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    The 'a' look at the right!
    The left is a carbon bounded to 3 other carbons
    So for 7aiii) it is a triplet cause theres 2 hydrogens to the adjacent carbon

    And using the n+1 rule; its 2+1 = triplet!

    7aii) the answer is, it has 4 peaks
    Theres 5 different hydrogen environments
    But 2 of them are CH3 which is the same environment so you class them as 1 single environments than two different environments
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    (Original post by Cakey_101)
    Yeah, sorry I dont think I made my question clear!
    If you have a look at June 2013 paper, question 7 you'll know what i mean i think.
    http://www.aqa.org.uk/subjects/scien...d-mark-schemes

    It asks:
    7 (a) (ii) Give the number of peaks in the 1H n.m.r. spectrum of J. (1 mark)
    7 (a) (iii) Give the splitting pattern of the protons labelled a. (1 mark)

    So what I dont understand is where do you have to look to find the splitting pattern or the number of peaks? To the left or the right of the letter they've specified?
    And also if youre having problems then check 'Enritoul' on youtube

    He goes over chem 4 nicely
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    Hi, can anyone help with question 1 e on June 2010, I just have no clue how to draw the structure of a 'trimer'
    Ive put the link to the paper below xx

    http://filestore.aqa.org.uk/subjects...W-QP-JUN10.PDF
 
 
 
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