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# Edexcel (IAL) S1 June 15th 2016 Discussion watch

• View Poll Results: How was the IAL S1 Exam (THIS IS IAL NOT GCE)
Easy as pie.
2
6.90%
Was very good.
11
37.93%
Ok.
8
27.59%
It was hard.
7
24.14%
Failed.
1
3.45%

1. (Original post by MichealD)
i believe that your answer to q3 where they ask you for the p(t=3)=1/2 is incorrect , since the p of 3 alone is 1/2 and you can also obtain a total of three from (1,2) + (2,1) + (0,3)
noo i didnt solve it like that

p(t=3) = (4/16)/1/2= 1/2
2. my answer was 23/36 , what i did is the following
to obtain a total score of 3 or a three you have to add
p(3)+p(0,3)+p(1,2)+p(2,1)
3. (Original post by MichealD)
i believe that your answer to q3 where they ask you for the p(t=3)=1/2 is incorrect , since the p of 3 alone is 1/2 and you can also obtain a total of three from (1,2) + (2,1) + (0,3)
Ayyyyy, I was really confused by what their answer.
4. (Original post by MichealD)
my answer was 23/36 , what i did is the following
to obtain a total score of 3 or a three you have to add
p(3)+p(0,3)+p(1,2)+p(2,1)
I did the same
5. did you obtain the same answer ? and what was your answer for the given question?
6. (Original post by MichealD)
did you obtain the same answer ? and what was your answer for the given question?
I got the same asnwer too. Which given question?
7. the one under this question where they say what is the p(3 given rolled twice)
8. (Original post by MichealD)
i believe that your answer to q3 where they ask you for the p(t=3)=1/2 is incorrect , since the p of 3 alone is 1/2 and you can also obtain a total of three from (1,2) + (2,1) + (0,3)
9. (Original post by wenogk)
thats exactly what i did , what about the question below it , where they asked for the p(3 given rolled twice) i obtained 5/18
10. (Original post by MichealD)
did you obtain the same answer ? and what was your answer for the given question?
(Original post by Sunethra)
I got the same asnwer too. Which given question?
11. (Original post by wenogk)
Yes i did it like that except for part 3 i beleive it was my mistake
12. There was a question 2 i believe there was a coding where v=(t-5)/10

in the last part he asked for the estimation for mean and standard deviation
i made t the subject correct me if i am wrong
13. (Original post by Tigernoob)
There was a question 2 i believe there was a coding where v=(t-5)/10

in the last part he asked for the estimation for mean and standard deviation
i made t the subject correct me if i am wrong
For the mean yeah just make t the subject but for standard deviation only multiply by 10
14. (Original post by Tigernoob)
There was a question 2 i believe there was a coding where v=(t-5)/10

in the last part he asked for the estimation for mean and standard deviation
i made t the subject correct me if i am wrong
For mean this is correct but for sd just multiply v by 10 because adding something in coding doesnt affect sd
15. (Original post by Tigernoob)
Yes i did it like that except for part 3 i beleive it was my mistake
Lol my wholw question is wrong
So lost 8 here and 5 in venn diagram
****
16. (Original post by wenogk)
For the mean yeah just make t the subject but for standard deviation only multiply by 10
what i did is i made t the subject so its like 10v+5 is = t

then said E(t)=10XE(v)+5

for standard deviation i did
Var(t)= 10^2 x Var(v)

i converted the s.d i got on the upper part to the variant and mulitplied with the 10^2

i hope what i did correct xD
17. (Original post by ToxicPhantom007)
Lol my wholw question is wrong
So lost 8 here and 5 in venn diagram
****
part 3 wasn't for 8 marks ?
18. What was the skewness?
19. Ahhh... Finally exams over for me.Paper was easy.I did lose marks in q2.but I'll get atleast 1 mark in that.
And for r and q both were positive right? I don't remember my probability questions :P and you were supposed to the 'show that B=3/8' using simultaneous eq.s
20. (Original post by Tigernoob)
what i did is i made t the subject so its like 10v+5 is = t

then said E(t)=10XE(v)+5

for standard deviation i did
Var(t)= 10^2 x Var(v)

i converted the s.d i got on the upper part to the variant and mulitplied with the 10^2

i hope what i did correct xD
I don't understand, how did you get Variance wasn't it just standard deviation

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