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    (Original post by RDKGames)
    Huh? Mate you need to check your maths: (a+b)^2=a^2+b^2 so a+b=\sqrt{a^2+b^2}=a+b
    I thought it was right.
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    (Original post by physicsmaths)
    Long time no see


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    Indeed. Excited for results day?


    (Original post by gdunne42)
    That's wrong (6x+3)^2 = (6x+3)(6x+3), expand the brackets


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    I'd stop wasting energy - this thread is not to be taken seriously, it seems 🙄
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    (Original post by RDKGames)
    Huh? Mate you need to check your maths: (a+b)^2=a^2+b^2 so a+b=\sqrt{a^2+b^2}=a+b
    No I don't mate, you do.


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    (Original post by gdunne42)
    That's wrong (6x+3)^2 = (6x+3)(6x+3), expand the brackets


    Posted from TSR Mobile
    Yeah you're right there. Damn my maths is rusty lol
    In that case, the answer should be:

    x = (-12+sqrt(87612))/74 or
    = (-12-sqrt(87612))/74
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    Hi,

    As said above the square root of y² +x² is not y + x.
    You can either use quadratic formula as some others have stated or take out a factor of 'a' and be left with a quadratic without the number in front of the x² term.

    Hope that helps a bit
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    (Original post by gdunne42)
    No I don't mate, you do.


    Posted from TSR Mobile
    You must've been taught wrong. It's all common sense (a+b)^2 means you square the a and then add on the square of b. Go back to textbooks, gg.
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    (Original post by SeanFM)
    Indeed. Excited for results day?




    I'd stop wasting energy - this thread is not to be taken seriously, it seems 🙄
    Excited :/ lol.
    Probably gna be in clearing with like 3A*s and 111 in step I-III minimum 😂.
    But seriosuly yeh i know i have minimum 1,1,1 in step and i dnt even know about AFM since i flopped modules like D1 D2 and S4 like got U in D1 😂(what did i expect not touching the module at all ) so i either get A* or a B since M3/4 r probably 100ums and M5 well made a mistake on a 10 marker so yh :/.
    So hopefully cam still accept me if i did flop a levels like I feared I would.



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    (Original post by RDKGames)
    You must've been taught wrong. It's all common sense (a+b)^2 means you square the a and then add on the square of b. Go back to textbooks, gg.
    Not wasting any more time on this troll thread


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    (Original post by gdunne42)
    You trolling or you want me to find you a text book example?


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    ...

    What do you think?
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    (Original post by RDKGames)
    ...

    What do you think?
    Nothing worse that bored maths students waiting for exam results.


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    (Original post by gdunne42)
    The square root of x^2 + y^2 is not x + y

    Try it, 64 + 36 = 100 the square root is 10. It is not 8 + 6


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    I'm aware but the OP is just messing around.
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    (Original post by gdunne42)
    Not wasting any more time on this troll thread


    Posted from TSR Mobile
    Sincerly sorry for this thread.
    Especially for wasting your time when you geniunely want to help.
    I got nothing better to do since I don't want to learn Analysis.


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    (Original post by gdunne42)
    Not wasting any more time on this troll thread


    Posted from TSR Mobile
    To be fair, (a+b)^2 = a^2 + b^2 in a field of characteristic 2.
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    The problem is simple, intersections of a line and circle, just big numbers. Substitute x^2 + (6x +3)^2 = 600, x^2 + 36x^2 + 36x +9 = 600, 37x^2 + 36x - 591 = 0. Now solve with the quadratic formula, x = (-36 +- sqrt ( 1296 + 4 * 37 * 591))/ 2 * 37 = (-36 +- 297.93) / 74, x = -4.51, 3.54. Now substitute in y = 6x + 3. (-4.51, -24.06), (3,54, 24.24) are the approximate intersection points.

    Use standard substitution method. Do not be intimidated by big numbers.
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    (Original post by mathplustutornj)
    The problem is simple, intersections of a line and circle, just big numbers. Substitute x^2 + (6x +3)^2 = 600, x^2 + 36x^2 + 36x +9 = 600, 37x^2 + 36x - 591 = 0. Now solve with the quadratic formula, x = (-36 +- sqrt ( 1296 + 4 * 37 * 591))/ 2 * 37 = (-36 +- 297.93) / 74, x = -4.51, 3.54. Now substitute in y = 6x + 3. (-4.51, -24.06), (3,54, 24.24) are the approximate intersection points.

    Use standard substitution method. Do not be intimidated by big numbers.
    Did you even read any of the comments on this thread? :facepalm:
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    You're all wrong!

    (a+b)^2 = a^2 + 2ab + b^2
    = 2 + a^2 + a + b^2 + b
    = 2 + a^3 + b^3
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    (Original post by RDKGames)
    Did you even read any of the comments on this thread? :facepalm:
    Is my solution wrong? This is a simple problem of the intersection of a circle and a line. I see some people were discussing a solution along the lines I mentioned. If you had y = x +1 and x^2 + y^2 =9, you would solve it the same way. In the problem given, the numbers are bigger, but it is a simple problem.
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    (Original post by mathplustutornj)
    Is my solution wrong? This is a simple problem of the intersection of a circle and a line. I see some people were discussing a solution along the lines I mentioned. If you had y = x +1 and x^2 + y^2 =9, you would solve it the same way. In the problem given, the numbers are bigger, but it is a simple problem.
    No, your solution and method are fine. The OP was joking with the question, he didn't need help with it.
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    (Original post by RDKGames)
    No, your solution and method are fine. The OP was joking with the question, he didn't need help with it.
    Yeh i did actually. I was proper stuck


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    Are you okay?
 
 
 
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