissors
    i) scissors with paper: gain of 1, loss of 2: 1 + (-2) ≠ 0
    ii) playsafe: scissors
    iii) scissors 2-2p-4q, paper 3p+2q-2, rock 2q-p
    iv) p=0.5, q=0.25, rock = 0.25

    5) critical path analysis
    i) F and H also critical
    ii) A: -, B: -, C: -, D: A, E: BD, F: BCD, G: E, H: EF, I: GH, J: H
    iii) 60 mins, critical ABDEHJ
    iv) allocation for 3 people
    v) allocation for 2 people
    vi) A is critical, but so is B, which happens at the same time, so must reduce both to gain 5 minutes. 200+400=£600. Best is H and J: £500+£500 = £1000

    6i) (0;0)-(1;1)-(2;1)-(3;0)-(4;0): weight 7
    ii) 1 point
    iii) (0;0)-(1;0) 1
    (0;0)-(1;1) 2
    (1;0)-(2;0) 1
    (1;0)-(2;1) 1
    (1;1)-(2;0) 2
    (1;1)-(2;1) 1
    (2;0)-(3;0) 0
    (2;0)-(3;1) 0
    (2;1)-(3;0) 2
    (2;1)-(3;1) 0
    (3;0)-(4;0) 1
    (3;1)-(4;0) 2
    iv) (0;0)-(1;0)-(2;0)-(3;0)-(4;0): 1 point per round maximum
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    (Original post by marioman)
    Did anyone on here manage to augment the flow the second time?
    Yep man, was just a standard hungarian algo. right?
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    I'm glad other people think that was a mistake too... I was ****ting myself 😂
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    what mark to people reckon for grade boundaries ?
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    (Original post by Fp3)
    what mark to people reckon for grade boundaries ?
    Usually high 50 low 60 for an A and between 6-8 between each grade


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    (Original post by marioman)
    Did anyone on here manage to augment the flow the second time?
    That was a mean one but I found a route which you could augment by one, it involved going backwards on one of the arcs - I can't rmemeber which one, but basically, it meant a maximum flow of 8
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    I don't know I think grade boundaries are standard,, the only tricky question was number 6 which was due to the weirdness of it
    62 for an A probably
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    (Original post by xsanda)
    Xsanda’s solutions:

    1) Matching
    i) JF=3-ND=4
    1:MA
    2:-
    3:JF
    4:ND
    5:JA
    6:MJ
    ii) SO=5-JA=2
    1:MA 2:JA 3:JF 4:ND 5: SO 6:MJ
    iii) 3=JF,4=ND,5=SO always
    1:MJ 2:MA 3:JF 4:ND 5: SO 6:JA

    2) Flow
    i) FT = 2, DT = 4, cut = 9
    iia) SCBFT +2 (given)
    b) SCFBAEDT +1
    iii) 8, with cut {SABCF}{DET} of value 8

    3) Hungarian
    i) Add dummy column X with 100 in each
    Reduce rows -86, -91, -88, -98
    Reduce cols -0,-2,-0,-2
    ii) AS, BT, CL, no match for D, £271 cost
    iii) CS, BT; AL costs £83

    4) Rock paper scissors
    i) scissors with paper: gain of 1, loss of 2: 1 + (-2) ≠ 0
    ii) playsafe: scissors
    iii) scissors 2-2p-4q, paper 3p+2q-2, rock 2q-p
    iv) p=0.5, q=0.25, rock = 0.25

    5) critical path analysis
    i) F and H also critical
    ii) A: -, B: -, C: -, D: A, E: BD, F: BCD, G: E, H: EF, I: GH, J: H
    iii) 60 mins, critical ABDEHJ
    iv) allocation for 3 people
    v) allocation for 2 people
    vi) A is critical, but so is B, which happens at the same time, so must reduce both to gain 5 minutes. 200+400=£600. Best is H and J: £500+£500 = £1000

    6i) (0;0)-(1;1)-(2;1)-(3;0)-(4;0): weight 7
    ii) 1 point
    iii) (0;0)-(1;0) 1
    (0;0)-(1;1) 2
    (1;0)-(2;0) 1
    (1;0)-(2;1) 1
    (1;1)-(2;0) 2
    (1;1)-(2;1) 1
    (2;0)-(3;0) 0
    (2;0)-(3;1) 0
    (2;1)-(3;0) 2
    (2;1)-(3;1) 0
    (3;0)-(4;0) 1
    (3;1)-(4;0) 2
    iv) (0;0)-(1;0)-(2;0)-(3;0)-(4;0): 1 point per round maximum
    Thats what I got My explanation for the cost being >200 for reducing activities A and B may have been a bit kerfuffled but other than that, I'm fairly pleased
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    (Original post by bassala)
    Thats what I got My explanation for the cost being >200 for reducing activities A and B may have been a bit kerfuffled but other than that, I'm fairly pleased
    Yeah I am the same, that part was only worth 2 marks though right?
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    (Original post by JoshuaHope)
    Yeah I am the same, that part was only worth 2 marks though right?
    The explanation part would be one mark and the part where you identify H and J is another mark so yeah
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    Found it all fine other than that flow augmentation, I had to say to ignore the one they had added in ii.a , and added two flow augmentation routes (one of flow 2, one of flow 1) to show a flow of 8 through
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    Who gives a cooking award to the person who's icing is of most similar quality to their baking?
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    (Original post by CuriosityKTMC)
    Who gives a cooking award to the person who's icing is of most similar quality to their baking?
    Isnt it least similar?
 
 
 
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