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OCR MEI DE June 17 2016 watch

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    (Original post by Geo_)
    Yeah that's precisely what I did. Ok that's alright then, I can definitely cope with 1 mark lost.
    Although, because it asked for the time difference between the 1st and 2nd times they are equal, surely that will be the difference between when t=pi/6 and t=3pi/2 ? As 5pi/6 would be the third time they are equal to each other




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    5pi/6 is smaller than 3pi/2 so would occur first but its only one mark so no major issueee
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    (Original post by username98)
    5pi/6 is smaller than 3pi/2 so would occur first but its only one mark so no major issueee
    Haha yeah of course sorry! Apparently my brain doesn't work on a Saturday...


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    Does anyone have a copy of the question paper?
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    (Original post by Geo_)
    Yeah that's precisely what I did. Ok that's alright then, I can definitely cope with 1 mark lost.
    Although, because it asked for the time difference between the 1st and 2nd times they are equal, surely that will be the difference between when t=pi/6 and t=3pi/2 ?




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    t= 1.5pi isn't a root of that equation.
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    The answer to the last part was \dfrac{2}{3} \pi, because it was the difference between \dfrac{\pi}{6} and \dfrac{5}{6} \pi - there was a root at \dfrac{3}{2} \pi, but it wanted the time difference between the first two occurrences, which are both when sint = \dfrac{1}{2}, as you can tell by drawing a sine graph.
 
 
 
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