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    what did everyone get for the period question too?
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    Did anyone get 38 for the summations sequences question and X=12,-3 for logs
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    i think it's only x=12, -3 wasn't possible
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    (Original post by M12345689)
    Did anyone get 38 for the summations sequences question and X=12,-3 for logs
    For some reason i got 37 for the summation i might have made a slip up some where. I got the same for the logs
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    (Original post by Stanspam)
    i think it's only x=12, -3 wasn't possible
    I thought because the X was squared it would make it possible as it would go to 9
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    (Original post by Stanspam)
    i think it's only x=12, -3 wasn't possible
    -3 was possible if you put it into the equation the bit inside the log was >0 as there was x^2 and x+4
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    Does anyone remember what the actual log question was?
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    (Original post by Csd1999)
    Does anyone remember what the actual log question was?
    2log x - log (x+4) = 3, I think

    Edit: scratch that, guy below me is right
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    (Original post by Csd1999)
    Does anyone remember what the actual log question was?
    2log base 3 (X) - log base 3 (X+4) = 2
    I think
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    (Original post by sandpitturtle)
    what did everyone get for the period question too?
    I got pi/a, just by trying sin x, sin 2x, sin 3x, etc and roughly sketching the graph.

    (Original post by M12345689)
    Did anyone get 38 for the summations sequences question and X=12,-3 for logs
    Yep, I got that.

    (Original post by Stanspam)
    i think it's only x=12, -3 wasn't possible
    -3 is possible because you square the x on top and add 4 to x on the bottom, so you get x^2 / 1
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    (Original post by h3rmit)
    I got pi/a, just by trying sin x, sin 2x, sin 3x, etc and roughly sketching the graph.


    Yep, I got that.

    -3 is possible because you square the x on top and add 4 to x on the bottom, so you get x^2 / 1
    -3 wasn't possible in the original equation
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    (Original post by Annonomous09)
    -3 wasn't possible in the original equation
    It is if
    (Original post by M12345689)
    2log base 3 (X) - log base 3 (X+4) = 2
    is the original equation, which does definitely seem to ring a bell. If you apply the 2 as a power before logging it works and gives 2
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    Unofficial mark scheme anyone?
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    Does anyone know how many marks the log question was worth?
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    (Original post by h3rmit)
    It is if

    is the original equation, which does definitely seem to ring a bell. If you apply the 2 as a power before logging it works and gives 2
    I don't think it counts as you can't really square a minus, and log isn't valid for negative numbers, but I am not tottaly sure
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    Was the period not 2pi/a?
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    (Original post by sandpitturtle)
    I don't think it counts as you can't really square a minus, and log isn't valid for negative numbers, but I am not tottaly sure
    Why cant you square a minus? Surely it works like squaring in general, turns it positive? Maybe they wanted you to state it would have to be 3 instead of -3?
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    (Original post by Sourestdeeds)
    Why cant you square a minus? Surely it works like squaring in general, turns it positive? Maybe they wanted you to state it would have to be 3 instead of -3?
    true, sorry i got confused with sqr rooting, i am still so unsure about that question if -3 was counted though
    either way would probably only be a mark so not too fussed haha
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    (Original post by sandpitturtle)
    true, sorry i got confused with sqr rooting, i am still so unsure about that question if -3 was counted though
    either way would probably only be a mark so not too fussed haha
    I was also confused because it works in the rearranged equation, just not the original. I just stuck with 12 anyway
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    What do people think the boundaries will be?
 
 
 
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