CCEA AS Maths C2 Tuesday 31st May Watch

caitrionacarson
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#21
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#21
(Original post by Xsk)
What the hell was that.


The 'Evaluate' one? I got -2.
Aw yes thanks, heard a lot of different answers for it.


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Xsk
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#22
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#22
(Original post by caitrionacarson)
Aw yes thanks, heard a lot of different answers for it.


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Heard a lot of different answers for every question lmao
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caitrionacarson
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#23
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#23
(Original post by 9clpc9)
That paper was terrible. Much harder than last year. Did anyone get that bearings question?
I used the sine rule to get the distance from the start to the oak tree, think I got 292.38
Then used trig to get the shortest distance to the path.
Sin(30)=d/292.38
D= 146.19
~146

Anyone else?


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9clpc9
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#24
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#24
(Original post by caitrionacarson)
I used the sine rule to get the distance from the start to the oak tree, think I got 292.38
Then used trig to get the shortest distance to the path.
Sin(30)=d/292.38
D= 146.19
~146

Anyone else?

I used the sine rule too, but I forget my answers.
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For the last question what did everyone get?

Anyone got the papers too?
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lmg1
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#25
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#25
(Original post by caitrionacarson)
I used the sine rule to get the distance from the start to the oak tree, think I got 292.38
Then used trig to get the shortest distance to the path.
Sin(30)=d/292.38
D= 146.19
~146

Anyone else?


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I Got a similar answer for that but I've only realised that I used the two angles given, should I have found out the missing angle and use it?
Also does anyone have an idea what you would need to get an A or an B on that paper, even in my case a c?
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caitrionacarson
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#26
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#26
(Original post by 9clpc9)
For the last question what did everyone get?

Anyone got the papers too?
Think I got (x+3)^2 + (y-2)^2 = 25




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lmg1
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#27
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#27
(Original post by 9clpc9)
For the last question what did everyone get?

Anyone got the papers too?
I barely got answers to them questions... I have the question paper to both if that's what you mean.
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ozmo19
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#28
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#28
(Original post by caitrionacarson)
Think I got (x+3)^2 + (y-2)^2 = 25

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That is what i got too.

1)a) y=4x-(1\x)+4
b)ii) 4.61
3)a)-19.5,-160 - something like that.
4)i) 242m
ii) 213m
5)i)59.3
ii)130
6)a) -2
b)-1.58
8)b=2
(x+3)^2 + (y-2)^2 = 25
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9clpc9
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#29
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#29
(Original post by ozmo19)
That is what i got too.

1)a) y=4x-(1\x)+4
b)ii) 4.61
3)a)-19.5,-160 - something like that.
4)i) 242m
ii) 213m
5)i)59.3
ii)130
6)a) -2
b)-1.58
8)b=2
(x+3)^2 + (y-2)^2 = 25
I don't remember exactly what I got as my answers but it looks familiar! I got the same for 6b and 8

(Original post by lmg1)
I barely got answers to them questions... I have the question paper to both if that's what you mean.
Hi, yeah can I get pics of the question paper please?
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Xsk
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#30
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#30
(Original post by caitrionacarson)
I used the sine rule to get the distance from the start to the oak tree, think I got 292.38
Then used trig to get the shortest distance to the path.
Sin(30)=d/292.38
D= 146.19
~146

Anyone else?


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Sine rule was 200/sin30 = x/sin40, so x = 200sin40/sin30 = 257.12, trig from there?
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ozmo19
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#31
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#31
(Original post by Xsk)
Sine rule was 200/sin30 = x/sin40, so x = 200sin40/sin30 = 257.12, trig from there?
This is what I did. I then used sine rule again followed by pythagoras to get 242m
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Smcdonald98
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#32
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#32
(Original post by Xsk)
Sine rule was 200/sin30 = x/sin40, so x = 200sin40/sin30 = 257.12, trig from there?
I got that too, and for the shortest distance i got 266 i think
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Smcdonald98
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#33
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#33
Anoyone have access to the paper?
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Xsk
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#34
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#34
(Original post by Smcdonald98)
I got that too, and for the shortest distance i got 266 i think
Using trig, the shortest distance = 257.12sin70 = 242?
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caitrionacarson
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#35
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#35
(Original post by Xsk)
Sine rule was 200/sin30 = x/sin40, so x = 200sin40/sin30 = 257.12, trig from there?
Aw damn I did x/sin110=200/sin40

Oh well


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Xsk
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#36
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#36
(Original post by ozmo19)
This is what I did. I then used sine rule again followed by pythagoras to get 242m
That seems like a longer way of doing it
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ozmo19
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#37
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#37
(Original post by Xsk)
That seems like a longer way of doing it
It was the only thing i could think of at the time
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Xsk
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#38
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#38
(Original post by caitrionacarson)
Aw damn I did x/sin110=200/sin40

Oh well


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sin40? If you had done sin30 then you could have done an alternate method, from what I can see You sure you didn't?
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Smcdonald98
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#39
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#39
I stored some answers on my calculator:

137, 257, 357, 266, 59.3, 119, -1.58,

324, 256 - my values for n and k
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caitrionacarson
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#40
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#40
(Original post by Xsk)
sin40? If you had done sin30 then you could have done an alternate method, from what I can see You sure you didn't?
Yeah I think I drew the diagram wrong, would need to see the question to see what I done.


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