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    (Original post by Steelmeat)
    How do i do part C?
    Find the tension in terms of k and then set T > 0 and solve for k.
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    (Original post by Zacken)
    Find the tension in terms of k and then set T > 0 and solve for k.
    I don't understand how i would do that?

    currently for part b i have the expressionT=\dfrac{W}{3} - \dfrac{kW}{2}

    not sure where to go from there
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    (Original post by Steelmeat)
    I don't understand how i would do that?

    currently for part b i have the expressionT=\dfrac{w}{3} - \dfrac{kW}{2}

    not sure where to go from there
    What on earth is w?

    Anyways... I get T = \frac{W}{6}(2-3k) in (b).
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    (Original post by Zacken)
    What on earth is w?

    Anyways... I get T = \frac{W}{6}(2-3k) in (b).
    sorry i made a mistake, i was supposed to make it captial

    but yea uu got the same thing as me written in a different form....
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    (Original post by Steelmeat)
    sorry i made a mistake, i was supposed to make it captial

    but yea uu got the same thing as me written in a different form....
    Right, so make that >0 and solve for k.
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    (Original post by Zacken)
    Right, so make that >0 and solve for k.
    hmmm do i just say then

    0<\dfrac{W}{3} - \dfrac{kW}{2}
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    (Original post by Steelmeat)
    hmmm do i just say then

    0<\dfrac{W}{3} - \dfrac{kW}{2}
    Now solve for k:

    \displaystyle \frac{W}{6}(2-3k) > 0 \iff 2-3k > 0 \iff \cdots
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    (Original post by Zacken)
    Now solve for k:

    \displaystyle \frac{W}{6}(2-3k) > 0 \iff 2-3k > 0 \iff \cdots
    so k<\dfrac{2}{3}?
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    (Original post by Steelmeat)
    so k<\dfrac{2}{3}?
    Yeah.
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    (Original post by Zacken)
    Yeah.
    ah thanks again
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    (Original post by Steelmeat)
    ah thanks again
    Sure.
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    how is part C done in this???!!! I'm stuck on it
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    (Original post by Steelmeat)
    I don't understand how i would do that?

    currently for part b i have the expressionT=\dfrac{W}{3} - \dfrac{kW}{2}

    not sure where to go from there
    (Original post by Zacken)
    What on earth is w?

    Anyways... I get T = \frac{W}{6}(2-3k) in (b).
    (Original post by Steelmeat)
    hmmm do i just say then

    0<\dfrac{W}{3} - \dfrac{kW}{2}
    ^^ do everything above do part B and find an expression for T in terms of everything else
    the set the big half of the expression >0 then solve for k
    (Original post by pondsteps)
    how is part C done in this???!!! I'm stuck on it
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    (Original post by pondsteps)
    how is part C done in this???!!! I'm stuck on it
    Did you read the thread?
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    (Original post by Steelmeat)
    I don't understand how i would do that?

    currently for part b i have the expressionT=\dfrac{W}{3} - \dfrac{kW}{2}

    not sure where to go from there
    is it right if we kept the expression in this form?
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    (Original post by poundsoffat)
    ^^ do everything above do part B and find an expression for T in terms of everything else
    the set the big half of the expression >0 then solve for k
    why do we set it to > 0
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    (Original post by pondsteps)
    is it right if we kept the expression in this form?
    yes it's fine Zacken's format or Steelmeat's format are both fine

    (Original post by pondsteps)
    why do we set it to > 0
    well if k=0 it doesn't have a value xD
    if k<0 then k is negative which you don't want
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    (Original post by pondsteps)
    why do we set it to > 0
    That's the definition of something being taut, it's tension is greater than 0. You should brush up your mechanical concepts.
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    (Original post by Zacken)
    That's the definition of something being taut, it's tension is greater than 0. You should brush up your mechanical concepts.
    ohh okay thanks. if its slack then the tension = 0 ?
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    (Original post by pondsteps)
    ohh okay thanks. if its slack then the tension = 0 ?
    Yeah.
 
 
 
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