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    (Original post by Ali2001)
    Hi
    Can I know how hard people found todays paper please. I think I got 58/70. I just want to see if it was just me struggling more than the past papers or everyone else as well. Thanks
    58/70 would have been an A*^ with last years boundaries.

    Personally, I thought it was pretty good.
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    (Original post by theholychilli)
    Yeah I think you're right. I was going off what someone got for their answer, which was 45. Now I've remembered I got 65.
    I initially got 65, but went back and realised you had to add the LHS to get x root'5' then make the RHS match, so it was 45, which I got in the end. I believe you must have taken away the root'80' and squared everything - which doesn't work unfortunately.
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    (Original post by economy)
    I initially got 65, but went back and realised you had to add the LHS to get x root'5' then make the RHS match, so it was 45, which I got in the end. I believe you must have taken away the root'80' and squared everything - which doesn't work unfortunately.
    Yep, that's what I did. Ah well, hopefully method marks will be on my side. Plus, got most of the other questions right anyway.
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    (Original post by Ali2001)
    Hi
    Can I know how hard people found todays paper please. I think I got 58/70. I just want to see if it was just me struggling more than the past papers or everyone else as well. Thanks
    I personally found it easy but i think most people have mixed reactions
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    (Original post by LokiiR)
    I got
    1) 3x^2-20x
    2) a=3 b=-20
    3)n=12 b) 3/5
    4)(-5, 8) b)root 10
    5) x=39 degrees
    6)m=8 p= -1
    7) 9, 10, 11
    8) x=121
    9) x^3-15x^2+75x-125
    10) -80
    11) Gradient AB = -5/2, Gradient BC= 2/5
    12) h=3 k=-7
    13) x=45
    14) 3a=3 a=1 b)(x+2)(x-7)(x-3)
    15) 2root 7 -4
    16) I got 5/6 but answer was -5/6 because it was obtuse
    17) k = 9
    18) (x^2+9)(x-3)(x+3)
    19) 3 + 3 + 3 + 3root 3 is what you get for totals and factorise it to 3 (3+root 3)
    20) w = 3n because y use cosine rule and the answer = 1/3 rearrange it and then factorise it into two solutions but answer cant be negative so its n=w/3 and w=3n so two lengthsare equal and u get isosceles
    Can anyone remember what question 15 was? I think thats the only one which my results did not corroborate with. Great job btw LokiiR
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    (Original post by economy)
    Surds, where it was surd + surd = surd + root'x'
    √125 + √20 = √x + √80
    5√5 + 2√5 = √x + 4√5
    5√5 + 2√5 - 4√5= √x
    3√5 = √x
    √45 = √x
    x = 45

    QED
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    (Original post by economy)
    I initially got 65, but went back and realised you had to add the LHS to get x root'5' then make the RHS match, so it was 45, which I got in the end. I believe you must have taken away the root'80' and squared everything - which doesn't work unfortunately.
    What was the final answer?


    Posted from TSR Mobile
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    (Original post by rekt99)
    Pretty sure the answer to question ten is 80 not -80!
    its -80 because y was <0 so it was -1/5 not 1/5

    (Original post by Jesse2106)
    Do you know the marks for each question?
    I know it for some of them, hang on:
    1) 3x^2-20x (2)
    2) a=3 b=-20 (3)
    3)n=12 (2) b) 3/5 (1)
    4)(-5, 8) b)root 10
    5) x=39 degrees
    6)m=8 p= -1
    7) 9, 10, 11
    8) x=121
    9) x^3-15x^2+75x-125
    10) -80
    11) Gradient AB = -5/2, Gradient BC= 2/5 (3)
    12) h=3 k=-7 b) (-3, -7) (1) c) -3+ or - root 7 (1)
    13) x=45
    14) 3a=3 a=1 (2?) b)(x+2)(x-7)(x-3)
    15) 2root 7 -4
    16) I got 5/6 but answer was -5/6 because it was obtuse (3)
    17) k = 9 (5)
    18) (x^2+9)(x-3)(x+3)
    19)prove that the first part = 3, do it by doing sin45 = 1/root2, and 1/root2=x/3root2. Rearrange for 3. b)3 + 3 + 3 + 3root 3 is what you get for totals and factorise it to 3 (3+root 3) (4)
    20) w = 3n because y use cosine rule and the answer = 1/3 rearrange it and then factorise it into two solutions but answer cant be negative so its n=w/3 and w=3n so two lengthsare equal and u get isosceles (4)
    thats all I can remember...some may not be right, ALSO added answers

    (Original post by A-22)
    Can anyone remember what question 15 was? I think thats the only one which my results did not corroborate with. Great job btw LokiiR
    Question 15 was I believe rationalising the denominator of a surd. You get to 6root7-12/3 and cancel it down to 2root7 - 4
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    (Original post by gibsond9)
    What was the final answer?


    Posted from TSR Mobile
    x = 45

    There's a complete mark scheme for anyone who wants it:
    http://www.thestudentroom.co.uk/show...6#post65956266
 
 
 
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