Physics P1 AQA Watch

jazz_xox_
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#21
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#21
E (J) = m (kg) × c (J/kg) × θ (degrees c)

efficiency (J) = useful energy out / total energy in (× 100%)

efficiency (J)= useful power outtotal power in (× 100%)

E (J) = P(W) × t (s)

v (m/s) = f(Hz) × λ(m)

Payback time = cost of installation / saving per year (£)

kwH = kw x hour

cost (£) = kwh x price per unit (P)
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glassriver
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#22
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#22
(Original post by z_o_e)
Like this?

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Yep, I think that looks OK.
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CaptErin
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#23
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#23
(Original post by LNDNWASPS)
x
(Original post by PrinceKian)
x
(Original post by TheOtherSide.)
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(Original post by _Xenon_)
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(Original post by glassriver)
x
Thanks everyone for the advice
I've got that we need to know payback time and the kilowatt hours equation
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z_o_e
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#24
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#24
What could I say for the second bit?
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TheOtherSide.
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#25
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#25
(Original post by z_o_e)
What could I say for the second bit?
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It dissipates into surroundings.
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Dave<
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#26
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#26
Thanks that was a big help
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z_o_e
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#27
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#27
(Original post by TheOtherSide.)
It dissipates into surroundings.
Thank you xx :yy:

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_Xenon_
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#28
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#28
Hi the main thread can be found here
http://www.thestudentroom.co.uk/show...4111921&page=1

Best of luck for tomorrow!
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