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    E (J) = m (kg) × c (J/kg) × θ (degrees c)

    efficiency (J) = useful energy out / total energy in (× 100%)

    efficiency (J)= useful power outtotal power in (× 100%)

    E (J) = P(W) × t (s)

    v (m/s) = f(Hz) × λ(m)

    Payback time = cost of installation / saving per year (£)

    kwH = kw x hour

    cost (£) = kwh x price per unit (P)
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    (Original post by z_o_e)
    Like this?

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    Yep, I think that looks OK.
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    (Original post by LNDNWASPS)
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    (Original post by PrinceKian)
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    (Original post by TheOtherSide.)
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    (Original post by _Xenon_)
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    (Original post by glassriver)
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    Thanks everyone for the advice
    I've got that we need to know payback time and the kilowatt hours equation
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    What could I say for the second bit?
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    (Original post by z_o_e)
    What could I say for the second bit?
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    It dissipates into surroundings.
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    Thanks that was a big help
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    (Original post by TheOtherSide.)
    It dissipates into surroundings.
    Thank you xx :yy:

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    Hi the main thread can be found here
    http://www.thestudentroom.co.uk/show...4111921&page=1

    Best of luck for tomorrow!
 
 
 
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