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# Edexcel C3 June 2016 - Unofficial Mark Scheme watch

1. [QUOTE=veldt127;65974317
ii ln(2.5)

wasn't 4ii 0.5ln(2.5)

because 2x= ln(2.5)
so x= 0.5ln(2.5)
2. For 8b how many marks will I lose if I left the answers in degrees and not radians
3. (Original post by mk_98)
It was - 4x^2+20 wasn't it? Otherwise how would you get the range of values for the second part?
https://www.wolframalpha.com/input/?...x%5E2%2B5)%5E2

The answer in the original post is correct. It can't be simplified any further.
4. How much was question 2b worth
5. And what was question 5i ?

Also anyone remembers how many marks
5i, 5ii is worth?
ii ln(2.5)

wasn't 4ii 0.5ln(2.5)

because 2x= ln(2.5)
so x= 0.5ln(2.5)
4e^2x - 25 = 0
e^2x = 25/4
e^x = 5/2
x = ln(5/2)
7. What was question 3b and 3a? the questions not answers
8. Does anyone remember how many marks the last question was? I was SO STUPID. I left it out (( looks like someones not going to uni...
9. For 3(c), I don't understand why the lowest value of theta wasn't just 33 from part b?

anyone help?
10. how much do i have to pay if i want to retake c3 next year ?
11. (Original post by particlestudent)
Im sure only the middle two values were allowed for 8B
No, the interval was -pi<x<pi
12. (Original post by theereflex)
For 3(c), I don't understand why the lowest value of theta wasn't just 33 from part b?

anyone help?
In part b you solved for when sin theta was negative, in part c however sin theta was positive
13. (Original post by theereflex)
For 3(c), I don't understand why the lowest value of theta wasn't just 33 from part b?

anyone help?
I asked someone about this, apparently the equation showed on part C was not the same equation as part a, there was a negative sign added somewhere so you had to equate it again and get a different value for the angle.

Hope this helped
14. (Original post by jovdawesome)
how much do i have to pay if i want to retake c3 next year ?
its around £34 for 1 retake as you have to take it outside school so the school doesn't subsidise.
15. Really? That's what I was expecting so I checked the equations over and over, ... and I still missed it, wow

thanks
16. (Original post by DomWoodcock)
Yeah I think I remember the limits between -pi/2 and pi/2
i recall that also so i only had two angles
17. anyone remember what question 6 was?
18. (Original post by Dieselblue)
For 5i what did people do with the sin and cos?

Also part 2a is wrong, -4x^2-20=-4(x^2+5) so -4/x^2+5
I believe you're wrong. It was -4x^2 + 20, not -20. Therefore the answer stated by this post is correct.
19. (Original post by Mattematics)
4e^2x - 25 = 0
e^2x = 25/4
e^x = 5/2
x = ln(5/2)
I did 4e^2x =25
e^2x=25/4
2x=ln(25/4)
x=0.5ln(25/4)

But didn't simplify ant further would this be alright??
20. (Original post by marethyu)
a 2
b 2
c 4
8 in total
Totally saying goodbye to any chances of an A ......

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