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Hard A* GCSE Question Challenge - Perfect for Edexcel Calculator Paper Revision Watch

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    I am making the solutions for these questions now, and will shortly upload.
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    (Original post by gurpartapl)
    Edexcel has given previous questions in maths gcse that requires the students to choose suitable values of things, so for example, if you got 9.2.... so on... number of sweets. You to make a decision that you cannot have 9.2 number of sweets therefore round down to 9... Sorry if it confused you. hamza772000 and thanks for doing these questions.
    Okay, right, no problem, and thank you for posting these questions, if something like this comes up now I would know what to do, thanks again man.
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    (Original post by gurpartapl)
    Edexcel has given previous questions in maths gcse that requires the students to choose suitable values of things, so for example, if you got 9.2.... so on... number of sweets. You to make a decision that you cannot have 9.2 number of sweets therefore round down to 9... Sorry if it confused you. hamza772000 and thanks for doing these questions.
    chance of getting two blue sweets 6/30
    6*5 both equals 30
    then 3*2 is six ( as you take one away sweet away)
    3/6 are blue and 3/6 are yellow
    so 10 yellow sweets.
    Not to sure if this question works
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    (Original post by BW2206)
    chance of getting two blue sweets 6/30
    6*5 both equals 30
    then 3*2 is six ( as you take one away sweet away)
    3/6 are blue and 3/6 are yellow
    so 10 yellow sweets.
    Not to sure if this question works
    This question was inspired from hannah's sweets question, so i may have overlooked this method of answering the question, i wanted the students to approach this question algebraically (ie form a quadratic equation) so i didn't consider this way, that is my fault.

    Looking at your working out though, i am not sure why you multiplied 6 by 5 and then 3*2.. could you explain your method? BW2206


    Thanks.
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    Solutions uploaded guys, check it out.
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    for question 1 how do you get the answer for C, when you add 3 + 28/9 doesnt it give u 28/3.. lol tell me what i done wrong
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    Thanks so much for this! Appreciate the time you took to make these questions and solutions. Funnily enough, I found question 1 the hardest and the other two questions easier haha. I got the same answers as you too btw
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    (Original post by mariyahx)
    for question 1 how do you get the answer for C, when you add 3 + 28/9 doesnt it give u 28/3.. lol tell me what i done wrong
    Make the 3, into a fractional form so 3/1
    Make the denominator for both the fractions the same, in this case multiply (3/1)top and bottom by 9... So you get 27/9... Now if you add 27/9 + 28/9 (basically add the top numbers as denominators the same), you get 55/9..

    Use the calculator and u get 55/9.
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    where did u get the 27/9 from
    (Original post by gurpartapl)
    Make the 3, into a fractional form so 3/1
    Make the denominator for both the fractions the same, in this case multiply top and bottom by 9... So you get 27/9... Now if you add 27/9 + 28/9 (basically add the top numbers as denominators the same), you get 55/9..

    Use the calculator and u get 55/9.
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    (Original post by mariyahx)
    where did u get the 27/9 from
    By multiplying the top and bottom of the fraction 3/1 by 9... (3×9)/(1×9).. The reason you multiply it by 9 is because you want to get the denominators of the two fractions the same, so you can add them.

    This is a calculator question so just use a calc to avoid the trouble.
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    thanks makes sense now
    (Original post by gurpartapl)
    By multiplying the top and bottom of the fraction 3/1 by 9... (3×9)/(1×9).. The reason you multiply it by 9 is because you want to get the denominators of the two fractions the same, so you can add them.

    This is a calculator question so just use a calc to avoid the trouble.
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    (Original post by gurpartapl)
    Hi guys,
    created these questions myself and are very challenging. These types of questions are usually found at the end of the paper and require logical thinking and problem solving skills. The document i've attached contains 3 questions, ordered from easiest to hardest. Give them a go and tell me how you found those questions. If you become stuck simply notify me, and i can help you out. ~ Enjoy

    All these questions are not drawn to scale

    I have UPDATED the document with some changes to the final question as i noticed that some people might be prone to rounding errors... ( On the last question make sure you round your calculations in your working out to 3 sf, so that your final answer is unaffected)

    Detailed solutions added
    Thanks for the work of putting these questions together
    To be honest I thought these questions were a bit too elongated, and a bit too complicated than it would and normally is.

    But thanks still!
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    The answer for the first question needs to include x. The answer is y=-14/9x +55/9
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    My solution to the last Q was: 1. Sine rule with the figures already given to find angle BVC (74.6) which will also be VBP because alternate angles on parallel lines are equal (also angle BPV because isoscelese.)
    2. Take away angles 40 and 74.6 from triangle (180) to find angle BCV (65.4)
    3. Sine rule to get BV(5.7)
    4. Use CAH on triangle BZV and then double the answer to get 3.0.

    This is less monsterous and suits the number of marks awarded
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    Did 'em all
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    (Original post by Johnthetank)
    Did 'em all
    You truly are a genius kiddo
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    I'm appalled by Q2. The question makes no sense at all.If there's 9 blue sweets, the probability of taking 2 blues is 18/95 = 0.18947 approx.You have stated the probability is 0.2 which is clearly false.If you say the probability is 0.2 to 1sf, then number of blues could be 9 or 10.Should have just used a different value from 20 so you could use a nice exact probability.
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    I'm appalled by Q2. The question makes no sense at all.If there's 9 blue sweets, the probability of taking 2 blues is 18/95 = 0.18947 approx.You have stated the probability is 0.2 which is clearly false.If you say the probability is 0.2 to 1sf, then number of blues could be 9 or 10.Should have just used a different value from 20 so you could use a nice exact probability.
 
 
 
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