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    [QUOTE=veldt127;65974317
    ii ln(2.5)


    wasn't 4ii 0.5ln(2.5)

    because 2x= ln(2.5)
    so x= 0.5ln(2.5)
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    For 8b how many marks will I lose if I left the answers in degrees and not radians
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    (Original post by mk_98)
    It was - 4x^2+20 wasn't it? Otherwise how would you get the range of values for the second part?
    https://www.wolframalpha.com/input/?...x%5E2%2B5)%5E2

    The answer in the original post is correct. It can't be simplified any further.
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    How much was question 2b worth
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    And what was question 5i ?

    Also anyone remembers how many marks
    5i, 5ii is worth?
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    (Original post by cookie_raider01)
    ii ln(2.5)


    wasn't 4ii 0.5ln(2.5)

    because 2x= ln(2.5)
    so x= 0.5ln(2.5)
    4e^2x - 25 = 0
    e^2x = 25/4
    e^x = 5/2
    x = ln(5/2)
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    What was question 3b and 3a? the questions not answers
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    Does anyone remember how many marks the last question was? I was SO STUPID. I left it out (( looks like someones not going to uni...
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    For 3(c), I don't understand why the lowest value of theta wasn't just 33 from part b?

    anyone help?
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    how much do i have to pay if i want to retake c3 next year ?
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    (Original post by particlestudent)
    Im sure only the middle two values were allowed for 8B
    No, the interval was -pi<x<pi
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    (Original post by theereflex)
    For 3(c), I don't understand why the lowest value of theta wasn't just 33 from part b?

    anyone help?
    In part b you solved for when sin theta was negative, in part c however sin theta was positive
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    (Original post by theereflex)
    For 3(c), I don't understand why the lowest value of theta wasn't just 33 from part b?

    anyone help?
    I asked someone about this, apparently the equation showed on part C was not the same equation as part a, there was a negative sign added somewhere so you had to equate it again and get a different value for the angle.

    Hope this helped
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    (Original post by jovdawesome)
    how much do i have to pay if i want to retake c3 next year ?
    its around £34 for 1 retake as you have to take it outside school so the school doesn't subsidise.
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    Really? That's what I was expecting so I checked the equations over and over, ... and I still missed it, wow

    thanks
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    (Original post by DomWoodcock)
    Yeah I think I remember the limits between -pi/2 and pi/2
    i recall that also so i only had two angles
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    anyone remember what question 6 was?
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    (Original post by Dieselblue)
    For 5i what did people do with the sin and cos?

    Also part 2a is wrong, -4x^2-20=-4(x^2+5) so -4/x^2+5
    I believe you're wrong. It was -4x^2 + 20, not -20. Therefore the answer stated by this post is correct.
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    (Original post by Mattematics)
    4e^2x - 25 = 0
    e^2x = 25/4
    e^x = 5/2
    x = ln(5/2)
    I did 4e^2x =25
    e^2x=25/4
    2x=ln(25/4)
    x=0.5ln(25/4)

    But didn't simplify ant further would this be alright??
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    (Original post by marethyu)
    a 2
    b 2
    c 4
    8 in total
    Totally saying goodbye to any chances of an A ......
 
 
 
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