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    (Original post by RDKGames)
    That's because the equation is wrong. It's not linear. I think you meant \frac{2}{7}=\frac{3x}{2x-5} otherwise \frac{3x}{2x} \rightarrow \frac{3}{2} as the x's cancel out.
    I wanted to write it as a fraction but had no clue how to. I have an assumption about what you did with the x, but at the same isn't it needed to find out what x is?

    Sorry for my ignorance. If there's a topic I should read up on to understand it better just mention it.
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    (Original post by Chrollo-Lucilfer)
    I wanted to write it as a fraction but had no clue how to. I have an assumption about what you did with the x, but at the same isn't it needed to find out what x is?

    Sorry for my ignorance. If there's a topic I should read up on to understand it better just mention it.
    I didn't do ANYTHING with the x. I simply pointed out you've written the equation wrong. If you want to solve for x, then take \frac{2}{7}=\frac{3x}{2x-5} and multiply both sides by 7(2x-5) and tidy it up to solve for x.
    Yeah you should read up on how to manipulate fractions more efficiently.
 
 
 
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