Hey there! Sign in to join this conversationNew here? Join for free
    Offline

    1
    ReputationRep:
    (Original post by Xsk)
    What the hell was that.


    The 'Evaluate' one? I got -2.
    Aw yes thanks, heard a lot of different answers for it.


    Posted from TSR Mobile
    Offline

    1
    ReputationRep:
    (Original post by caitrionacarson)
    Aw yes thanks, heard a lot of different answers for it.


    Posted from TSR Mobile
    Heard a lot of different answers for every question lmao
    Offline

    1
    ReputationRep:
    (Original post by 9clpc9)
    That paper was terrible. Much harder than last year. Did anyone get that bearings question?
    I used the sine rule to get the distance from the start to the oak tree, think I got 292.38
    Then used trig to get the shortest distance to the path.
    Sin(30)=d/292.38
    D= 146.19
    ~146

    Anyone else?


    Posted from TSR Mobile
    Offline

    2
    ReputationRep:
    (Original post by caitrionacarson)
    I used the sine rule to get the distance from the start to the oak tree, think I got 292.38
    Then used trig to get the shortest distance to the path.
    Sin(30)=d/292.38
    D= 146.19
    ~146

    Anyone else?

    I used the sine rule too, but I forget my answers.
    Posted from TSR Mobile
    For the last question what did everyone get?

    Anyone got the papers too?
    • Thread Starter
    Offline

    3
    ReputationRep:
    (Original post by caitrionacarson)
    I used the sine rule to get the distance from the start to the oak tree, think I got 292.38
    Then used trig to get the shortest distance to the path.
    Sin(30)=d/292.38
    D= 146.19
    ~146

    Anyone else?


    Posted from TSR Mobile
    I Got a similar answer for that but I've only realised that I used the two angles given, should I have found out the missing angle and use it?
    Also does anyone have an idea what you would need to get an A or an B on that paper, even in my case a c?
    Offline

    1
    ReputationRep:
    (Original post by 9clpc9)
    For the last question what did everyone get?

    Anyone got the papers too?
    Think I got (x+3)^2 + (y-2)^2 = 25




    Posted from TSR Mobile
    • Thread Starter
    Offline

    3
    ReputationRep:
    (Original post by 9clpc9)
    For the last question what did everyone get?

    Anyone got the papers too?
    I barely got answers to them questions... I have the question paper to both if that's what you mean.
    Offline

    16
    ReputationRep:
    (Original post by caitrionacarson)
    Think I got (x+3)^2 + (y-2)^2 = 25

    Posted from TSR Mobile
    That is what i got too.

    1)a) y=4x-(1\x)+4
    b)ii) 4.61
    3)a)-19.5,-160 - something like that.
    4)i) 242m
    ii) 213m
    5)i)59.3
    ii)130
    6)a) -2
    b)-1.58
    8)b=2
    (x+3)^2 + (y-2)^2 = 25
    Offline

    2
    ReputationRep:
    (Original post by ozmo19)
    That is what i got too.

    1)a) y=4x-(1\x)+4
    b)ii) 4.61
    3)a)-19.5,-160 - something like that.
    4)i) 242m
    ii) 213m
    5)i)59.3
    ii)130
    6)a) -2
    b)-1.58
    8)b=2
    (x+3)^2 + (y-2)^2 = 25
    I don't remember exactly what I got as my answers but it looks familiar! I got the same for 6b and 8

    (Original post by lmg1)
    I barely got answers to them questions... I have the question paper to both if that's what you mean.
    Hi, yeah can I get pics of the question paper please?
    Offline

    1
    ReputationRep:
    (Original post by caitrionacarson)
    I used the sine rule to get the distance from the start to the oak tree, think I got 292.38
    Then used trig to get the shortest distance to the path.
    Sin(30)=d/292.38
    D= 146.19
    ~146

    Anyone else?


    Posted from TSR Mobile
    Sine rule was 200/sin30 = x/sin40, so x = 200sin40/sin30 = 257.12, trig from there?
    Offline

    16
    ReputationRep:
    (Original post by Xsk)
    Sine rule was 200/sin30 = x/sin40, so x = 200sin40/sin30 = 257.12, trig from there?
    This is what I did. I then used sine rule again followed by pythagoras to get 242m
    Offline

    2
    ReputationRep:
    (Original post by Xsk)
    Sine rule was 200/sin30 = x/sin40, so x = 200sin40/sin30 = 257.12, trig from there?
    I got that too, and for the shortest distance i got 266 i think
    Offline

    2
    ReputationRep:
    Anoyone have access to the paper?
    Offline

    1
    ReputationRep:
    (Original post by Smcdonald98)
    I got that too, and for the shortest distance i got 266 i think
    Using trig, the shortest distance = 257.12sin70 = 242?
    Offline

    1
    ReputationRep:
    (Original post by Xsk)
    Sine rule was 200/sin30 = x/sin40, so x = 200sin40/sin30 = 257.12, trig from there?
    Aw damn I did x/sin110=200/sin40

    Oh well


    Posted from TSR Mobile
    Offline

    1
    ReputationRep:
    (Original post by ozmo19)
    This is what I did. I then used sine rule again followed by pythagoras to get 242m
    That seems like a longer way of doing it
    Offline

    16
    ReputationRep:
    (Original post by Xsk)
    That seems like a longer way of doing it
    It was the only thing i could think of at the time
    Offline

    1
    ReputationRep:
    (Original post by caitrionacarson)
    Aw damn I did x/sin110=200/sin40

    Oh well


    Posted from TSR Mobile
    sin40? If you had done sin30 then you could have done an alternate method, from what I can see You sure you didn't?
    Offline

    2
    ReputationRep:
    I stored some answers on my calculator:

    137, 257, 357, 266, 59.3, 119, -1.58,

    324, 256 - my values for n and k
    Offline

    1
    ReputationRep:
    (Original post by Xsk)
    sin40? If you had done sin30 then you could have done an alternate method, from what I can see You sure you didn't?
    Yeah I think I drew the diagram wrong, would need to see the question to see what I done.


    Posted from TSR Mobile
 
 
 
Poll
Do you agree with the PM's proposal to cut tuition fees for some courses?

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Write a reply...
Reply
Hide
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.